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AP ICET 2025 Analytical Ability Section Sample Questions: With the AP ICET 2025 examination scheduled to be conducted on May 7th, 2025, the candidates are expected to brush through the various concepts of the AP ICET examination in these few months leading up to the exam date. Section A of the AP ICET question paper is the analytical ability section. The analytical ability section is one of the most important sections of the AP ICET exam due to the weightage it holds. 75 out of 200 questions will be asked from this section alone in the AP ICET 2025 examination. Therefore, practising the AP ICET 2025 analytical ability sample questions is necessary for the candidates to gain much-needed practice for solving the different types of questions. This article contains a collection of AP ICET analytical ability model questions, which also includes the questions from the AP ICET previous year’s question papers.
As per the latest updates from the Andhra Pradesh State Council of Higher Education (APSCHE), who is responsible for conducting the AP ICET 2025 examination, there is no change in the AP ICET 2025 exam pattern. There are also no changes prescribed in the AP ICET 2025 syllabus. Hence, the candidates can also expect a similar trend in the question paper design and overall exam trends as well. The official AP ICET 2025 exam pattern 2025 is given below.
Details | Number of Questions | AP ICET Total Questions |
Section A – Analytical Ability | 75 | |
1. Data Sufficiency | 20 | |
2. Problem-Solving | 55 | |
Section B – Communication Ability | 70 | |
1. Vocabulary | 15 | |
2. Functional Grammar | 20 | |
3. Business and Computer Terminology | 15 | |
4. Reading Comprehension | 20 | |
Section C – Mathematical Ability | ||
1. Arithmetical Ability | 35 | 55 |
2. Algebraical and Geometrical Ability | 10 | |
3. Statistical Ability | 10 | |
AP ICET Marks Weightage | 200 Marks | 200 |
More than one-third of the AP ICET 2025 question paper is comprised of the analytical ability section. Precisely, 37.5% is the weightage held by the analytical ability section in the AP ICET 2025 question paper. This makes it necessary to practice using the AP ICET analytical ability sample questions. The analytical ability section of the AP ICET 2025 exam is divided into two sections, Data Sufficiency and Problem-Solving. The overall question distribution of the analytical ability of the AP ICET 2025 exam is given below:
Section A – Analytical Ability | |
1. Data Sufficiency | 20 |
2. Problem-Solving | 55 |
The data sufficiency section of the AP ICET 2025 analytical ability section consists of 20 questions. They will be the first 20 questions appearing in the question paper. In this section, the candidates will be given two statements, and by going through it, they must identify if both the statements, either the first or the second statement alone, can bring a conclusion. In case both the statements together cannot answer the question, they must choose the last option, neither. Given below are a few AP ICET data sufficiency sample questions for the candidate’s practice.
In the questions below, a question is followed by data in the form of two statements labelled as I and II. You have to decide whether the data given in the statement is sufficient to answer the questions. Using the data, make an appropriate choice from (1) to (4) as per the following guidelines:
a) Mark choice (1) if the statement I alone is sufficient to answer the question.
b) Mark choice (2) if the statement II alone is sufficient to answer the question.
c) Mark choice (3) if the statements I and II together are sufficient to answer the question but neither statement alone is sufficient.
d) Mark choice (4) if the statements I and II together are not sufficient to answer the question and additional data is required.
Question:
What is the cost of each pen?
Statements:
I. Cost of 3 pens and 4 pencils is Rs. 10
II. Cost of 12 pencils and 9 pens is Rs. 30
Options:
1
2
3
4
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Correct Option: 4
Explanation:
Both statements provide some information about the costs of pens and pencils, but none of them alone is sufficient to calculate the cost of a single pen. We would need to solve a system of equations using the data from both statements to determine the cost of each pen. Therefore, the correct answer is "4," which indicates that additional data is required.
Question:
For the positive integer n, is n - 10 odd?
Statements:
I. n - 16 is a positive integer
II. n + 12 is even
Options:
1
2
3
4
Correct Option: 2
Explanation:
From Statement II, we know that n + 12 is even. This implies that n must be even (because adding an even number to an even number gives an even number). Since n is even, n - 10 will be even, not odd. Hence, Statement II alone is sufficient to answer the question.
Question:
Four friends, A, B, C, and D got the top four ranks in a test but did not get the first. B did not get the second, C did not get the third, and D did not get the fourth. Who secured which rank?
Statements:
I. Neither A nor D were among the first 2 ranks
II. Neither B nor C was third or fourth
Options:
1
2
3
4
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Correct Option: 3
Explanation:
Using both statements, we can deduce the ranking:
From Statement I: A and D are excluded from the top two ranks.
From Statement II: B and C cannot be 3rd or 4th.
Therefore, A must be 1st, B must be 2nd, C must be 3rd, and D must be 4th.
Thus, Statement I and II together are sufficient to answer the question, but neither statement alone is enough.
Question:
What is the value of x in the equation 2x + 5 = 11?
Statements:
I. x = 3
II. x is a prime number
Options:
1
2
3
4
Correct Option: 1
Explanation:
Statement I directly gives the value of x as 3. Hence, Statement I alone is sufficient to answer the question. Therefore, the correct answer is "1."
Question:
What is the cost of the book?
Statements:
I. A man earns a profit of 25% on selling a book
II. The selling price of the book is Rs. 5000
Options:
1
2
3
4
Correct Option: 3
Explanation:
From Statement II, the selling price is given as Rs. 5000. From Statement I, a 25% profit is made on selling the book. To find the cost price, we can use the formula:
Cost Price = Selling Price / (1 + Profit Percentage)
Cost Price = 5000 / (1 + 0.25)
Cost Price = 5000 / 1.25 = Rs. 4000
Thus, both statements together are sufficient to answer the question. Hence, the correct answer is "3."
Question:
How many students scored more than the average marks of the class in a test?
Statements:
I. The average marks of the class was 70
II. 10 students scored above the arithmetic mean of the class
Options:
1
2
3
4
Correct Option: 2
Explanation:
Statement I gives us the average marks (70), but without knowing the total number of students, we cannot directly determine how many scored above the average. Statement II informs us that 10 students scored above the arithmetic mean. Hence, Statement II is sufficient to answer the question. Therefore, the correct answer is "2."
Question:
What is the total distance travelled by a train?
Statements:
I. The train travelled at an average speed of 80 km/h for 4 hours.
II. The train travelled at an average speed of 100 km/h for 2 hours.
Options:
1
2
3
4
Correct Option: 4
Explanation:
To calculate the total distance, we can use the formula:
Distance = Speed × Time
From Statement I: Distance = 80 km/h × 4 hours = 320 km
From Statement II: Distance = 100 km/h × 2 hours = 200 km
Adding the distances from both statements, the total distance is 320 km + 200 km = 520 km. Therefore, both statements together are sufficient to answer the question. Hence, the correct answer is "4."
Question:
How many persons attended the meeting?
Statements:
I. Each registered person can take two persons with him/her.
II. There were totally 180 registrations for the meeting.
Options:
1
2
3
4
Correct Option:
4. 4
Explanation:
From Statement II, there were 180 registrations for the meeting. From Statement I, each registered person can bring 2 additional persons. Therefore, the total number of people who attended the meeting is:
Total attendees = 180 (registrants) × 3 (including each person with 2 others) = 540.
Hence, both statements together are sufficient to answer the question. Therefore, the correct answer is "4."
The key to solving the data sufficiency questions in the AP ICET 2025 examination is by clearly understanding the question and statements. The candidates might carefully analyse the statements as well as the questions, or they might get confused easily while attending the questions. Some of the effective AP ICET preparation strategies for the data sufficiency problems are:
The candidate should avoid unnecessary calculations. The goal of the candidate is to find if the statements are sufficient to solve the problem; they need not find the answer to the question. Trying to do so may result in confusion and wrong responses.
Questions from both logical reasoning as well as quantitative ability are asked in the data sufficiency section of the analytical ability. Hence, the candidates should solve multiple AP ICET sample questions from these topics as well.
The candidates should also read both the statements carefully. Just going through one statement and immediately jumping to a conclusion can be fatal.
The candidates should avoid making assumptions. They must stick strictly to the information provided in the statements.
To have more idea of the type of questions asked under the analytical ability section and the difficulty level of the questions, the candidates should refer to the previous year's question papers of the AP ICET examination.
The problem-solving sub-section of the analytical ability section is essentially the logical reasoning section of the AP ICET 2025 examination. This section includes topics such as finding the missing numbers, coding decoding, completing the series, clocks, analogy, seating arrangements, calendars, puzzles and a few simple mathematical problems. The candidates can also expect around 10 questions from the data interpretation topic as well. 55 out of 75 questions of the analytical ability section of the AP ICET examination is asked from this section alone, making it necessary for the candidates to practice a lot of AP ICET analytical ability sample questions. The candidates can refer to the various AP ICET analytical ability sample questions given below.
Question:
Find the odd thing from the following.
Options:
Cricket
Chess
Hockey
Football
Correct Option:
2. Chess
Explanation:
All options except "Chess" refer to team sports that require physical activity, while chess is an indoor board game that doesn't involve physical activity like the others. Therefore, "Chess" is the odd one out.
Question:
Find the odd thing from the following.
Options:
121
144
169
226
Correct Option:
4. 226
Explanation:
121, 144, and 169 are all perfect squares (112, 122, and 132 respectively), while 226 is not a perfect square. Therefore, 226 is the odd one out.
Question:
Find the odd thing from the following.
Options:
Nephrology
Astrology
Pathology
Mycology
Correct Option:
2. Astrology
Explanation:
Nephrology, Pathology, and Mycology are scientific fields related to the study of diseases and organisms, while Astrology is a belief system related to the positions of celestial bodies and their influence on human affairs. Therefore, "Astrology" is the odd one out.
Question:
Find the Missing Number
Options:
16
18
17
19
Correct Option:
2. 18
Explanation:
The given sequence is: 0.5, 2, 4.5, 8, 12.5.
The pattern appears to increase by successive intervals:
0.5 + 1.5 = 2,
2 + 2.5 = 4.5,
4.5 + 3.5 = 8,
8 + 4.5 = 12.5.
Thus, the next term will be:
12.5 + 5.5 = 18.
Hence, the missing number is 18.
Question:
Find the Missing Number
1, 4, 27, 256, 3125, ________.
Options:
7776
56646
46656
1296
Correct Option:
3. 46656
Explanation:
The given sequence is: 1, 4, 27, 256, 3125.
These numbers follow a pattern of increasing powers:
1 = 1¹
4 = 2²
27 = 3³
256 = 4⁴
3125 = 5⁵
The next term in the pattern will be 6⁶ = 46656.
Hence, the missing number is 46656.
Question:
Find the Missing Letters
CMM, EOO, GQQ, ________, KUU
Options:
GRR
GSS
ISS
ITT
Correct Option:
3. ISS
Explanation:
The pattern follows a sequence where the first letter increases by 2 steps each time: C (3), E (5), G (7), I (9), K (11).
The second letter increases by 2 steps: M (13), O (15), Q (17), S (19), U (21).
The third letter increases by 1 step: M (13), O (15), Q (17), S (19), U (21).
Thus, the missing term in the sequence is "ISS".
Question:
If 'NOVEMBER' is coded as 'PQXGODGT', how would 'MARCH' be coded?
Options:
OCTEJ
OCTEI
OCSET
OCTFJ
Correct Option:
OCTEJ
Explanation:
Each letter in the word is shifted forward by 2 positions in the alphabet:
N → P, O → Q, V → X, E → G, M → O, B → D, E → G, R → T.
Applying the same pattern to MARCH:
M → O, A → C, R → T, C → E, H → J.
Hence, MARCH is coded as OCTEJ.
Question:
BGH : FKL :: ______
Options:
GJO
HJN
HJO
GIN
Correct Option:
3. HJO
Explanation:
The pattern involves increasing the letters by a fixed number:
B → F (+4)
G → K (+4)
H → L (+4)
So, for the next sequence:
D → H (+4)
F → J (+4)
K → O (+4)
Hence, the missing code is HJO.
Question:
BEHK : 25811 :: ADGJ : ______
Options:
13810
14810
14710
12710
Correct Option:
3. 14710
Explanation:
The pattern involves the following:
The first letter of BEHK (B) corresponds to 2, the second letter (E) corresponds to 5, the third (H) corresponds to 8, and the fourth (K) corresponds to 11.
Similarly, for ADGJ:
A corresponds to 1, D corresponds to 4, G corresponds to 7, and J corresponds to 10.
Thus, ADGJ corresponds to 14710, following the same sequence pattern.
Question:
Six friends A, B, C, D, E, and F are sitting around a round table facing the centre of the table. B is between A and C, D is between A and E, and F is between C and E. Who is sitting to the right of C?
Options:
E
D
B
F
Correct Option:
4. F
Explanation:
From the given information:
B is between A and C.
D is between A and E.
F is between C and E.
Based on the arrangement, if we position A, B, C, D, E, and F around the table, we can determine that F is sitting to the right of C. Hence, the correct answer is "F".
Question:
The last day of a century CANNOT be ______ weekday?
Options:
Monday
Tuesday
Wednesday
Friday
Correct Option:
2. Tuesday
Explanation:
After considering the leap years and the days added over the centuries, we know from extensive calendar calculations that the last day of a century cannot be a Tuesday due to the pattern created by the leap years and century transitions.
Question:
The table represents the number of athletes who participated from various countries during the years 2014 to 2019. Answer the questions using these details.
Countries → | A | B | C | D | E |
Years ↓ | M | F | M | F | M |
2014 | 4.3 | 3.6 | 5.8 | 6.3 | 6.7 |
2015 | 6.6 | 4.2 | 8.4 | 6.2 | 6.9 |
2016 | 9.6 | 4.9 | 8.7 | 7.4 | 4.8 |
2017 | 11.8 | 5.9 | 9.2 | 7.3 | 7.3 |
2018 | 11.8 | 5.8 | 9.5 | 5.9 | 10.2 |
2019 | 8.2 | 5.2 | 6.4 | 7.4 | 10.8 |
Question:
In which of the following years was the total number of participants (athletes) from Country C the second highest?
Options:
2019
2018
2017
2015
Correct Option:
2. 2018
Explanation:
To find the second highest total number of participants for Country C, we need to calculate the total number of participants for each year:
2014: 5.8 (M) + 6.3 (F) = 12.1
2015: 8.4 (M) + 6.2 (F) = 14.6
2016: 8.7 (M) + 7.4 (F) = 16.1
2017: 9.2 (M) + 7.3 (F) = 16.5
2018: 9.5 (M) + 5.9 (F) = 15.4
2019: 6.4 (M) + 7.4 (F) = 13.8
From the above totals, the second highest total is 15.4 in 2018.
Hence, the correct answer is 2018.
Question:
The number of female athletes who participated from Country E in the year 2018 was approximately what percentage of the total number of athletes who participated from Country B in the year 2017?
Options:
40%
46%
50%
56%
Correct Option:
2. 46%
Explanation:
From the table:
Female athletes from Country E in 2018: 5.8
Total athletes from Country B in 2017 (sum of male and female athletes):
Male (B): 5.9
Female (B): 5.8
Total = 5.9 + 5.8 = 11.7
Now, calculate the percentage:
Percentage = (5.8 / 11.7) × 100 ≈ 46%
Hence, the correct answer is 46%.
Question:
A bus takes 3 hours and 30 minutes to cover a distance of 280 km. To make this journey in 4 hours, by how much should the speed of the bus be decreased?
Options:
12 kmph
8 kmph
10 kmph
15 kmph
Correct Option:
3. 10 kmph
Explanation:
First, calculate the speed of the bus when it takes 3 hours and 30 minutes to cover 280 km.
Time = 3 hours 30 minutes = 3.5 hours
Speed = Distance / Time = 280 km / 3.5 hours = 80 km/h
Now, to make the journey in 4 hours:
Required speed = Distance / Time = 280 km / 4 hours = 70 km/h
The decrease in speed = 80 km/h - 70 km/h = 10 km/h
Hence, the speed of the bus should be decreased by 10 km/h. Therefore, the correct answer is 10 km/h.
Question:
What is the angle between the minute hand and hour hand at 5:55?
Options:
155°
152.5°
180.5°
185.5°
Correct Option:
2. 152.5°
Explanation:
To calculate the angle between the minute hand and hour hand, use the formula:
Angle = |(30 × H) - (5.5 × M)|
Where:
H = Hour
M = Minute
At 5:55:
H = 5
M = 55
Using the formula:
Angle = |(30 × 5) - (5.5 × 55)|
Angle = |150 - 302.5|
Angle = | -152.5 | = 152.5°
Hence, the angle between the minute hand and the hour hand at 5:55 is 152.5°.
The candidates should always prioritise learning the analytical ability section of the AP ICET exam’s problem-solving section due to its high weightage. While analysing the previous year's question papers in the analytical ability section, it can be understood that a lot of questions have easy to moderate difficulty. The questions asked from the topics such as series completion, coding and decoding, analogy and odd one out were easy and straightforward. Hence, along with practicing for the exam using the AP ICET analytical ability model questions, the candidates should also follow the given below preparation tips.
Understanding the basics is the preliminary step for mastering any concepts of the examination. The candidates should be thorough with series completion, coding-decoding, analogy, and odd one out, as these often appear with easy to moderate difficulty.
The candidates should also solve a variety of questions daily to build speed and accuracy. Use AP ICET model questions and AP ICET sample papers for enhanced AP ICET 2025 practice.
For series and coding questions, the candidates should focus on identifying patterns or logic behind the sequences early. This will help them solve the problems early and enhance their AP ICET 2025 scores.
The candidates should focus on solving a lot of questions related to the logical reasoning section. They should note down the important topics and the questions that they have answered incorrectly. They must review the questions and understand the logic to avoid similar errors on the AP ICET exam day.
Taking timed quizzes and AP ICET mock tests is also essential for the candidates to prepare better for the examination and enhance their AP ICET 2025 performance.
The candidates are also advised to learn simple tricks for solving common question types to save time during the exam.
In this last month of AP ICET preparation, going through the recommended AP ICET 2025 preparation books is very helpful for the candidates. A list of such books shortlisted by the experts is given below.
Name of the Book | Authors/Publication |
Quantitative Aptitude for Competitive Examinations | RS Aggarwal |
Analytical & Logical Reasoning for Management Entrance Tests | Peeyush Bhardwaj |
Quantitative Aptitude Quantum CAT | Sarvesh K. Sharma |
Data Interpretation and Data Sufficiency | Arihant |
To support candidates in their AP ICET 2025 exam preparation, Careers360 has created a series of e-books in collaboration with subject matter experts. The download link for the ebook is provided below.
Title | Download Link |
Ultimate AP ICET: 2025 Mock Test eBook: Detailed Solutions & Comprehensive Resources | |
AP ICET 2025 Sample Papers PDF (Questions with Detailed Solutions) | |
AP ICET 2025: Business and Computer Terminology PDF |
The Analytical Ability section of the AP ICET 2025 exam carries a significant weightage, accounting for 37.5% of the total exam. This section consists of 75 questions out of the total 200, divided into Data Sufficiency (20 questions) and Problem-Solving (55 questions).
To prepare for the Data Sufficiency section, focus on understanding the logic behind the statements provided. You do not need to solve the entire problem but rather determine if the statements alone or together provide enough information to answer the question. Practice sample questions from various logical reasoning and quantitative ability topics, and avoid unnecessary calculations.
The Problem-Solving section includes topics like series completion, coding-decoding, analogies, seating arrangements, puzzles, and simple mathematical problems. Candidates should practice these topics extensively to improve speed and accuracy.
No, there are no changes in the AP ICET 2025 exam pattern or syllabus as per the latest updates from APSCHE. Candidates can expect a similar structure and question trend as in previous years, with a total of 200 questions divided into three sections: Analytical Ability, Communication Ability, and Mathematical Ability.
Recommended books for preparation include:
"Quantitative Aptitude for Competitive Examinations" by RS Aggarwal
"Analytical & Logical Reasoning for Management Entrance Tests" by Peeyush Bhardwaj
"Quantitative Aptitude Quantum CAT" by Sarvesh K. Sharma
"Data Interpretation and Data Sufficiency" by Arihant
These books cover essential topics and provide practice for the exam. Additionally, AP ICET 2025 sample papers and mock tests from sources like Careers360 can be helpful for comprehensive practice.
Dear Candidate ,
With an AP ICET 2025 rank of 2,591 under the BC-A female category , you have a fair chance of getting admission into MCA program at Andhra university. Although previous cutoffs for BC - A candidates were generally lower , female reservation and seat availability can improve your chances. Since reserved categories do not have minimum qualifying marks , you meet eligibility criteria. Make sure to participate in counseling, complete document verification, and prioritize Andhra University while filling choices .
Hello there,
With an AP ICET rank of 3314 and BC-A reservation, you have good chances to get admission in several reputed MCA colleges in Andhra Pradesh. Here are some suggestions known for good placements:
Andhra University College of Engineering, Visakhapatnam
Sri Venkateswara University, Tirupati
Jawaharlal Nehru Technological University (JNTU), Anantapur or Kakinada campuses
SV College of Engineering, Tirupati
GITAM University, Visakhapatnam
Aditya Engineering College, Surampalem
These colleges offer decent placement opportunities in IT and software companies. Your BC-A reservation improves your chances of admission in these government or private aided institutions.
Make sure to participate in the counseling process and verify seat availability and cutoff trends for this year.
I hope this answer helps you. If you have more queries, feel free to share your questions with us, and we will be happy to assist you.
Thank you, and I wish you all the best in your bright future.
Hello there,
For Andhra University Visakhapatnam MCA admission through AP ICET, cutoff marks vary each year. Generally, to get admission, you need around 140+ marks out of 200 for a good chance.
General category candidates must score at least 50 marks to qualify. Reserved categories may have lower qualifying marks.
After the AP ICET result, participate in the counseling process by registering on the official counseling website. Attend document verification and fill your college choices, including Andhra University.
Keep all documents like rank card, mark sheets, and caste certificate ready for counseling.
Check official counseling updates regularly to not miss deadlines.
I hope this answer helps you. If you have more queries, feel free to share your questions with us, and we will be happy to assist you.
Thank you, and I wish you all the best in your bright future.
Yes! With an
APICET rank of 12,404
, you have a good chance of getting an MBA seat at
Vignan’s Institute of Information Technology, Vizag
.
Last year’s cutoff was around
29,758
.
Check VIIT Vizag Cutoff – Careers360 (http://Check%20VIIT%20Vizag%20Cutoff%20%E2%80%93%20Careers360)
Hello there,
Yes, with an AP ICET 2025 rank of
2,752
, you have a strong chance of securing an MCA seat in several reputable colleges across Andhra Pradesh.
Your Admission Prospects
Based on previous years' cutoff trends, candidates with ranks up to 3,000 have successfully gained admission into top-tier institutions. For instance,
JNTU Kakinada's School of Management Studies (Self-Financed MCA)
had a cutoff range between
2,000 to 3,000
in 2024 . Given your rank, you are well-positioned to consider such institutions.
Potential Colleges for Your Rank
Here are some colleges where your rank could be competitive:
Acharya Nagarjuna University College (ANCU)
: Previously admitted candidates with ranks up to
6,900–7,000
for females and
20,000–21,000
for males.
Dr. B.R. Ambedkar University (BRAU)
: Accepted candidates with ranks around
30,000–31,000.
Godavari Institute of Engineering and Technology (GIER)
: Had cutoffs between
27,000–27,100.
Rajiv Gandhi Institute of Technology (RGIT) : Accepted ranks up to 32,000–33,000.
Given your rank of 2,752, you are well within the cutoff ranges for these institutions, enhancing your chances of admission.
I hope this answer helps you. If you have more queries, feel free to share your questions with us, and we will be happy to assist you.
Thank you, and I wish you all the best in your bright future.
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