CAT 2025 Formula Sheet: Key Quantitative Aptitude Formulas for Success

CAT 2025 Formula Sheet: Key Quantitative Aptitude Formulas for Success

Edited By Himanshu Shekhar | Updated on Jul 01, 2025 11:29 AM IST | #CAT

CAT 2025 Formulae: The CAT 2025 formula sheet is a powerful and strategic tool for aspirants targeting high scores in the Quantitative Aptitude section. It includes all vital formulas from Arithmetic, Algebra, Geometry, Trigonometry, and the Number System. Designed for quick revision and smart learning, this CAT formula sheet enhances concept clarity, boosts calculation speed, and improves performance in CAT mock tests. Regular use of this Quant formula sheet for CAT 2025 can significantly increase accuracy and help you crack the exam more efficiently.

This Story also Contains
  1. Overview of CAT 2025 Quantitative Aptitude section
  2. Key Features of the CAT Formula Sheet
  3. CAT Important Formulas of Geometry
  4. CAT Important Formulas of Trigonometry
  5. Quantitative Aptitude Formulae for CAT 2025
  6. Why is the CAT 2025 Formulae Important?
  7. How to Use the CAT 2025 Formulae Sheet for Exam Preparation?
  8. CAT 2025 Quantitative Aptitude Preparation
  9. CAT Preparation 2025 Important Books
CAT 2025 Formula Sheet: Key Quantitative Aptitude Formulas for Success
CAT 2025 Formula Sheet: Key Quantitative Aptitude Formulas for Success

Overview of CAT 2025 Quantitative Aptitude section

The CAT 2025 Quantitative Aptitude section is one of the most challenging sections of the MBA entrance exam. This is mainly due to the high difficulty level and tricky questions that are asked in it. However, candidates can master these topics from CAT 2025 Syllabus with the help of the CAT 2025 Formula Sheet.

Practising these formulas regularly helps to improve your speed in calculations and gain an edge over other candidates. Whether you are just starting to prepare for the CAT 2025 or getting ready for the final exam. It is important to make these quantitative formulas a key part of your study plan.

Key Features of the CAT Formula Sheet

The CAT Formula Sheet is a strategic tool designed to help aspirants quickly revise and recall essential formulas across key topics like Arithmetic, Algebra, Geometry, and Trigonometry. It enhances exam preparation by offering structured, topic-wise Quantitative Aptitude formulas that improve problem-solving efficiency and accuracy during the CAT exam.

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1. Topic-Wise Segregation for Focused Preparation
The CAT formula sheet is systematically divided into core Quantitative Aptitude topics such as Arithmetic, Algebra, Geometry, Trigonometry, and Number System. This organised structure helps aspirants target specific areas during revision.

2. Comprehensive and Exam-Relevant Formulas
It includes all important formulas for CAT that are frequently tested in past exams. Only high-utility formulas that directly aid in solving Quant questions are included. It helps students avoid distractions and concentrate on formulas with the highest exam relevance and scoring potential.

3. High-Visibility Layout for Quick Recall
Designed with readability in mind, the sheet uses bold headings, colour-coded sections, and concise formats to make it visually appealing and easy to scan. This makes it highly effective for last-minute CAT 2025 revision, especially when time is limited and quick recall is essential.

4. Quick Revision-Friendly Format
Ideal for daily practice and mock test preparation, the formula sheet allows aspirants to revise all crucial formulas quickly. It is vital for mastering speed-based problem-solving techniques required for the CAT Quantitative Aptitude section.

5. Updated According to the Latest CAT Exam Pattern
The formula sheet is regularly updated based on the latest trends, question formats, and difficulty levels observed in recent CAT exams. This ensures that aspirants are not only revising the right formulas but also staying aligned with the current CAT exam syllabus.

CAT Important Formulas of Geometry

Mastering important geometry formulas is crucial for cracking the CAT exam, as geometry is a key topic in the Quantitative Aptitude section. The following section covers all essential CAT geometry formulas, including areas, polygons, angles, and properties of triangles and circles to help you solve problems quickly and accurately.

Topic

Formula

Area of Triangle

$\frac{1}{2} \times \text{Base} \times \text{Height}$

Heron's Formula

$A = \sqrt{s(s-a)(s-b)(s-c)}$, where $s = \frac{a+b+c}{2}$

Pythagoras Theorem

$a^2 + b^2 = c^2$ (For right-angled triangle)

Equilateral Triangle Area

$\frac{\sqrt{3}}{4} a^2$

Circumference

$2\pi r$

Area of Circle

$2\pi r^2$

Length of Arc

$\frac{\theta}{360} \times 2\pi r$

Area of Sector

$\frac{\theta}{360} \times \pi r^2$

Area of Rectangle

$\text{Length} \times \text{Breadth}$

Perimeter of Rectangle

$2 \times (L + B)$

Area of Square

$a^2$

Perimeter of Square

$4a$

Area of Parallelogram

$\text{Base} \times \text{Height}$

Area of a Rhombus

$\frac{1}{2} \times d_1 \times d_2$

Sum of Interior Angles

$(n-2) \times 180^\circ$

Each Interior Angle (Regular Polygon)

$\frac{(n-2) \times 180}{n}$

Each Exterior Angle (Regular Polygon)

$\frac{360}{n}$

Surface Area of Sphere

$4\pi r^2$

Volume of Sphere

$\frac{4}{3} \pi r^3$

Surface Area of Cylinder

$2\pi r(h + r)$

Volume of Cylinder

$\pi r^2 h$

Surface Area of Cone

$\pi r (l + r)$

Volume of Cone

$\frac{1}{3} \pi r^2 h$

CAT Important Formulas of Trigonometry

Trigonometry plays a vital role in the CAT Quantitative Aptitude section, making it essential to learn and memorise key formulas. This comprehensive list of important CAT trigonometry formulas helps aspirants solve complex problems with speed, accuracy, and confidence during the exam.

1. Basic Trigonometric Ratios

These are defined in relation to a right-angled triangle:

  • $ \sin \theta = \frac{\text{Opposite side}}{\text{Hypotenuse}} $

  • $ \cos \theta = \frac{\text{Adjacent side}}{\text{Hypotenuse}} $

  • $ \tan \theta = \frac{\text{Opposite side}}{\text{Adjacent side}} $

  • $ \csc \theta = \frac{\text{Hypotenuse}}{\text{Opposite side}} $

  • $ \sec \theta = \frac{\text{Hypotenuse}}{\text{Adjacent side}} $

  • $ \cot \theta = \frac{\text{Adjacent side}}{\text{Opposite side}} $

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2. Pythagorean Identities

  • $ \sin^2 \theta + \cos^2 \theta = 1 $

  • $ 1 + \tan^2 \theta = \sec^2 \theta $

  • $ 1 + \cot^2 \theta = \csc^2 \theta $

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3. Trigonometric Functions of Negative Angles

  • $ \sin(-\theta) = -\sin \theta $

  • $ \cos(-\theta) = \cos \theta $

  • $ \tan(-\theta) = -\tan \theta $

  • $ \csc(-\theta) = -\csc \theta $

  • $ \sec(-\theta) = \sec \theta $

  • $ \cot(-\theta) = -\cot \theta $

4. Angle Sum and Difference Formulas

  • $ \sin(A + B) = \sin A \cos B + \cos A \sin B $

  • $ \sin(A - B) = \sin A \cos B - \cos A \sin B $

  • $ \cos(A + B) = \cos A \cos B - \sin A \sin B $

  • $ \cos(A - B) = \cos A \cos B + \sin A \sin B $

  • $ \tan(A + B) = \frac{\tan A + \tan B}{1 - \tan A \tan B} $

  • $ \tan(A - B) = \frac{\tan A - \tan B}{1 + \tan A \tan B} $

Quantitative Aptitude Formulae for CAT 2025

Quantitative Aptitude formulas form the foundation of the Quantitative Aptitude section in the CAT 2025 exam. Here are some important CAT 2025 quant section-wise formulae for CAT 2025 preparation:

Arithmetic

The Arithmetic section is the most important section in the Quantitative Aptitude Section, which is also useful to solve the Data Interpretation problems. Following are some 50+ Important Formulas for CAT Preparation of this section which are given in this CAT Formula Sheet:

Percentage

Following are some Important CAT Formulas of percentage:

$ \text{X is what percentage of Y} = \frac{X}{Y} \times 100% $

$ \text{X is what percentage more/less than Y} = \frac{|X - Y|}{Y} \times 100% $

$ \text{If X is } a% \text{ more than Y, then } X = Y \times \left( \frac{100 + a}{100} \right) $

$ \text{If X is } a% \text{ less than Y, then } X = Y \times \left( \frac{100 - a}{100} \right) $

Shortcut Formulas

Following are some formulas which can be used as CAT Quant Formulae:

Concept

Formula

Successive percentage change

$ \text{Overall } % \text{ change} = x + y + \frac{x \cdot y}{100} $

Changes in A when B and C are altered

$ \text{Overall } % \text{ change in A} = x + y + \frac{x \cdot y}{100} $

Price increase followed by a decrease

$ \text{Overall } % \text{ change in price} = -\frac{x^2}{100} $

Profit & Loss:

Following are some Important CAT Formulas of this topic:

Concept

Formula/Explanation

Selling Price and Profit

$ \text{S.P.} = \text{C.P.} + \text{Profit} $

Selling Price and Loss

$ \text{S.P.} = \text{C.P.} - \text{Loss} $

Profit or Loss Percentage

$ \text{Profit or Loss } % = \left( \frac{\text{Profit or Loss}}{\text{C.P.}} \right) \times 100% $

Discount Percentage

$ \text{Discount } % = \left( \frac{\text{Discount}}{\text{M.P.}} \right) \times 100% $

Selling Price with Profit or Loss

$ \text{S.P.} = \text{C.P.} \times \left( \frac{100 + \text{Profit}}{100} \right) \quad \text{or} \quad \text{C.P.} \times \left( \frac{100 - \text{Loss}}{100} \right) $

Shortcut Formulas

Cheat Sheet for the preparation and exam point of view:

Concept

Formula/Explanation

Profit or Loss with Markup and Discount

$ \text{Overall profit or loss } % = m - d - \frac{m \cdot d}{100} $

Simple Interest (S.I.) & Compound Interest (C.I.):

Following are some basic and Important Formulas for CAT 2025 related to Simple Interest and Compound Interest:

Concept

Formula/Explanation

Simple Interest

For Principal (P)

Rate of Interest (R)

Time (T)

$ \text{S.I.} = \frac{P \times R \times T}{100} $

Compound Interest (annually)

$ \text{Amount} = P \times \left(1 + \frac{R}{100} \right)^n \quad \text{(where } n = \text{Time in years)} $

Compound Interest (half-yearly)

$ \text{Amount} = P \times \left(1 + \frac{R}{2 \times 100} \right)^{2T} $

Total Amount

$ \text{Amount} = P + \text{Interest} $

Shortcut Formulas

Following are some formulas which can be used as CAT Quant Formula Cheat Sheet for the preparation and exam point of view:

Concept

Formula/Explanation

Doubling Time with Compound Interest

$ \text{Time to double} = \frac{72}{R} \text{ years} \quad (\text{where } R = \text{annual interest rate}) $

Example

$ \text{If } P = 2000 \text{ and } R = 8%, \text{ time to double} = \frac{72}{8} = 9 \text{ years} $

Difference Between C.I. and S.I. (2 years)

$ \text{C.I.} - \text{S.I.} = P \times \left( \frac{R}{100} \right)^2 $

Difference Between C.I. and S.I. (3 years)

$ \text{C.I.} - \text{S.I.} = P \times \left( \frac{R}{100} \right)^2 \times \left( 3 + \frac{R}{100} \right) $

Time, Speed & Distance:

Following are some basic and Important Formulas for CAT 2025 related to Time, Speed and Distance:

Concept

Formula/Explanation

Distance

$\text{Distance (D)} = \text{Speed (S)} \times \text{Time (T)}$

Average Speed

$ \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} $

Trains:

Concept

Formula/Explanation

Time for a train to cross a pole/person

$ \text{Time} = \frac{l}{s} $

Where:

  • $l$ = Length of the train

  • $s$ = Speed of the train

Time for a train to cross a platform/tunnel

$ \text{Time} = \frac{l + d}{s} $

Where:

  • $l$ = Length of the train

  • $d$ = Length of the platform or tunnel

  • $s$ = Speed of the train

Time for trains to cross each other (same direction)

$ \text{Time} = \frac{l_1 + l_2}{|s_1 - s_2|} $

Where:

  • $l_1$, $l_2$ = Lengths of Train 1 and Train 2

  • $s_1$, $s_2$ = Speeds of Train 1 and Train 2

Time for trains to cross each other (opposite direction)

$ \text{Time} = \frac{l_1 + l_2}{s_1 + s_2} $

Where:

  • $l_1$, $l_2$ = Lengths of Train 1 and Train 2

  • $s_1$, $s_2$ = Speeds of Train 1 and Train 2

Boat & Streams:

Concept

Formula/Explanation

Speed of Boat in Still Water

x kmph

Speed of Stream/Water/Current

y kmph

Travelling Time

t hr

Distance (Downstream: same direction)

D = (x + y) × t km

Distance (Upstream: opposite direction)

D = (x - y) × t km

Clocks:

Concept

Formula/Explanation

Speed of Hour Hand

0.5° per minute

Round covered by Hour Hand

1 round = 360° in 12 hours or 720 minutes

Speed of Minute Hand

6° per minute

Round covered by Minute Hand

1 round = 360° in 1 hour or 60 minutes

Angle between Hour and Minute Hands

θ = |112M-30H|

Shortcut Formulas

Following are some Quantitative Aptitude Formulas which can be used as a CAT Quant Formula Cheat Sheet for the preparation and exam point of view:

  1. If the distance covered in each stage of the journey is the same, but speeds are different, then the average speed is the harmonic mean of the different speeds.

Ex: If distance between point A to B and B to C are same and are covered with the speed of $s_1$ and $s_2$ respectively. Then-

$ \text{Average Speed} = \frac{2 S_1 S_2}{S_1 + S_2} $

  1. If the time taken in each stage of journey is same, but speeds are different then, the average speed is the average of the different speeds.

Ex: If time taken between points A to B and B to C is same and these distances are covered with the speed of $s_1$ and $s_2$ respectively. Then-

$ \text{Average Speed} = \frac{S_1 + S_2}{2} $

  1. If two people start running on a circular track of length D km in the same direction from the same point with speeds a & b kmph, then-

(i) Time taken in first meeting$ = \frac{D}{|a - b|} \text{ hr} $

(ii) Time taken to meet again at the starting point$ = \text{LCM} \left( \frac{D}{a}, \frac{D}{b} \right) $

(iii) Number of distinct meeting points$ = |x - y| $

{x & y are the simplified ratio of speeds, Ex: If speeds a & b are 12 kmph & 9 kmph

respectively, then- x: y = 12: 8 = 3: 2; So, x = 3 & y =2}

  1. If two people start running on a circular track of length D km in the opposite direction from the same point with speeds a & b kmph, then-

(i) Time taken in first meeting = D|a+b| hr.

(ii) Time taken to meet again at the starting point = LCM (Da ,Db) hr.

(iii) No. of Distinct meeting Points = |x + y|

{x & y are the simplified ratio of speeds}

  1. If a person P starts from A and heads towards B and another person Q starts from B and heads towards A and they meet after a time 't' then, $t=(x.y)$

[where x = time taken (after meeting) by P to reach B and y = time taken (after meeting) by Q to reach A]

  1. If the speed of the boat downstream is u kmph and the speed of the boat upstream is v kmph, then-

$ \text{Speed of the boat in still water} = \frac{u + v}{2} \text{ kmph} $

$ \text{Rate of stream} = \frac{u - v}{2} \text{ kmph} $

Geometry

The Geometry section is the lengthiest section in the Quantitative Aptitude Section which has lots of properties and formulas. Following are 50+ Important Formulas for CAT Preparation of this section which are given in this CAT Formula Sheet:

1. Triangles:

Properties of Triangles:

  1. The sum of all interior angles in a triangle is 180° and Exterior angles is 360°.

  2. The sum of any two sides is always greater than the third one and the difference of any two sides is less than the third one.

Let a,b,c are the sides of triangles, then

|b-c| < a < b + c

  1. In a Scalene Triangle the greatest side is always greater than the one-third of perimeter and less than half of the perimeter.

  • Let a,b,c are the sides of triangles and a is the greatest side of the triangle. The perimeter of the triangle is P.

P/3 < a < P/2

Ex: In a scalene triangle ABC, the perimeter of the triangle is 24 cm and all sides are integers.

Sol: Let a,b,c are sides of a triangle, and a is the greatest side.

$24/3 < a < 24/2$

$8 < a < 12$

So, all possible values are 9,10,11 cm.

  1. Let a,b,c are sides of a triangle, and a is the greatest side.

If $a^2<b^2+c^2$

Then triangle is an acute angled triangle

If $a^2=b^2+c^2$

Then triangle is a Right-angled triangle= Pythagoras theorem

If $a^2>b^2+c^2$

Then triangle is an Obtuse angled triangle

  1. (Here D is the midpoint of the AC side or AD = DC).

Mid point of triangle

  1. Length of the Median-

$ BD = \frac{1}{2} \sqrt{2(AB^2 + BC^2) - AC^2} $

  1. 3 (Sum of squares of sides) = 4 (Sum of squares of medians)

$ 3(a^2 + b^2 + c^2) = 4(M_a^2 + M_b^2 + M_c^2) $

{Where a,b,c are sides of triangle and Ma, Mb, Mc are medians of the triangle}

  1. In a right-angle triangle, Median of Hypotenuse= Hypotenuse/2

$CD = \frac{AB}{2}$

median of hypotenuse

  1. If all the medians are drawn in the triangle, then the 6 small triangles are generated in the triangle, which are equal in the Area.

Area of Triangle:

  1. Heron’s Formula

If all sides of a triangle are given. Let a,b,c are sides of triangle-

$ \text{Area} = \sqrt{s(s - a)(s - b)(s - c)} \quad \text{where } s = \frac{a + b + c}{2} $ where s is the semiperimeter.

  1. If two sides and one included angle is given-

Area = ½ x Product of given sides x Sin(given included angle)

$ \text{Area} = \frac{1}{2} \times a \times b \times \sin C $

{ex: sides a, b are given and included angle C is given}

  1. If a side and its respective Altitude (perpendicular drawn on a side from the opposite vertex) is given, then-

Area of the triangle = ½ x Base x Height (Altitude)

Shortcut Formulas

  1. $ \text{Area of an equilateral triangle} = \frac{\sqrt{3}}{4} a^2 $

  2. $ \text{Height (Altitude) of an equilateral triangle} = \frac{\sqrt{3}}{2} a $

  3. $ \text{Area of a triangle} = r \times s \quad \text{(where $r$ is inradius and $s$ is semi-perimeter)} $

  4. $ \text{Area of a triangle} = \frac{abc}{4R} \quad \text{(where $a$, $b$, $c$ are sides and $R$ is circumradius)} $

Quadrilaterals:

Trapezium

Trapezium

Area = ½ x (Sum of Parallel Sides) x Height (perpendicular distance between parallel sides)

= ½ x (AB + CD) X H

Parallelogram

Parallelogram

  1. Opposite angles and sides are equal.

  2. Diagonals bisect each other.

  3. $ \text{Sum of squares of diagonals} = 2(a^2 + b^2) $

  4. $ \text{Area} = \text{Base} \times \text{Height} $

  5. $ \text{Area} = a \cdot b \cdot \sin \theta $

Rhombus

Rhombus






  1. All sides and opposite angles are equal.

  2. Diagonals bisect each other at $90^\circ$.

  3. $ \text{Sum of squares of diagonals} = 4a^2 $

  4. $ \text{Area} = \frac{1}{2} \times d_1 \times d_2 $

  5. $ \text{Perimeter} = 4a $

Where:

  • $a$ is the length of a side

  • $d_1$ and $d_2$ are the lengths of the diagonals


Rectangle

  1. $ \text{Perimeter} = 2(l + b) \quad \text{(where } l = \text{length, } b = \text{breadth)} $

  2. $ \text{Area} = l \cdot b $

  3. $ \text{Length of diagonal} = \sqrt{l^2 + b^2} $


Square

  1. $ \text{Perimeter} = 4a \quad \text{(where } a = \text{side of square)} $

  2. $ \text{Area} = a^2 $

  3. $ \text{Length of diagonal} = a \sqrt{2} $

Cyclic Quadrilateral

Cyclic Quadrilateral

  1. $ \text{Sum of opposite angles} = 180^\circ $

  2. $ \text{Area} = \frac{1}{2} \times d_1 \times d_2 \times \sin \theta \quad \text{(where } \theta \text{ is the angle between diagonals)} $

  3. $ \text{Area} = \sqrt{(s - a)(s - b)(s - c)(s - d)} \quad \text{(where } a, b, c, d \text{ are sides and } s = \frac{a + b + c + d}{2} \text{ is semi-perimeter)} $

3. Circle:

$ \text{Circumference of a circle} = 2\pi r $

$ \text{Area of a circle} = \pi r^2 $

Semi-circle

$ \text{Circumference of a semi-circle} = \pi r $

$ \text{Perimeter of a semi-circle} = \pi r + 2r $

$ \text{Area of a semi-circle} = \frac{\pi r^2}{2} $

Sector & Segment of circle

1721716318104

{OAXC is called the sector of the circle & AXC is called the segment}

  • $ \text{Length of arc AXC} = \frac{\theta}{360} \times 2\pi r \quad \text{(where } r \text{ is the radius)} $

  • $ \text{Area of sector OAXC} = \frac{\theta}{360} \times \pi r^2 $

  • $ 2 \times \text{Area of sector} = \text{Length of arc} \times \text{Radius} $

  • $ \text{Area of segment AXC} = \text{Area of sector OAXC} - \text{Area of } \triangle OAC $

  • $ A = \frac{\theta}{360} \pi r^2 - \frac{1}{2} r^2 \sin \theta $

Where:

  • $\theta$ is the angle subtended at the center (in degrees)

  • $r$ is the radius of the circle

Common Tangent

PQ & RS are the direct common tangents of the circle, which are equal in length. Length of direct common tangent (L)-

$L^2=d^2–(r_1−r_2)^2$

{d = distance between centers of circle, $r_1,r_2$ are radius of circle}

distance between centers of circle, r1,r2 are radius of circle

  1. PQ & RS are the transverse common tangents of the circle, which are equal in length. Length of transverse common tangent (L)-

  2. $ L^2 = d^2 - (r_1 + r_2)^2 $

Where:

  • $L$ is the length of the direct common tangent,

  • $d$ is the distance between the centers of the two circles,

  • $r_1$ and $r_2$ are the radii of the two circles.

distance between centers of circle, r1,r2 are radius of circle

Mensuration:

Cube

{a- side of cube}

  1. $ \text{Lateral Surface Area (L.S.A.)} = 4a^2 $

  2. $ \text{Total Surface Area (T.S.A.)} = 6a^2 $

  3. $ \text{Volume} = a^3 $

Where:

  • $a$ is the side length of the cube.


Cuboid

{l-length, b-breadth,

h-height}

  1. $ \text{Lateral Surface Area (L.S.A.)} = 2(l + b) \cdot h $

  2. $ \text{Total Surface Area (T.S.A.)} = 2(lb + bh + lh) $

  3. $ \text{Volume} = l \cdot b \cdot h $

Where:

  • $l$ = length,

  • $b$ = breadth,

  • $h$ = height of the cuboid.

Cylinder

{r-radius of circular base,

h-height}

  1. $ \text{Curved Surface Area (C.S.A.)} = 2\pi r h $

  2. $ \text{Total Surface Area (T.S.A.)} = 2\pi r (r + h) $

  3. $ \text{Volume} = \pi r^2 h $

Where:

  • $r$ = radius of the base,

  • $h$ = height of the cylinder

Cone

{r-radius of circular base,

h-height, l- slant height}

  1. $ \text{Curved Surface Area (C.S.A.)} = \pi r l $

  2. $ \text{Total Surface Area (T.S.A.)} = \pi r (r + l) $

  3. $ \text{Volume} = \frac{1}{3} \pi r^2 h $

Where:

  • $r$ = radius of the base,

  • $l$ = slant height,

  • $h$ = height of the cone.

Sphere

{r-radius}

  1. $ \text{Total Surface Area} = 4\pi r^2 $

  2. $ \text{Volume} = \frac{4}{3} \pi r^3 $

Where:

  • $r$ = radius of the sphere.

Hemi-sphere

{r-radius}

  1. $ \text{Curved Surface Area (C.S.A.)} = 2\pi r^2 $

  2. $ \text{Total Surface Area (T.S.A.)} = 3\pi r^2 $

  3. $ \text{Volume} = \frac{2}{3} \pi r^3 $

Where:

  • $r$ = radius of the hemisphere.

Algebra

The Algebra section is a critical part of the Quantitative Aptitude section in the CAT exam. Below are over 50 important formulas for CAT preparation in this section, which are provided in this comprehensive CAT Formula Sheet:

1. Quadratic Equations

  1. General Quadratic equation will be in the form of $??^2+??+?=0$

  2. Values of ‘x’ which satisfies the equation are called roots of the equation. To find the roots the Shreedhara Acharya's Formula is used.

Roots of the equation,

$ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} $

$ \text{Sum of the roots} = -\frac{b}{a} $

$ \text{Product of the roots} = \frac{c}{a} $

$ \text{Difference of the roots} = \frac{D}{a} \quad \text{where } D = b^2 - 4ac $

If $ D > 0 $, then the roots of the equation are real and distinct.

i. If D is perfect square, then roots will be rational; ex: x = 1,6

ii. If D is non-perfect square, then roots will be irrational or conjugate surds

ex: $x = 3-\sqrt{5}, 3+\sqrt{5}$

If $ D = 0 $, then the roots of the equation are real and equal.

If $ D < 0 $, then the roots of the equation are imaginary and distinct.

$ y = ax^2 + bx + c \quad \text{where } a > 0 $

  • For $ y = ax^2 + bx + c $, if $ a > 0 $, the minimum value occurs at $ x = \frac{-b}{2a} $ and is given by:
    $ y = \frac{-D}{4a} \quad \text{(Minimum value)} $

  • For $ y = ax^2 + bx + c $, if $ a < 0 $, the maximum value occurs at $ x = \frac{-b}{2a} $ and is given by:
    $ y = \frac{-D}{4a} \quad \text{(Maximum value)} $

Where $ D = b^2 - 4ac $ is the discriminant.

If the roots of the quadratic equation are $a$ and $b$, then the quadratic equation is:

$ x^2 - Sx + P = 0 \quad \text{where } S = a + b \text{ and } P = ab $

That is:

$ x^2 - (a + b)x + ab = 0 $

Progression & Series

In this chapter there are three types of progression, which are-

  1. Arithmetic Progression

  2. Geometric Progression

  3. Harmonic Progression

Arithmetic Progression (A.P.)

If a is the first term and d is the common difference then the Arithmetic Progression (A.P.). can be written as-

  • $ a,\ a + d,\ a + 2d,\ a + 3d,\ \ldots $

Where:

$a$ = first term

$d$ = common difference

Nth term of the A.P. –

$T_n=a+(n−1).d$

Here $n$ is the no. of terms

Sum of the n terms of the A.P. ($S_n$) = Average of all the terms x no. of terms(n)

Average of the terms can be found out easily

  • If no. of terms is odd then the middle term will be the average

Ex: 2,5,8,11,14 are the terms of the A.P. then middle term 8 is the average

So, the sum = avg. x n = 8 x 5 = 40

  • If no. of terms is even then the average of middle terms will be the average of the A.P.

$S_n=\frac{n}{2}[2a+(n−1)d]$

Shortcut Formulae

$ S_n = \frac{n}{2}(a + l) \quad \text{(where } a = \text{first term, } l = \text{last term, } n = \text{number of terms)} $

$ n = \frac{l - a}{d} + 1 \quad \text{(number of terms in A.P.)} $

Geometric Progression (G.P.)

If a is the first term and r is the common ratio then the Geometric Progression (G.P.) can be written as-

$a,a.r,a.r^2,a.r^3,\ldots$

Nth term of the G.P. –

$T_n=a.r^{n−1}$ where n is the no. of terms

Sum

  • $ S_\infty = \frac{a}{1 - r} \quad \text{if } |r| < 1 $

  • If $ r < 1 $:
    $ S_n = a \cdot \frac{1 - r^n}{1 - r} $

  • If $ r > 1 $:
    $ S_n = a \cdot \frac{r^n - 1}{r - 1} $

Where:

$a$ = first term

$r$ = common ratio

$n$ = number of terms

Sum of infinite terms of the G.P.-

$ S_\infty = \frac{a}{1 - r} \quad \text{if } |r| < 1 $

Where:

  • $a$ = first term

  • $r$ = common ratio

  • $|r| < 1$ ensures the series converges.

Shortcut Formulas

If there are odd no. of terms in a G.P., then the product of all terms are equal to the nth power of the middle term.

e.g. 2,6,18,54,162 are the terms of a G.P.

Then the products of all the terms = 185

Harmonic Progression (H.P.)

If $ a, b, c $ are in A.P., then $ \frac{1}{a}, \frac{1}{b}, \frac{1}{c} $ are in Harmonic Progression (H.P.).

$ \text{n-th term of the H.P.} = \frac{1}{\text{n-th term of the corresponding A.P.}} $

Series

Sum of first $n$ natural numbers:
$ 1 + 2 + 3 + \cdots + n = \frac{n(n+1)}{2} $

Sum of squares of first $n$ natural numbers:
$ 1^2 + 2^2 + 3^2 + \cdots + n^2 = \frac{n(n+1)(2n+1)}{6} $

Sum of cubes of first $n$ natural numbers:
$ 1^3 + 2^3 + 3^3 + \cdots + n^3 = \left( \frac{n(n+1)}{2} \right)^2 $

Sum of first $n$ natural odd numbers:
$ 1 + 3 + 5 + \cdots + (2n - 1) = n^2 $

Sum of squares of first $n$ even numbers:
$ 2^2 + 4^2 + 6^2 + \cdots + (2n)^2 = \frac{2n(n+1)(2n+1)}{3} $

Sum of squares of first $n$ odd numbers:
$ 1^2 + 3^2 + 5^2 + \cdots + (2n - 1)^2 = \frac{n(2n+1)(2n-1)}{3} $

Indices & Surds

Product Rule:

$ a^m \cdot a^n = a^{m+n} $

Quotient Rule:

$ \frac{a^m}{a^n} = a^{m - n} $

Power of a Power:

$ (a^m)^n = a^{mn} $

Power of a Product:

$ (ab)^n = a^n \cdot b^n $

Power of a Quotient:

$ \left( \frac{a}{b} \right)^n = \frac{a^n}{b^n} $

Negative Exponent:

$ a^{-n} = \frac{1}{a^n} $

Shortcut Formulae

$ \prod_{n=1}^{\infty} a = \lim_{n \to \infty} a_n $

Logarithmic Rules and Properties

Definition of Logarithm:

$ \log_b a = x \iff b^x = a $

Log of 1:

$ \log_b 1 = 0 \quad \text{(for any base } b > 0,\ b \ne 1) $

Log of the base itself:

$ \log_b b = 1 $

Log of a product:

$ \log_b (mn) = \log_b m + \log_b n $

Log of a quotient:

$ \log_b \left( \frac{m}{n} \right) = \log_b m - \log_b n $

Log of a power:

$ \log_b (m^n) = n \cdot \log_b m $

Change of base formula:

$ \log_b a = \frac{\log_k a}{\log_k b} \quad \text{(commonly with base 10 or } e \text{)} $

Base switch rule:

$ \log_a b = \frac{1}{\log_b a} $

Why is the CAT 2025 Formulae Important?

CAT 2025 Formulae is crucial for MBA exam preparation as it compiles essential mathematical formulas and concepts, streamlining study efforts and enhancing exam readiness. This resource not only aids in quick recall but also fosters a deeper understanding of quantitative topics.

  • A consolidated formula PDF for CAT allows for focused study sessions. It also reduces the time spent searching for formulas across various resources.

  • Regular use of the CAT formula PDF helps in developing quick problem-solving techniques. This is essential for tackling the time constraints of the CAT exam.

  • A CAT formula sheet helps candidates to do quick revisions before the examination.

  • Familiarity with formulas leads to fewer mistakes during the exam. This boosts both confidence and accuracy before the examination.

  • Understanding which formulas are most relevant helps candidates prioritise questions. This leads to a more strategic approach and helps in maximising their scores.

How to Use the CAT 2025 Formulae Sheet for Exam Preparation?

A CAT 2025 formula sheet is an advanced tool for precision-driven preparation, enabling strategic revision and targeted practice. Read on to know about the ways in which you can use the CAT 2025 formula PDF for the examination.

  • Dedicate specific time slots each day to review and recite formulas. This reinforces memory retention and ensures familiarity with key concepts.

  • Pair each formula with example problems to understand its application. This enhances comprehension and enables quicker recall during the exam.

  • Use the formula sheet while attempting the CAT 2025 mock tests. This allows for real-time application and helps to identify areas needing further practice.

  • Create visual aids or mind maps from the formula sheet to connect related concepts, facilitating deeper understanding and quicker retrieval during problem-solving.

  • Refine the formula sheet regularly by adding new insights, shortcuts, or variations encountered during practice.

CAT 2025 Quantitative Aptitude Preparation

Whether you're reviewing concepts or tackling practice problems, having a CAT formulas cheat sheet at your fingertips provides immediate access to vital quantitative formulas. This resource is essential for streamlining your preparation, as it gathers all necessary CAT 2025 quant formulae, enhancing both efficiency and effectiveness.

Careers360 has developed a comprehensive ebook featuring the top 100 facts. It helps candidate by boosting their preparation for the CAT 2025 quantitative aptitude section. It also contains essential formulas relevant to the CAT QA section. Candidates can download and study this ebook for effective CAT Quantitative Aptitude 2025 exam preparation.

Title

Link

100 Quant Facts Every CAT Aspirant Must Know

Download Now

CAT 2025 Quantitative Aptitude Syllabus

The CAT Quantitative Aptitude Syllabus is one of the most crucial resources that candidates must keep handy before commencing their preparations. The CAT Syllabus 2025 consists of topics that are asked during the examination. Refer to the table below to get the updated CAT 2025 Quantitative Aptitude syllabus.




Arithmetic

1. Percentage (Basics and related questions)

2. Ratios (Basics and related concepts i.e.Proportions and Variations )

3. Averages (Basics and related concepts i.e. Mixture and Alligation )

4. Profit & Loss

5. Simple Interest and Compound Interest

6. Time, Speed and Distance

(Questions related to Trains and Stream etc.)

7. Time & Work


Number System

1. Numbers and their classification i.e. Prime numbers, rational numbers, fractions, integers etc.

2. Divisibility Rule

3. Factorisation of Numbers

4. LCM & HCF related questions



Geometry

1. Lines and angles

2. Triangles (area, similarity, congruency etc.)

3. Circles

4. Quadrilaterals (Rectangle, square, trapezium)

5. Mensuration (Area and volume of 2D and 3D figures)

6. Trigonometry

7. Co-ordinate Geometry


Algebra

1. Advance Linear Equations

2. Quadratic Equations, Inequalities & Modulus

3. Progression & Series (Arithmetic Progression, Geometric Progression, Harmonic Progression and Relation Between AM, GM and HM)

4. Indices & Surds

5. Logarithm

Miscellaneous

1. Permutation & Combination

2. Probability

CAT Preparation 2025 Important Books

Choosing the right set of books during CAT preparation 2025 is very essential to excel in the examination. These books offer conceptual clarity for different topics and also provide ample practice questions. Here is a list of important books on CAT 2025 Quantitative Aptitude.

CAT Quantitative Aptitude Books

Book Title

Author

How to Prepare for Quantitative Aptitude for the CAT

Arun Sharma

NCERT Mathematics Books (Class 6 to 10)

NCERT

Quantitative Aptitude Quantum CAT

Sarvesh Sharma

Quantitative Aptitude for Competitive Examinations

Abhijit Guha

Frequently Asked Questions (FAQs)

1. How do I start my CAT preparation for 2025?

For CAT preparation 2025, candidates must start their preparation with proper analysis and understanding of the CAT exam pattern and syllabus. They should devise the CAT study plan and focus on important topics to cover them within the stipulated time. 

2. Is 1 month enough for CAT preparation?

CAT preparation requires a significant amount of time to prepare. However, candidates can prepare the CAT exam syllabus within 1 month if the right strategy and determination are executed. 

3. What is the formula for probability in CAT?

CAT Probability or Chance: Probability is a quantitative measure of the likelihood of a particular event occurring. $PE=n(E)/n(S)$, where n(E) = number of favorable events; n(S) = sample space.

4. What is the important formula for percentage in CAT exam?

Important percentage formulas for CAT exam are:

  • Increase N by S% = N(1+S/100)
  • Decrease N by S% = N(1 - S/100)
  • Percentage Change=(New Value−Old Value/Old Value)×100
5. How can I effectively memorize the important formulas for CAT?

Use flashcards, practice problems, and regular revision to reinforce memory and understanding of key formulas.

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Questions related to CAT

Have a question related to CAT ?

Hello Ashish,

Yes, you can get admission to MBA programs at IISWBM without a CAT score, but only for certain courses. Note that IISWBM has MBA programs under the University of Calcutta and flagship courses like MBA (Day) or MBA-HRM typically require a CAT score. Other programs like the PGDM or Executive MBA/Course may have other entrance examinations on which consideration would be made, or considerations may be based on merit, and of course work experience. Always run any eligibility detail checks with the official IISWBM (https://www.iiswbm.edu/) website or The IISWBM prospectus.

Hello,

Yes, a state (Delhi) NC-OBC certificate is valid for CAT 2025 , but it must be in the central government format (for appointment to posts under Government of India).

Also, it should be issued after 31st March 2025, as required by IIMs. If your certificate meets these conditions, it will be accepted.

Hope it helps !

Hello aspirant,
With 375 marks and an AIR of around 2.6 lakh in NEET 2025, getting admission to Ayurvedic & Unani Tibbia College (AUTC), New Delhi under the state quota is quite difficult. The cutoffs for government BAMS seats in AUTC generally stay below AIR 50,000, especially for the General and EWS categories. Your score may not meet the cutoff in the first or second rounds, but you might still have a slim chance in the mop-up or stray vacancy rounds, depending on how many seats remain and how other candidates opt. If you're a Delhi domicile and have all your documents ready, you should definitely apply and fill AUTC as a top choice. It’s also good to keep backup options in other AYUSH colleges open.

GIBS Business School in Bangalore accepts multiple national and state-level entrance exam scores for admission to its PGDM program. You can apply using scores from exams like CAT, MAT, XAT, CMAT, GMAT, ATMA, or various state-level CETs.

The admission process typically considers your entrance exam score along with your academic record, performance in the group discussion and personal interview, and any work experience you may have. For the BBA program, admissions are generally based on your Class 12 marks and do not require entrance exam scores.

If you're planning to apply, it's a good idea to keep your exam score, academic documents, and personal statement ready for the selection rounds.

If your son’s first preference is CSE, then Amrita Bangalore clearly leads among the three, simply because CSE opens more doors in terms of placements, internships, and future-proof careers. Amrita is also NAAC A++ and has a strong reputation, especially for CSE. Category 2 is also manageable fee-wise compared to higher categories.

VIT Chennai is a decent campus, and their ECE program is solid, but Category 5 means much higher fees and very low chance of branch upgrade later. CSE at VIT Chennai would have been more competitive here — but ECE at that fee tier is not as strong a deal unless your son has a strong interest in core electronics.

Manipal Bangalore (MIT Bengaluru campus) is a newer campus. ECE there is still developing in terms of placements and faculty compared to the main Manipal campus. Unless your son strongly prefers Bangalore or is getting some advantage here like scholarships or internship access, it doesn't stand out above Amrita.

So, recommendation: Go with Amrita Bangalore CSE (Category 2). It balances a strong branch with a decent campus and better long-term potential in the tech industry. If your son is open to core electronics and you’re okay with the higher cost, VIT Chennai is fine, but still comes second to CSE at Amrita.

All the best!

View All

Directions for question :

M/s Deloitte Touche Tohmatsu Limited, one of the top four audit and accounting firms in the world with headquarters at London, UK, and with an operational presence in 153 countries, hires Management Trainees (MT) from all the premier management institutes of India thrice every year, in the months of January, May and September.

Each new group of Management Trainees (MT) have to go through a four month rigorous training schedule, after which they have to pass through a test consisting of a written assessment and a case-analysis. The top hundred ranked Management Trainees (MT) based on the performance in the test are confirmed as Management Executives (ME). The rest are given the opportunity of undergoing the training for four months one more time along with the next batch of Management Trainees (MT) and then passing through the subsequent test consisting of the written assessment and case-analysis. The Management Trainee (MT) who fails to get confirmed as a Management Executive (ME) the second time is fired.

The scatter-graph below depicts the number of Management Trainees (MT) at Deloitte taking the tests from January 2020 till May 2022, and the vis-à-vis hired Management Trainees (MT) at Deloitte who were fired :

It is also known that for the month of September 2019 at Deloitte, 96 hired Management Trainees (MT) failed to be confirmed as a Management Executive (ME) the first time, and that 36 hired Management Trainees (MT) were fired. 

Question :

In which test did the minimum number of Management Trainees (MT) get confirmed as a Management Executive (ME) in the second attempt ?

Option: 1

September 2020

 

 


Option: 2

May 2021


Option: 3

January 2021

 


Option: 4

January 2022 


Directions for question:

Two friends Moloy and Niloy passed out from the Purulia Institute of Science and Technology with B.Tech degrees in Mechanical Engineering, but even after a year placement was hard to find. So they decided to take the challenge head-on, came down to Kolkata, rented a garage space on Park Street, and having an affinity towards making people enjoy good food, started their firm named 'B.Tech Bread-Omlette Wala'. 

They started with three items on the menu. One was the French Toast which could be prepared in 3 minutes. The second was the Egg Tortillas which took 15 minutes to prepare. Any one of Moloy and Niloy could prepare any one of them at a time. The third was the Egg Bhurji with French Fries. This however was prepared on an automated fryer which could prepare 3 servings at a time and took 5 minutes irrespective of the number of servings equal to or below 3. The fryer did not need anyone to attend to it, and the time to put in the raw ingredients could be neglected. So one could tend to the preparation of other items while the Egg Bhurji with French Fries were being prepared. 

They wanted to serve the orders as early as possible after the order was given. The individual items in any order were served as and when all the items were ready, and the order was then considered closed. None of the items on the menu were prepared in advance in anticipation of future orders. 

On the first day, 3 groups of customers came in and ordered at 6.00 pm, 6.10 pm, and 6.13 pm. The first order was for a plate of Egg Tortillas, two plates of French Toast, and three plates of Egg Bhurji with French Fries. The second order was for a plate of French Toast and two plates of Egg Bhurji with French Fries. The third order was for a plate of Egg Tortilla and a plate of Egg Bhurji with French Fries. 

On the backdrop of the above information answer the questions given :

Question: 

Assuming that the next customer's order could only be attended to when the previous customer's order was closed, at what time would the first customer's order be considered closed ?

 

Option: 1

6.15 pm

 

 


Option: 2

6.17 pm

 


Option: 3

6.18 pm

 


Option: 4

6.20 pm


Directions for question :

Six sticks of equal lengths were kept in the vertical position in an empty flower-vase, to be arranged at the six corners of a regular hexagon. The two ends of each of the sticks were of different colours. 

The top ends of the sticks were one of each of the following colours – Red, Cyan, Pink, Brown, Black and Green. The bottom ends were one of each of the following colours – Blue, Yellow, White, Orange, Purple and Grey. Both the sets of colours mentioned were in no particular order.

It was also known that :

a) The stick with the red colour was opposite to the stick with the blue colour

b) There were exactly two sticks whose both ends had colours whose names started with the same letter

c) The stick with the grey colour was adjacent to the stick with the white colour

d) The stick with the cyan colour was adjacent to both the sticks with the brown colour and the one with the blue colour

e) The stick with the purple colour was adjacent to both the sticks with the grey colour and the one with the green colour

f) The stick with the white colour was opposite to the stick with the green colour

Question :

What was the colour of the bottom end of the stick having brown colour at the top end ?

Option: 1

 White 

 


Option: 2

Yellow 


Option: 3

Black

 


Option: 4

Grey


Directions for question:

Two friends Moloy and Niloy passed out from the Purulia Institute of Science and Technology with B.Tech degrees in Mechanical Engineering, but even after a year placement was hard to find. So they decided to take the challenge head-on, came down to Kolkata, rented a garage space on Park Street, and having an affinity towards making people enjoy good food, started their firm named 'B.Tech Bread-Omlette Wala'. 

They started with three items on the menu. One was the French Toast which could be prepared in 3 minutes. The second was the Egg Tortillas which took 15 minutes to prepare. Any one of Moloy and Niloy could prepare any one of them at a time. The third was the Egg Bhurji with French Fries. This however was prepared on an automated fryer which could prepare 3 servings at a time and took 5 minutes irrespective of the number of servings equal to or below 3. The fryer did not need anyone to attend to it, and the time to put in the raw ingredients could be neglected. So one could tend to the preparation of other items while the Egg Bhurji with French Fries were being prepared. 

They wanted to serve the orders as early as possible after the order was given. The individual items in any order were served as and when all the items were ready, and the order was then considered closed. None of the items on the menu were prepared in advance in anticipation of future orders. 

On the first day, 3 groups of customers came in and ordered at 6.00 pm, 6.10 pm, and 6.13 pm. The first order was for a plate of Egg Tortillas, two plates of French Toast, and three plates of Egg Bhurji with French Fries. The second order was for a plate of French Toast and two plates of Egg Bhurji with French Fries. The third order was for a plate of Egg Tortilla and a plate of Egg Bhurji with French Fries. 

On the backdrop of the above information answer the questions given :

Question: 

Assuming that the next customer's order could only be attended to when the previous customer's order was closed, at what time would the third customer's order be considered closed ?

 

Option: 1

6.28 pm

 


Option: 2

6.35 pm

 


Option: 3

6.38 pm


Option: 4

6.45 pm


Directions for question:

Two friends Moloy and Niloy passed out from the Purulia Institute of Science and Technology with B.Tech degrees in Mechanical Engineering, but even after a year placement was hard to find. So they decided to take the challenge head-on, came down to Kolkata, rented a garage space on Park Street, and having an affinity towards making people enjoy good food, started their firm named 'B.Tech Bread-Omlette Wala'. 

They started with three items on the menu. One was the French Toast which could be prepared in 3 minutes. The second was the Egg Tortillas which took 15 minutes to prepare. Any one of Moloy and Niloy could prepare any one of them at a time. The third was the Egg Bhurji with French Fries. This however was prepared on an automated fryer which could prepare 3 servings at a time and took 5 minutes irrespective of the number of servings equal to or below 3. The fryer did not need anyone to attend to it, and the time to put in the raw ingredients could be neglected. So one could tend to the preparation of other items while the Egg Bhurji with French Fries were being prepared. 

They wanted to serve the orders as early as possible after the order was given. The individual items in any order were served as and when all the items were ready, and the order was then considered closed. None of the items on the menu were prepared in advance in anticipation of future orders. 

On the first day, 3 groups of customers came in and ordered at 6.00 pm, 6.10 pm, and 6.13 pm. The first order was for a plate of Egg Tortillas, two plates of French Toast, and three plates of Egg Bhurji with French Fries. The second order was for a plate of French Toast and two plates of Egg Bhurji with French Fries. The third order was for a plate of Egg Tortilla and a plate of Egg Bhurji with French Fries. 

On the backdrop of the above information answer the questions given :

Question: 

Suppose Moloy and Niloy had decided to process multiple orders at the same time, however strictly prioritising a first come first serve basis, when would the second customer's order be considered closed ?

Option: 1

6.20 pm

 

 


Option: 2

6.18 pm


Option: 3

6.15 pm

 


Option: 4

6.12 pm


Directions for question:

Two friends Moloy and Niloy passed out from the Purulia Institute of Science and Technology with B.Tech degrees in Mechanical Engineering, but even after a year placement was hard to find. So they decided to take the challenge head-on, came down to Kolkata, rented a garage space on Park Street, and having an affinity towards making people enjoy good food, started their firm named 'B.Tech Bread-Omlette Wala'. 

They started with three items on the menu. One was the French Toast which could be prepared in 3 minutes. The second was the Egg Tortillas which took 15 minutes to prepare. Any one of Moloy and Niloy could prepare any one of them at a time. The third was the Egg Bhurji with French Fries. This however was prepared on an automated fryer which could prepare 3 servings at a time and took 5 minutes irrespective of the number of servings equal to or below 3. The fryer did not need anyone to attend to it, and the time to put in the raw ingredients could be neglected. So one could tend to the preparation of other items while the Egg Bhurji with French Fries were being prepared. 

They wanted to serve the orders as early as possible after the order was given. The individual items in any order were served as and when all the items were ready, and the order was then considered closed. None of the items on the menu were prepared in advance in anticipation of future orders. 

On the first day, 3 groups of customers came in and ordered at 6.00 pm, 6.10 pm, and 6.13 pm. The first order was for a plate of Egg Tortillas, two plates of French Toast, and three plates of Egg Bhurji with French Fries. The second order was for a plate of French Toast and two plates of Egg Bhurji with French Fries. The third order was for a plate of Egg Tortilla and a plate of Egg Bhurji with French Fries. 

On the backdrop of the above information answer the questions given :

Question: 

Suppose Moloy and Niloy had decided to process multiple orders at the same time, however strictly prioritising a first come first serve basis, when would the third customer's order be considered closed ?

 

Option: 1

6.22 pm

 


Option: 2

6.25 pm


Option: 3

6.28 pm 


Option: 4

6.30 pm


Directions for question:

Two friends Moloy and Niloy passed out from the Purulia Institute of Science and Technology with B.Tech degrees in Mechanical Engineering, but even after a year placement was hard to find. So they decided to take the challenge head-on, came down to Kolkata, rented a garage space on Park Street, and having an affinity towards making people enjoy good food, started their firm named 'B.Tech Bread-Omlette Wala'. 

They started with three items on the menu. One was the French Toast which could be prepared in 3 minutes. The second was the Egg Tortillas which took 15 minutes to prepare. Any one of Moloy and Niloy could prepare any one of them at a time. The third was the Egg Bhurji with French Fries. This however was prepared on an automated fryer which could prepare 3 servings at a time and took 5 minutes irrespective of the number of servings equal to or below 3. The fryer did not need anyone to attend to it, and the time to put in the raw ingredients could be neglected. So one could tend to the preparation of other items while the Egg Bhurji with French Fries were being prepared. 

They wanted to serve the orders as early as possible after the order was given. The individual items in any order were served as and when all the items were ready, and the order was then considered closed. None of the items on the menu were prepared in advance in anticipation of future orders. 

On the first day, 3 groups of customers came in and ordered at 6.00 pm, 6.10 pm, and 6.13 pm. The first order was for a plate of Egg Tortillas, two plates of French Toast, and three plates of Egg Bhurji with French Fries. The second order was for a plate of French Toast and two plates of Egg Bhurji with French Fries. The third order was for a plate of Egg Tortilla and a plate of Egg Bhurji with French Fries. 

On the backdrop of the above information answer the questions given :

Question: 

A fourth customer comes in and orders two plates of French Toast at 6.24 pm. Suppose Moloy and Niloy had decided to process multiple orders at the same time, however strictly prioritising a first come first serve basis. For exactly how many minutes would one of the friends be idle from 6.00 pm till serving the last customer, assuming that the four customers were the only ones to have come in within the period being discussed ?

Option: 1

9

 


Option: 2

13


Option: 3

18


Option: 4

21


Directions for question:

Two friends Moloy and Niloy passed out from the Purulia Institute of Science and Technology with B.Tech degrees in Mechanical Engineering, but even after a year placement was hard to find. So they decided to take the challenge head-on, came down to Kolkata, rented a garage space on Park Street, and having an affinity towards making people enjoy good food, started their firm named 'B.Tech Bread-Omlette Wala'. 

They started with three items on the menu. One was the French Toast which could be prepared in 3 minutes. The second was the Egg Tortillas which took 15 minutes to prepare. Any one of Moloy and Niloy could prepare any one of them at a time. The third was the Egg Bhurji with French Fries. This however was prepared on an automated fryer which could prepare 3 servings at a time and took 5 minutes irrespective of the number of servings equal to or below 3. The fryer did not need anyone to attend to it, and the time to put in the raw ingredients could be neglected. So one could tend to the preparation of other items while the Egg Bhurji with French Fries were being prepared. 

They wanted to serve the orders as early as possible after the order was given. The individual items in any order were served as and when all the items were ready, and the order was then considered closed. None of the items on the menu were prepared in advance in anticipation of future orders. 

On the first day, 3 groups of customers came in and ordered at 6.00 pm, 6.10 pm, and 6.13 pm. The first order was for a plate of Egg Tortillas, two plates of French Toast, and three plates of Egg Bhurji with French Fries. The second order was for a plate of French Toast and two plates of Egg Bhurji with French Fries. The third order was for a plate of Egg Tortilla and a plate of Egg Bhurji with French Fries. 

On the backdrop of the above information answer the questions given :

Question: 

Had Niloy been absent on that day, and assuming that the next customer's order could only be attended to when the previous customer's order was closed, at what time would the fourth customer's order (refer to the previous question) be considered closed ?

Option: 1

6:38 pm

 


Option: 2

6:42 pm

 


Option: 3

6:47 pm


Option: 4

6:49 pm


Directions for question:

The bar-graph given below shows the foreign exchange reserves of Nepal (in million Rupees) from 2014 to 2021. Answer the following questions based on the graph :

Question:

What was the percentage increase (rounded to the nearest integer, if deemed necessary) in the foreign exchange reserves in 2020 over 2016 ?

Option: 1 None

Option: 2 None

Option: 3 None

Option: 4 None

Directions for question:

The Jadavpur University’s Prince Anwar Shah Road hostel consists of two large separate buildings, one for the ladies and the other for the gents, while having a common kitchen and dining hall. It is the hostel of the CS and the EEC department of engineering students of the university.

In recognition of the growing dissatisfaction and hence complaints among the inmates of the hostel regarding the menu served for dinner, the Dean of the engineering department, Dr Aparesh Sanyal, personally decided to investigate the matter. He set about collecting information about the preference of dinner among the inmates, separately from the gents and the ladies wing of the hostel.

Dr Sanyal was able to gather the following partial information :  

 

Hostel inmates

Menu preference for dinner

Total

Egg Meal

Fish Meal

Chicken Meal

Gents

   

20

 

Ladies

     

64

Total

 

60

   

 

The Warden of the hostel was consulted, who after investigation declared that the following facts were clear :

1. Forty percent of the hostel inmates were ladies

2. One-third of the gentlemen inmates preferred an egg meal for dinner

3. Half the hostel inmates preferred either fish meal or chicken meal

Question:

What proportion of the lady hostel inmates preferred a fish meal for dinner ?

 

 

Option: 1

0.25

 

 


Option: 2

0.50

 


Option: 3

0.75

 


Option: 4

1.00 


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