Success in the CAT exam depends heavily on targeted practice, particularly in the DILR section, which tests logical thinking and analytical skills. To perform well, candidates should focus on solving a wide range of CAT DILR 2025 practice questions, including charts, tables, puzzles, and reasoning sets. Regular practice with questions based on the latest exam pattern gives you an edge in CAT 2025.
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CAT 2025 DILR Section - Exam Overview
CAT DILR 2025 Practice Questions
CAT DILR 2025 Practice Questions PDF Link
Benefits of Solving CAT 2025 DILR Practice Questions
CAT DILR 2025 Topic-wise Weightage and Difficulty
CAT DILR 2025: Previous Year Trends and Analysis
Tips to Solve CAT Data Interpretation Practice Questions
Tips to Solve CAT Logical Reasoning Practice Questions
The CAT exam pattern 2025 of the DILR section underwent an unexpected change in 2024. Instead of 20 questions, in the CAT question paper 2024, the candidates were asked 22 questions, thereby increasing the total number of CAT questions from 66 to 68. On the CAT exam day, the candidates will be given 40 minutes to solve the CAT questions under the DILR section. The expected CAT DILR exam pattern for the CAT 2025 examination is provided below.
Aspect
Details
Total Questions
22
Types
MCQs and TITA (Type In The Answer)
Sectional time limit
40 minutes
Marking Scheme
+3 for the correct answer -1 for incorrect responses
No mark awarded or deducted for unattempted questions.
Sub-sectional question arrangements
Jumbled
CAT DILR 2025 Practice Questions
Solving a lot of CAT DILR questions is the most effective CAT 2025 preparation strategy for the DILR section. The candidates should solve as many CAT DILR practice questions as possible and this includes various CAT preparation resources such as CAT mock tests and CAT sample papers. A few of the solved CAT DILR practice questions are provided below for the reference of the candidates.
CAT DILR 2025 Practice Questions: Data Interpretation Section
1. Comprehension: Over the top (OTT) subscribers of a platform are segregated into three categories: i) Kid, ii) Elder, and iii) Others. Some of the subscribers used one app and the others used multiple apps to access the platform. The figure below shows the percentage of the total number of subscribers in 2023 and 2024 who belong to the ‘Kid’ and ‘Elder’ categories.
The following additional facts are known about the numbers of subscribers.
1. The total number of subscribers increased by 10% from 2023 to 2024. 2. In 2024, 12 of the subscribers from the 'Kid' category and 23 of the subscribers from the 'Elder' category subscribers use one app. 3. In 2023, the number of subscribers from the 'Kid' category who used multiple apps was the same as the number of subscribers from the 'Elder' category who used one app. 4. 10,000 subscribers from the 'Kid' category used one app, and 15,000 subscribers from the 'Elder' category used multiple apps in 2023.
Question: What could be the minimum percentage of subscribers who used multiple apps in 2024?
22.00%
16.5%
20.0%
10.0%
Solution
After reading the bar graphs, we can find the distribution as:
Take Clue 1, assume that the total number of subscribers will be $100x$ in 2023 and $110x$ in 2024.
This provides the division of subscribers as:
2023: $100x$ 2024: $110x ; \to$ further divided in Clue 2
Based on Clue 2, of the $55x$ subscribers in 2024:
$11x = \dfrac{1}{2} \times 22x$, and
$\dfrac{2}{3} \times 33x = 22x$ had utilised a single app.
Therefore, the total usage of a single app in 2024 $= 11x + 22x = 33x$.
Now with Clues 3 and 4:
By Clue 4:
Ten thousand out of $15x$ Kids used one app.
Of $20x$ Elders, $15000$ use multiple apps.
Clue 3:
Children multi-tasking with several applications $= 15x - 10000$ equal to Older adults using one app $= 20x - 15000$.
Equating these (as per Clue 3):
$15x - 10000 = 20x - 15000$
Solution: $5x = 5000$
It means $x = 1000$.
And, Clue 2 makes us know that, of the $55000$ kids and elders, $33000$ use one app, thus $22000$ use more than one app.
To minimize the total number of multiple app users, we can assume that all $55000$ "other" subscribers use only one app.
Therefore, the number of multiple app users $= 22000$.
2. Comprehension: Over the top (OTT) subscribers of a platform are segregated into three categories: i) Kid, ii) Elder, and iii) Others. Some of the subscribers used one app and the others used multiple apps to access the platform. The figure below shows the percentage of the total number of subscribers in 2023 and 2024 who belong to the ‘Kid’ and ‘Elder’ categories.
The following additional facts are known about the numbers of subscribers.
1. The total number of subscribers increased by 10% from 2023 to 2024. 2. In 2024, 12 of the subscribers from the 'Kid' category and 23 of the subscribers from the 'Elder' category subscribers use one app. 3. In 2023, the number of subscribers from the 'Kid' category who used multiple apps was the same as the number of subscribers from the 'Elder' category who used one app. 4. 10,000 subscribers from the 'Kid' category used one app, and 15,000 subscribers from the 'Elder' category used multiple apps in 2023.
Question: What was the percentage increase in the number of subscribers in the 'Elder' category from 2023 to 2024?
65%
50%
60%
40%
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After reading the bar graphs, we can find the distribution as:
Take Clue 1, assume that the total number of subscribers will be $100x$ in 2023 and $110x$ in 2024.
This provides the division of subscribers as:
2023: 100x
2024: 110x → further divided in Clue 2
Based on Clue 2, of the 55x subscribers in 2024:
11x=half of 22x, and
23 of 33x=22x had utilised a single app.
Therefore, the total usage of a single app in 2024 = 11x+22x=33x
Now with Clues 3 and 4:
By Clue 4:
Ten thousand out of 15x Kids used one app
Of 20x Elders, 15,000 use multiple apps
Clue 3:
Children multi-tasking with several applications = 15x−10000 equal to Older adults using one app = 20x−15000
Equating these (as per Clue 3):
15x−10000=20x−15000
Solution: 5x=5000
It means x=1000
In 2023, there were 20000 elders, and in 2024, there were 33000 elders
Thus, the percentage increase in the number of subscribers in the 'Elder' category from 2023 to 2024 = 33000−2000020000×100=65%
Hence, the first option is correct.
3. Comprehension: Over the top (OTT) subscribers of a platform are segregated into three categories: i) Kid, ii) Elder, and iii) Others. Some of the subscribers used one app and the others used multiple apps to access the platform. The figure below shows the percentage of the total number of subscribers in 2023 and 2024 who belong to the ‘Kid’ and ‘Elder’ categories.
The following additional facts are known about the numbers of subscribers.
1. The total number of subscribers increased by 10% from 2023 to 2024. 2. In 2024, 12 of the subscribers from the 'Kid' category and 23 of the subscribers from the 'Elder' category subscribers use one app. 3. In 2023, the number of subscribers from the 'Kid' category who used multiple apps was the same as the number of subscribers from the 'Elder' category who used one app. 4. 10,000 subscribers from the 'Kid' category used one app, and 15,000 subscribers from the 'Elder' category used multiple apps in 2023.
Question: What was the percentage increase in the number of subscribers in the 'Elder' category from 2023 to 2024?
65%
50%
60%
40%
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Comprehensive CAT prep guide with focused practice on Verbal Ability, Data Interpretation & Logical Reasoning, and Quantitative Aptitude.
After reading the bar graphs, we can find the distribution as:
Take Clue 1, assume that the total number of subscribers will be $100x$ in 2023 and $110x$ in 2024.
This provides the division of subscribers as:
2023: $100x$
2024: $110x ;\to$ further divided in Clue 2
Based on Clue 2, of the $55x$ subscribers in 2024:
$11x = \dfrac{1}{2} \times 22x$, and
$\dfrac{2}{3} \times 33x = 22x$ had utilised a single app.
Therefore, the total usage of a single app in 2024 $= 11x + 22x = 33x$.
Now with Clues 3 and 4:
By Clue 4:
Ten thousand out of $15x$ Kids used one app.
Of $20x$ Elders, $15000$ use multiple apps.
Clue 3:
Children multi-tasking with several applications $= 15x - 10000$ equal to Older adults using one app $= 20x - 15000$.
Equating these (as per Clue 3):
$15x - 10000 = 20x - 15000$
Solution: $5x = 5000$
It means $x = 1000$.
In 2023, there were $20000$ elders, and in 2024, there were $33000$ elders.
Thus, the percentage increase in the number of subscribers in the 'Elder' category from 2023 to 2024 $= \dfrac{33000 - 20000}{20000} \times 100 = 65%$.
Hence, the first option is correct.
4. Comprehension: The table given below shows the amount, in grams, of carbohydrate, protein, fat and all other nutrients, per 100 grams of nutrients in seven foodgrains. The first column shows the foodgrain category and the second column its codename. The table has some missing values.
Food grain Category
Condename of the food grain
Compositions per hundred grams of nutrients in the food grain
Carbohydrates
Protein
Fats
Other Nutrients
Cereal
C1
0
12
C2
3
10
Millets
M1
62
10
M2
7
16
M3
56
12
Pseudo-cereal
P1
66
10
P2
14
8
The following additional facts are known.
1. Both the pseudo-cereals had higher amounts of carbohydrate as well as higher amounts of protein than any millet. 2. Both the cereals had higher amounts of carbohydrate than any pseudo-cereal. 3. All the missing values of carbohydrate amounts (in grams) for all the foodgrains are nonzero multiples of 5. 4. All the missing values of protein, fat and other nutrients amounts (in grams) for all the foodgrains are non-zero multiples of 4. 5. P1 contains double the amount of protein that M3 contains.
Question: What is the median of the number of grams of protein in 100 grams of nutrients among these food grains?
Solution
The initial clue in the puzzle is that the rows have to add up to 100 grams.
From Clue 3, we know that all missing values in the Carbs column must be multiples of 5, and from Clue 4, all missing values in the other three columns (Proteins, Fats, and Others) must be multiples of 4.
Next, take Clue 1, which says that the amount of Carbs in C1 and C2 should be higher than in any pseudo cereal. Because P1 is a pseudo cereal, and it contains 66g of Carbs, it means that C1 and C2 should contain over 66g of Carbs.
Attempt to fill in the values of C1: The possible Carb values (multiples of 5 greater than 66) are: 70, 75, 80, 85, 90, 95
We are told that 12g of the total 100g is already occupied by 'Other nutrients'. Therefore, the remaining 88g has to be shared by Carbs, Proteins and Fats.
Suppose we take:
90g: Carbs 90+12=102>total, remove
95g: Carbs 95+12=107>total, remove
85g: Carbs 85+12=97→leaves 3g of Protein, 3 is not a multiple of 4→eliminate
75g: Carbs 75+12=87→leaves 13g of Protein, 13 is not a multiple of 4→eliminate
80g: Carbs 80+12=92→leaves 8g for Protein, 8 is a multiple of 4
We’re told that 13g is already allocated (presumably to Fats or Others).
Therefore, out of 100g, 100−13=87g is left over to be divided between Carbs and Protein.
Possible Carbs values to be tested:
90g: 90+13=103>total, remove
95g→total exceeds, discard
85g: 85+13=98→leaves 2g Protein, 2 is not a multiple of 4→eliminate
80g: 80+13=93→leaves 7g, 7 is not a multiple of 4→discard
70g: 70+13=83→leaves 17g, 17 is not a multiple of 4→discard
75g Carbs: 75+13=88→leaves 12g, 12 is a multiple of 4
→ C2 therefore contains: 75g Carbs, 12g Protein, 13g Other
With Clues 1 and 2, we can conclude that the Carbs in P2 should be over 62 and below 75. The only values that are valid are 65 and 70.
If Carbs = 65g, then Protein = 100−65−14−8=13g→ Invalid (not a multiple of 4)
If Carbs = 70g, then Protein = 100−70−14−8=8g
Clue 1: Protein in M2 should be lower than any pseudo-cereal, which is 14g at the maximum.
So, Protein in M2 (and M3) can be: 12,8,4,0
Fats = 7g, Others = 16g given:
Carbs + Protein = 100−7−16=77g
Valid only combination: Protein = 12g, Carbs = 65g
The protein in M3 can be 0,4,8, or 12 (Clue 4).
From Clue 5, we know that P1's protein is double that of M3, so possible values for P1 protein are 0,8,16, or 24.
However, Clue 1 also states that P1's protein must be more than that of M1 and M2, so 0 and 8 are not valid.
This reduces to 16 and 24.
The protein and fats in P1 should now total:
100−66 (carbs)−10 (others)=24g
If protein = 24g, then fats = 0g, which violates Clue 4 (fats must be a non-zero multiple of 4) → Invalid
If protein = 16g, then fats = 8g
So, P1 has 16g protein and 8g fats, meaning M3 must have 8g protein (half of P1's), and with known carbs and fats, M3's others = 24g.
The proteins in the food grains, when arranged in ascending order, become: 8, 8, 10, 12, 12, 14, 16, giving the median as 12.
Hence, 12 is the correct answer.
5. Comprehension: The table given below shows the amount, in grams, of carbohydrate, protein, fat and all other nutrients, per 100 grams of nutrients in seven foodgrains. The first column shows the foodgrain category and the second column its codename. The table has some missing values.
Food grain Category
Condename of the food grain
Compositions per hundred grams of nutrients in the food grain
Carbohydrates
Protein
Fats
Other Nutrients
Cereal
C1
0
12
C2
3
10
Millets
M1
62
10
M2
7
16
M3
56
12
Pseudo-cereal
P1
66
10
P2
14
8
The following additional facts are known.
1. Both the pseudo-cereals had higher amounts of carbohydrate as well as higher amounts of protein than any millet. 2. Both the cereals had higher amounts of carbohydrate than any pseudo-cereal. 3. All the missing values of carbohydrate amounts (in grams) for all the foodgrains are nonzero multiples of 5. 4. All the missing values of protein, fat and other nutrients amounts (in grams) for all the foodgrains are non-zero multiples of 4. 5. P1 contains double the amount of protein that M3 contains.
Question: How many grams of other nutrients were there in 100 grams of nutrients in M3?
Solution
The initial clue in the puzzle is that the rows have to add up to 100 grams.
From Clue 3, we know that all missing values in the Carbs column must be multiples of 5, and from Clue 4, all missing values in the other three columns (Proteins, Fats, and Others) must be multiples of 4.
Next, take Clue 1, which says that the amount of Carbs in C1 and C2 should be higher than in any pseudo cereal. Because P1 is a pseudo cereal, and it contains 66g of Carbs, it means that C1 and C2 should contain over 66g of Carbs.
Attempt to fill in the values of C1: The possible Carb values (multiples of 5 greater than 66) are: 70, 75, 80, 85, 90, 95
We are told that 12g of the total 100g is already occupied by 'Other nutrients'. Therefore, the remaining 88g has to be shared by Carbs, Proteins and Fats.
Suppose we take:
90g: Carbs90+12=102>total, remove
95g: Carbs 95+12=107>total, remove
85g: Carbs 85+12=97→leaves 3g of Protein, 3 is not a multiple of 4→eliminate
75g: Carbs 75+12=87→leaves 13g of Protein, 13 is not a multiple of 4→eliminate
80g: Carbs 80+12=92→leaves 8g for Protein, 8 is a multiple of 4
We’re told that 13g is already allocated (presumably to Fats or Others).
Therefore, out of 100g, 100−13=87g is left over to be divided between Carbs and Protein.
Possible Carbs values to be tested:
90g: 90+13=103>total, remove
95g→total exceeds, discard
85g: 85+13=98→leaves 2g Protein, 2 is not a multiple of 4→eliminate
80g: 80+13=93, 7g remaining. 93 is not a multiple of 4; therefore, discard
70g: 70+13=83, leaves 17g, 17 is not a multiple of 4; discard
75g Carbs: 75+13=88→leaves 12g, 12 is a multiple of 4
→ C2 therefore contains: 75g Carbs, 12g Protein, 13g Other
With Clues 1 and 2, we can conclude that the Carbs in P2 should be over 62 and below 75. The only values that are valid are 65 and 70.
If Carbs = 65g, then Protein = 100−65−14−8=13g→ Invalid (not a multiple of 4)
If Carbs = 70g, then Protein = 100−70−14−8=8g
Clue 1: Protein in M2 should be lower than any pseudo-cereal, which is 14g at the maximum.
So, Protein in M2 (and M3) can be: 12,8,4,0
Fats = 7g, Others = 16g given:
Carbs + Protein = 100−7−16=77g
Valid only combination: Protein = 12g, Carbs = 65g
The protein in M3 can be 0,4,8, or 12 (Clue 4).
From Clue 5, we know that P1's protein is double that of M3, so possible values for P1 protein are 0,8,16, or 24.
However, Clue 1 also states that P1's protein must be more than that of M1 and M2, so 0 and 8 are not valid.
This reduces to 16 and 24.
The protein and fats in P1 should now total:
100−66 (carbs)−10 (others)=24g
If protein = 24g, then fats = 0g, which violates Clue 4 (fats must be a non-zero multiple of 4) → Invalid
If protein = 16g, then fats = 8g
So, P1 has 16g protein and 8g fats, meaning M3 must have 8g protein (half of P1's), and with known carbs and fats, M3 others = 24g.
Therefore, we can see that there were 24 grams of other nutrients in M3.
Hence, 24 is the correct answer.
6. Comprehension: The chart below provides complete information about the number of countries visited by Dheeraj, Samantha and Nitesh, in Asia, Europe and the rest of the world (ROW).
The following additional facts are known about the countries visited by them. 1. 32 countries were visited by at least one of them. 2. USA (in ROW) is the only country that was visited by all three of them. 3. China (in Asia) is the only country that was visited by both Dheeraj and Nitesh, but not by Samantha. 4. France (in Europe) is the only country outside Asia, which was visited by both Dheeraj and Samantha, but not by Nitesh. 5. Half of the countries visited by both Samantha and Nitesh are in Europe.
Question: How many countries in Europe were visited by exactly one of Dheeraj, Samantha and Nitesh?
12
14
10
5
Solution
Converting the data in tabular form we get:
Asia
Europe
ROW
Dheeraj
3
7
1
Samantha
0
9
4
Nitesh
1
6
12
To find the answer to this, let us draw Venn diagrams of Asia, Europe and the Rest of the World (ROW) depending on the given conditions.
It is given that half of the countries visited by Samantha and Nitesh are in Europe.
Note that those visited by the two of them in Asia is 0, this means the remaining half is in the rest of the world, and let x be the countries visited by Samantha and Nitesh only.
Therefore, the countries visited by Samantha and Nitesh are in Europe be: (x+1) [as one country, USA, is visited by all three in ROW].
Using this, we can deduce:
In ROW, the number of countries visited only by Samantha is (3−x), and those visited only by Nitesh is (11−x).
In Europe, the number of countries visited only by Samantha is (7−x), and those visited only by Nitesh is (5−x).
It is said that $32$ countries were visited by at least one of them.
$\Rightarrow (15 - x) + 3 + (20 - x) = 32$
$\Rightarrow x = 3$
Replacing the value of x, we get the following Venn diagrams:
Therefore, the number of countries in Europe that were visited by exactly one of Dheeraj, Samantha, and Nitesh =6+2+4=12.
Hence, the first option is correct.
7. Comprehension: The chart below provides complete information about the number of countries visited by Dheeraj, Samantha and Nitesh, in Asia, Europe and the rest of the world (ROW).
The following additional facts are known about the countries visited by them. 1. 32 countries were visited by at least one of them. 2. USA (in ROW) is the only country that was visited by all three of them. 3. China (in Asia) is the only country that was visited by both Dheeraj and Nitesh, but not by Samantha. 4. France (in Europe) is the only country outside Asia, which was visited by both Dheeraj and Samantha, but not by Nitesh. 5. Half of the countries visited by both Samantha and Nitesh are in Europe.
Question: How many countries in the ROW were visited by both Nitesh and Samantha?
4
6
7
9
Solution
Converting the data in tabular form we get:
Asia
Europe
ROW
Dheeraj
3
7
1
Samantha
0
9
4
Nitesh
1
6
12
To find the answer to this, let us draw Venn diagrams of Asia, Europe and the Rest of the World (ROW) depending on the given conditions.
It is given that half of the countries visited by Samantha and Nitesh are in Europe.
Note that those visited by the two of them in Asia is 0, this means the remaining half is in the rest of the world, and let x be the countries visited by Samantha and Nitesh only.
Therefore, the countries visited by Samantha and Nitesh are in Europe be: (x+1) [as one country, USA, is visited by all three in ROW].
Using this, we can deduce:
In ROW, the number of countries visited only by Samantha is (3−x), and those visited only by Nitesh is (11−x).
In Europe, the number of countries visited only by Samantha is (7−x), and those visited only by Nitesh is (5−x).
It is said that 32 countries were visited by at least one of them.
$\Rightarrow (15-x) + 3 + (20-x) = 32$
$\Rightarrow x = 3$
Replacing the value of x, we get the following Venn diagrams:
Therefore, four countries in the Rest of the world were visited by both Nitesh and Samantha.
8. Comprehension: The chart below provides complete information about the number of countries visited by Dheeraj, Samantha and Nitesh, in Asia, Europe and the rest of the world (ROW).
The following additional facts are known about the countries visited by them. 1. 32 countries were visited by at least one of them. 2. USA (in ROW) is the only country that was visited by all three of them. 3. China (in Asia) is the only country that was visited by both Dheeraj and Nitesh, but not by Samantha. 4. France (in Europe) is the only country outside Asia, which was visited by both Dheeraj and Samantha, but not by Nitesh. 5. Half of the countries visited by both Samantha and Nitesh are in Europe.
Question: How many countries in Europe were visited only by Nitesh?
2
3
4
5
Solution
Converting the data in tabular form we get:
Asia
Europe
ROW
Dheeraj
3
7
1
Samantha
0
9
4
Nitesh
1
6
12
To find the answer to this, let us draw Venn diagrams of Asia, Europe and the Rest of the World (ROW) depending on the given conditions.
It is given that half of the countries visited by Samantha and Nitesh are in Europe.
Note that those visited by the two of them in Asia is 0, this means the remaining half is in the rest of the world, and let x be the countries visited by Samantha and Nitesh only.
Therefore, the countries visited by Samantha and Nitesh in Europe are: (x+1)
[as one country, USA, is visited by all three in ROW].
Using this, we can deduce:
In ROW, the number of countries visited only by Samantha is (3−x), and those visited only by Nitesh is (11−x).
In Europe, the number of countries visited only by Samantha is (7−x), and those visited only by Nitesh is (5−x).
It is said that 32 countries were visited by at least one of them.
$\Rightarrow (15-x) + 3 + (20-x) = 32$
$\Rightarrow x = 3$
Replacing the value of x, we get the following Venn diagrams:
Therefore, exactly two countries in Europe were visited only by Nitesh.
9. Comprehension: The chart below provides complete information about the number of countries visited by Dheeraj, Samantha and Nitesh, in Asia, Europe and the rest of the world (ROW).
The following additional facts are known about the countries visited by them. 1. 32 countries were visited by at least one of them. 2. USA (in ROW) is the only country that was visited by all three of them. 3. China (in Asia) is the only country that was visited by both Dheeraj and Nitesh, but not by Samantha. 4. France (in Europe) is the only country outside Asia, which was visited by both Dheeraj and Samantha, but not by Nitesh. 5. Half of the countries visited by both Samantha and Nitesh are in Europe.
Question: How many countries in Asia were visited by at least one of Dheeraj, Samantha and Nitesh?
3
4
5
6
Solution
Converting the data in tabular form, we get:
Asia
Europe
ROW
Dheeraj
3
7
1
Samantha
0
9
4
Nitesh
1
6
12
To find the answer to this, let us draw Venn diagrams of Asia, Europe and the Rest of the World (ROW) depending on the given conditions.
It is given that half of the countries visited by Samantha and Nitesh are in Europe.
Note that those visited by the two of them in Asia is 0, this means the remaining half is in the rest of the world, and let x be the countries visited by Samantha and Nitesh only.
Therefore, the countries visited by Samantha and Nitesh are in Europe be: (x+1) [as one country, USA, is visited by all three in ROW].
Using this, we can deduce:
In ROW, the number of countries visited only by Samantha is (3−x), and those visited only by Nitesh is (11−x).
In Europe, the number of countries visited only by Samantha is (7−x), and those visited only by Nitesh is (5−x).
It is said that 32 countries were visited by at least one of them.
$\Rightarrow (15-x) + 3 + (20-x) = 32$
$\Rightarrow x = 3$
Replacing the value of x, we get the following Venn diagrams:
Therefore, three countries in Asia were visited by at least one of them.
CAT DILR 2025 Practice Questions: Logical Reasoning Section
1. Comprehension: The figure below shows a network with three parallel roads represented by horizontal lines R-A, R-B, and R-C and another three parallel roads represented by vertical lines V1, V2, and V3. The figure also shows the distance (in km ) between two adjacent intersections. Six ATMs are placed at six of the nine road intersections. Each ATM has a distinct integer cash requirement (in Rs. Lakhs), and the numbers at the end of each line in the figure indicate the total cash requirements of all ATMs placed on the corresponding road. For example, the total cash requirement of the ATM(s) placed on road R-A is Rs. 22 Lakhs.
The following additional information is known. 1. The ATMs with the minimum and maximum cash requirements of Rs. 7 Lakhs and Rs. 15 Lakhs are placed on the same road. 2. The road distance between the ATM with the second highest cash requirement and the ATM located at the intersection of R-C and V3 is 12 km .
Question: What is the number of ATMs whose locations and cash requirements can both be uniquely determined?
3
4
5
6
Solution
It is indicated to us that, of the 9 intersections in the figure, 6 contain ATMs. 3 of these intersections are vacant. It is also given to us that both the highest capacity and the lowest capacity ATMs are on the same road, highest capacity of 15L and the lowest of 7L. This information not only provides us with hints of the location of these two ATMs, but also, we now have the upper and lower limits of cash in the six ATMs with different cash. The next set of information which is provided is that the road distance between the ATM having the second highest cash requirement and the ATM at the intersection of R-C and V3 is 12 km. Since we can only traverse the roads, from (RC, V3), we have to either traverse the 5km road or the 7km road. It can only sum up to 12 in one way, 5+7. That means, the ATM with the second highest capacity is at (RB, V2). Now, let us start arranging the ATM's. We are informed that 15 and 7 are on the same road. We are provided with the total capacities on the roads; therefore, we have to find which roads have a capacity greater equal to 22. The only two choices are R-A or V3. Looking at V3, we see that 15L ATM cannot come at (RB, V3) or (RC, V3) since the RB and RC capacity is 20, and the minimum ATM limit is 7L, if a 15L ATM is on a road with total capacity 20L, this is a situation that is not possible since there cannot be an ATM with 5L capacity.
Case 1: 15L ATM is on the intersection (RA, V3).
In order to get a cumulative sum of 26L in column V3, there is a need to have an ATM containing 11L of cash at any of the intersections. This is because placing two ATMs in V3 is not viable, the minimum ATM capacity is 7L, and using two such machines would exceed 26L (since 7L + 7L = 14L, requiring a third ATM with 12L, which is not allowed).
The 11L ATM can only be placed at either (RB, V3) or (RC, V3).
Suppose we situate the 11L ATM in one of these intersections, then the second largest ATM, namely 9L, needs to be placed so that it does not break any row or column totals.
Where could 9L place?:
It cannot be placed at (RC, V1) or (RB, V1), because V1 totals 15L, and placing a 9L ATM there would require a 6L ATM to complete the sum, which is invalid since 6L is not an available capacity.
It also cannot be at (RB, V2), because we’ve already placed the 11L ATM, and V2 cannot accommodate both the highest (11L) and the second-highest (9L) values, as this would unbalance the totals and available combinations.
This means the only feasible position for the 9L ATM is at (RC, V2).
Through this placement, it is possible to logically infer and fill in the remaining values using the constraints of the row and column totals. This brings us to the final and coherent ATM configuration of Case-1.
Case 2: When the 15L ATM is placed at (RA, V1).
With 15L at (RA, V1), no other ATM can be placed in column V1, as the column total is already fully accounted for.
Now, the 7L ATM, which must be placed somewhere in row RA, cannot go to (RA, V2). The reason is that the sum of V2 is 21L, and to put 7L ATM at that point would need:
Another 7L ATM (which isn’t allowed, as ATM values are unique), or
A 14L ATM (which exceeds the row total limit of 20L for both RB and RC).
Hence, the 7L ATM must be placed in (RA, V3).
That leaves 19L to fill in column V3 because V3 contains a total of 26L, and we have already put 7L. A single ATM of 19L is not possible (not among the allowed capacities), so two additional ATMs must collectively sum to 19L.
After trying out the possible combinations and abiding by all the row and column restrictions, we can conclude about the location of the remaining ATMs and get the valid solution of Case 2.
Using the two cases, we can answer the given questions. ATMs that can be uniquely determined are the ATMs with cash 9L, 11L and 12L. Hence, the answer is 3.
2. Comprehension: The figure below shows a network with three parallel roads represented by horizontal lines R-A, R-B, and R-C and another three parallel roads represented by vertical lines V1, V2, and V3. The figure also shows the distance (in km ) between two adjacent intersections. Six ATMs are placed at six of the nine road intersections. Each ATM has a distinct integer cash requirement (in Rs. Lakhs), and the numbers at the end of each line in the figure indicate the total cash requirements of all ATMs placed on the corresponding road. For example, the total cash requirement of the ATM(s) placed on road R-A is Rs. 22 Lakhs.
The following additional information is known. 1. The ATMs with the minimum and maximum cash requirements of Rs. 7 Lakhs and Rs. 15 Lakhs are placed on the same road. 2. The road distance between the ATM with the second highest cash requirement and the ATM located at the intersection of R-C and V3 is 12 km .
Question: What can be best said about the road distance (in km) between the ATMs having the second highest and the second lowest cash requirements?
7 km
4 km
Either 4 km or 7 km
5 km
Solution
The network consists of three horizontal roads R-A, R-B, R-C and three vertical roads V1, V2, V3. The intersections form a 3×3 grid, with distances given between adjacent intersections.
Six ATMs are placed at six of the nine intersections. Let the cash requirements of the six ATMs be distinct integers in Rs. Lakhs. The total cash requirement of ATMs on each road is given. For example, on R-A, the total cash requirement = 22 Lakhs.
Given information:
1. The minimum and maximum cash requirements are Rs. 7 Lakhs and Rs. 15 Lakhs, placed on the same road.
2. The road distance between the ATM with the second highest cash requirement and the ATM at intersection (R-C,V3) is 12 km.
Identify possible locations of minimum and maximum ATMs
Let the road containing both minimum (7 Lakhs) and maximum (15 Lakhs) ATMs be R-B.
Determine possible distances between second highest and second lowest ATMs
Let the second highest cash requirement = 14 Lakhs, and the second lowest = 8 Lakhs.
The road distance between 14 Lakhs ATM and ATM at (R-C,V3) = 12 km. Compute possible distances between second highest and second lowest ATMs
Considering the grid layout and distances between intersections, the second highest and second lowest ATMs can be either 4 km or 7 km apart.
The road distance between the ATMs with the second highest and second lowest cash requirements = Either 4 km or 7 km.
3. Comprehension: Eight gymnastics players numbered 1 through 8 underwent a training camp where they were coached by three coaches - Xena, Yuki, and Zara. Each coach trained at least two players. Yuki trained only even numbered players, while Zara trained only odd numbered players. After the camp, the coaches evaluated the players and gave integer ratings to the respective players trained by them on a scale of 1 to 7 , with 1 being the lowest rating and 7 the highest.
The following additional information is known. 1. Xena trained more players than Yuki. 2. Player-1 and Player-4 were trained by the same coach, while the coaches who trained Player-2, Player-3 and Player-5 were all different. 3. Player-5 and Player-7 were trained by the same coach and got the same rating. All other players got a unique rating. 4. The average of the ratings of all the players was 4. 5. Player-2 got the highest rating. 6. The average of the ratings of the players trained by Yuki was twice that of the players trained by Xena and two more than that of the players trained by Zara. 7. Player-4's rating was double of Player-8's and less than Player-5's.
Question: For how many players the ratings can be determined with certainty?
6
7
8
9
From conditions 3 and 4, only two players got the same ratings. Thus, let K be the repetitive number, then:
(1+2+3+4+5+6+7+K)/8=4
It means K = 4
Thus, players 5 and 7 got the same rating. As Xena trained more players than Yuki. So, there are two possibilities, which are as follows:
Trainer
Possibility 1
Possibility 2
Average
Xena
3
4
X
Yuki
2
2
2X
Zara
3
2
2X - 2
Possibility 1, X = 3813, (Not possible)
Possibility 2, X = 3, (Possible)
Trainer
Number of players trained
Average Scores
Total Scores
Xena
4
3
12
Yuki
2
6
12
Zara
2
4
8
Step 2:
From condition 5, player 2 got the rating of 7. Also, player 4 got the rating of 2, and player 8 got the rating of 1.
So, we get:
Player
Rating
Trained by
1
2
7
3
4
2
5
4
6
7
4
8
1
Yuki has 2 players, and their total score is 12. The only available combination that works is 7 + 5. Because player-2 got a score of 7, the other score can only be that of player-6, that is 5. This is also consistent with the fact that the only even-numbered player left is player-6, and Yuki trained only even-numbered players. Therefore, Yuki trains player-2 and player-6.
The overall score of Zara is 8. The correct combinations used in 8 are 2+6 and 4+4. The point of 2 is player 4, but Zara trained only those players who have an odd number; therefore, it is not possible. The only valid move is 4 + 4, which can be given to player-5 and player-7, both belonging to odd-numbered. Therefore, Zara has to be above player-5 and player-7.
Thus, the table of the players and their trainers is as follows:
Player
Rating
Trained by
1
3/6
Xena
2
7
Yuki
3
6/3
Xena
4
2
Xena
5
4
Zara
6
5
Yuki
7
4
Zara
8
1
Xena
Thus, for 6 players, the ratings can be determined with certainty.
Hence, 6 is the correct answer.
12. Comprehension: Eight gymnastics players numbered 1 through 8 underwent a training camp where they were coached by three coaches - Xena, Yuki, and Zara. Each coach trained at least two players. Yuki trained only even numbered players, while Zara trained only odd numbered players. After the camp, the coaches evaluated the players and gave integer ratings to the respective players trained by them on a scale of 1 to 7 , with 1 being the lowest rating and 7 the highest.
The following additional information is known. 1. Xena trained more players than Yuki. 2. Player-1 and Player-4 were trained by the same coach, while the coaches who trained Player-2, Player-3 and Player-5 were all different. 3. Player-5 and Player-7 were trained by the same coach and got the same rating. All other players got a unique rating. 4. The average of the ratings of all the players was 4. 5. Player-2 got the highest rating. 6. The average of the ratings of the players trained by Yuki was twice that of the players trained by Xena and two more than that of the players trained by Zara. 7. Player-4's rating was double of Player-8's and less than Player-5's.
Question: What was the rating of Player-6?
3
4
5
8
Solution
From conditions 3 and 4, only two players got the same ratings. Thus, let K be the repetitive number, then:
(1+2+3+4+5+6+7+K)/8=4
It means K = 4
Thus, players 5 and 7 got the same rating. As Xena trained more players than Yuki. So, there are two possibilities, which are as follows:
Possibility 1, X = 3813, (Not possible)
Trainer
Possibility 1
Possibility 2
Average
Xena
3
4
X
Yuki
2
2
2X
Zara
3
2
2X - 2
Possibility 2, X = 3, (Possible)
Trainer
Number of players trained
Average Scores
Total Scores
Xena
4
3
12
Yuki
2
6
12
Zara
2
4
8
Step 2:
From condition 5, player 2 got the rating of 7. Also, player 4 got the rating of 2, and player 8 got the rating of 1.
So, we get:
Player
Rating
Trained by
1
2
7
3
4
2
5
4
6
7
4
8
1
Yuki has 2 players, and their total score is 12. The only available combination that works is 7 + 5. Because player-2 got a score of 7, the other score can only be that of player-6, that is 5. This is also consistent with the fact that the only even-numbered player left is player-6, and Yuki trained only even-numbered players. Therefore, Yuki trains player-2 and player-6.
The overall score of Zara is 8. The correct combinations used in 8 are 2+6 and 4+4. The point of 2 is player 4, but Zara trained only those players who have an odd number; therefore, it is not possible. The only valid move is 4 + 4, which can be given to player-5 and player-7, both belonging to odd-numbered. Therefore, Zara has to be above player-5 and player-7.
Thus, the table of the players and their trainers is as follows:
Player
Rating
Trained by
1
3/6
Xena
2
7
Yuki
3
6/3
Xena
4
2
Xena
5
4
Zara
6
5
Yuki
7
4
Zara
8
1
Xena
Thus, the rating of player 6 is 5.
Hence, 5 is the correct answer.
CAT DILR 2025 Practice Questions PDF Link
Considering the vastness of the CAT Data Interpretation and Logical Reasoning section, it is necessary for the candidates to shortlist the most important CAT DILR topics and solve a lot of CAT practice questions under those topics. Careers360 has shortlisted a set of topics under which the CAT DILR questions are repeatedly asked in the previous CAT examinations. The candidates are encouraged to download the CAT practice questions DILR of the CAT 2025 important topics using the links given below.
Benefits of Solving CAT 2025 DILR Practice Questions
CAT Logical Reasoning is all about structured thinking and eliminating unnecessary steps. Candidates often find this section time-consuming, but with the right approach, you can turn it into a scoring area. While practising CAT 2025 LR Practice Questions, focus on accuracy before speed, and develop a systematic problem-solving style instead of random trial-and-error.
Understand How Questions Work
Practising CAT 2025 DILR questions helps you see how each set is built. You start understanding the logic behind puzzles, arrangements, tables, and caselets. This makes it easier to know where to start and what steps to follow.
Spot Patterns Quickly
By solving many questions, you begin to notice patterns in how sets are made. You can quickly identify similar types during the exam, which saves time and reduces confusion.
Reduce Mistakes in Sets
A single error can affect all questions in a DILR set. Regular practice trains you to check your work carefully and avoid small mistakes that cost marks.
Learn Which Sets to Attempt
Not every set is worth your time. Practising helps you decide which sets you can solve fast and which ones to skip, so you get more marks in less time.
Sharpen Reasoning and Calculation
Every practice question requires arranging data and thinking clearly. Doing this repeatedly improves both your logical thinking and calculation speed.
CAT DILR 2025 Topic-wise Weightage and Difficulty
Understanding the topic-wise weightage and difficulty of the CAT DILR 2025 section helps streamline your preparation. Based on past trends, Data Interpretation and Logical Reasoning carry equal importance. Use CAT 2025 DILR practice questions and follow targeted CAT 2025 DILR preparation tips to improve accuracy and speed across varying difficulty levels.
Topic
CAT 2025 Weightage
CAT Difficulty Level
Tables and Charts
1–2 Sets
Moderate to Difficult
Bar Graphs & Line Graphs
1 Set
Moderate
Pie Charts
0–1 Set
Moderate
Caselets (Data-based Scenarios)
1–2 Sets
Moderate to Difficult
Games and Tournaments
1 Set
Difficult
Puzzles and Arrangements
1–2 Sets
Moderate to Difficult
Binary Logic / Team Formation
0–1 Set
Moderate
Networks and Routes
0–1 Set
Difficult
Venn Diagrams
0–1 Set
Easy to Moderate
CAT DILR 2025: Previous Year Trends and Analysis
Analysing previous year CAT DILR papers helps you understand the changing patterns in topic weightage, difficulty level, and question types. Candidates must have an understanding of the total questions they have to attempt to score CAT 99 percentile or starting your CAT self study, reviewing trends from CAT 2024 and earlier helps you fine-tune your CAT 2025 DILR preparation strategy. Practise with CAT 2025 DILR practice questions aligned to the latest CAT syllabus for maximum impact.
Year
Total DILR Sets
Easy Sets
Moderate Sets
Difficult Sets
Key Topics Appeared
2024
4 Sets (20 Qs)
1
2
1
Games & Tournaments, Bar Graphs, Puzzles, Venn Diagrams
2023
4 Sets (20 Qs)
1
2
1
Seating Arrangement, Caselets, Pie Charts, Logical Conditions
2022
4 Sets (20 Qs)
0
2
2
DI on Profit & Loss, Puzzles, Matrix Arrangement
2021
4 Sets (20 Qs)
1
1
2
Venn Diagrams, Charts, Network Flow
2020
4 Sets (24 Qs)
1
2
1
Logical Reasoning, Grouping, Table DI
Tips to Solve CAT Data Interpretation Practice Questions
Mastering DILR requires more than just calculation speed, it demands pattern recognition, logical structuring, and time optimisation. Regularly working on CAT 2025 DILR Practice Questions builds these skills by exposing you to diverse data sets, from tables and charts to complex caselets as prescribed in the CAT DILR Syllabus 2025. The key is to approach them with a strategy that combines smart selection, efficient solving, and accuracy checks.
1. Analyse Data Before Calculating
When solving CAT 2025 DILR Practice Questions, spend the first 30–40 seconds scanning the entire set. Identify the format (tables, graphs, caselets) and relationships among variables before attempting calculations. This helps in avoiding wasted effort on unnecessary data points.
2. Prioritise Manageable Sets
In CAT 2025 DILR Practice Questions, not every set is equally solvable within the time. Learn to quickly reject overly complex or calculation-heavy sets. This directly impacts percentile scores, as attempting fewer but high-accuracy sets often yields better results than brute-force solving.
3. Use Approximation and Ratios
Many CAT 2025 DILR Practice Questions can be cracked faster by using approximations, ratios, or percentage changes rather than detailed calculations. This reduces arithmetic load and saves up to 2–3 minutes per set, a crucial advantage in a 40-minute section.
4. Build a Step-Wise Framework
For structured solving of CAT 2025 DILR Practice Questions, create a framework. Extract data → organise into a table/grid → identify patterns → solve step by step. Writing neatly reduces errors and improves recall under time pressure.
5. Review Previous Year Patterns
Aspirants who practice past CAT 2025 DILR Practice Questions notice recurring logic types, arrangements, team distributions, and percentage comparisons. Recognising these patterns allows faster mapping of new problems to familiar templates.
Tips to Solve CAT Logical Reasoning Practice Questions
CAT Logical Reasoning is all about structured thinking and eliminating unnecessary steps. Candidates often find this section time-consuming, but with the right approach, you can turn it into a scoring area. While practising CAT 2025 LR Practice Questions, focus on accuracy before speed, and develop a systematic problem-solving style instead of random trial-and-error.
Break down the problem structure
Every LR set hides patterns within conditions. When you attempt CAT 2025 LR Practice Questions, start by simplifying the data into tables, grids, or diagrams. This helps you see relationships clearly instead of juggling information mentally.
Learn to eliminate impossible cases quickly
The exam rewards those who can identify dead-ends early. While working on CAT 2025 LR Practice Questions, strike out inconsistent scenarios rather than pursuing them. This saves 30–40% of time per set.
Prioritise sets based on solvability
Not all LR sets carry equal difficulty. In CAT 2025 LR Practice Questions, practice identifying which sets are calculation-heavy versus logic-heavy. Attempt solvable sets first to maximise your percentile.
Track time per set, not per question
LR sections are designed around sets, not individual questions. While solving CAT 2025 LR Practice Questions, measure how long you take to complete a set. Ideally, aim for 8–10 minutes on medium-level sets during practice.
Reverse-engineer past CAT papers
The best way to master LR is to work backwards. While analysing CAT 2025 LR Practice Questions from past years, check the official solutions and note how the first step simplifies the set. Often, the approach matters more than the answer.
Short Tricks to Ace Difficult CAT DILR Questions
Difficult CAT DILR questions can seem time-consuming, but using the right approach makes them manageable. With practice, you can quickly identify patterns, eliminate unnecessary steps, and solve sets efficiently. These short tricks save time, reduce errors, and help you attempt the right questions for a higher score.
Trick 1: Analyse Before Solving
Before jumping into calculations, read the entire set carefully. Identify what is asked, note key data points, and spot constraints. A quick analysis prevents wasted steps and avoids mistakes that come from rushing.
Trick 2: Break Sets into Small Parts
Divide complex sets into smaller, manageable sections. Solve one part at a time instead of trying to tackle the entire set at once. This keeps your work organized and reduces confusion.
Trick 3: Use Elimination
In multiple-choice or arrangement-based questions, eliminate clearly impossible options first. Narrowing choices increases accuracy and speeds up decision-making.
Trick 4: Look for Patterns
Many DILR sets follow recurring patterns, like sequences, symmetry, or repeated conditions. Spotting patterns early allows you to fill in answers faster and with fewer calculations.
Trick 5: Skip and Return
If a set seems too complex initially, skip it and solve easier sets first. Return later with a fresh mind; sometimes insight comes after solving other questions.
Trick 6: Note Key Relationships
Write down important relationships, totals, or conditions in a structured way. Using small tables, grids, or diagrams helps you track information clearly and reduces errors.
Best Books for CAT DILR Preparation
The candidates can refer to the following best CAT 2025 books for the DILR section to enhance their CAT DILR preparation. These books will provide the candidates with even more CAT 2025 DILR practice questions to enhance their CAT DILR preparation.
Book Title
Author
How to Prepare for Data Interpretation for CAT
Arun Sharma
Logical Reasoning and Data Interpretation for the CAT
Nishit K. Sinha
A Modern Approach to Logical Reasoning
R.S. Aggarwal
Data Interpretation & Data Sufficiency
Ananta Ashisha
CAT Preparation Materials by Careers360
The candidates can download the various CAT preparation materials curated by the subject matter experts of Careers360 for the Data Interpretation and Logical Reasoning section, as well as the other important CAT sections, such as the CAT VARC and CAT QA sections, use the links given in the table below.
Q: Which topics in DILR should I prioritise for CAT 2025?
A:
Prioritise arrangements, puzzles, tables, caselets, and charts. These appear most frequently and practising them improves both accuracy and speed.
Q: How can I improve speed in DILR sets?
A:
Focus on analysing the set first, breaking it into smaller parts, and practising shortcut methods. Skipping tough sets initially also saves time.
Q: How many CAT 2025 DILR practice questions should I attempt daily?
A:
Attempt 15–20 CAT 2025 DILR practice sets daily initially, then increase to 25–30 sets as you gain speed and accuracy. Quality practice matters more than quantity.
Q: How many DILR sets should I solve daily for CAT 2025?
A:
Try solving at least 2–3 DILR sets daily. Mix topics like arrangements, puzzles, charts, and games.
Q: What are some effective resources and materials to prepare for CAT DILR?
A:
Recommended books include Arun Sharma’s How to Prepare for Data Interpretation, Nishit K. Sinha’s LRDI for CAT, and RS Aggarwal’s Logical Reasoning.
Q: How important is the DILR section in overall CAT performance?
A:
The DILR section is considered one of the most challenging and decisive parts of the CAT exam. Attempting at least 12 questions with high accuracy is a common benchmark for top percentile scores, making daily practice with varied set types essential.
Q: How many questions are there in the DILR section of CAT 2025 and how is it structured?
A:
The DILR section in CAT 2025 includes 22 questions to be solved within 40 minutes. These questions are a mix of MCQs and TITA (Type In The Answer), with jumbled sub-sections and a +3/−1 marking scheme, testing candidates' ability to manage both time and complexity effectively.
Hey! With an All India Rank (AIR) of 302,821 in NEET and belonging to the BCE category, it is highly unlikely to get a BDS seat in Telangana under the state quota, as the closing ranks for BCE are usually below 50,000. You may consider applying to private colleges under management quota or explore BDS seats in other states, but the chances remain very limited with this rank.
At KIMS Amalapuram, the internship stipend for MBBS students is generally reported to be around 20,000 per month, though some students have mentioned that in certain years no stipend was provided at all, which means it can vary depending on the policies in place at the time of your internship. To get the most accurate and updated information, it is always best to confirm directly with the college administration or recent interns, but on average, you can expect a stipend in the range of 18,000-20,000 per month during the compulsory rotating internship.
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Do not make another payment.
Making a second payment could cause a double debit, which is difficult to get a refund for. You should:
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a copy of your form and a screenshot of the "S" payment status as proof.
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contact the official CAT helpdesk
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The CAT 2025 exam is a national-level MBA entrance test for IIMs and top B-schools in India. It will be held on 30th November 2025 in computer-based mode across ~170 cities.
The registration is open from 1st August to 13th September 2025 on
iimcat.ac.in
.
Admit cards will be available from 5th November 2025 onward.
Graduates with at least 50 marks (45 for SC/ST/PwD) are eligible to apply.
The exam tests English, Reasoning, and Quantitative Aptitude in three timed sections.
M/s Deloitte Touche Tohmatsu Limited, one of the top four audit and accounting firms in the world with headquarters at London, UK, and with an operational presence in 153 countries, hires Management Trainees (MT) from all the premier management institutes of India thrice every year, in the months of January, May and September.
Each new group of Management Trainees (MT) have to go through a four month rigorous training schedule, after which they have to pass through a test consisting of a written assessment and a case-analysis. The top hundred ranked Management Trainees (MT) based on the performance in the test are confirmed as Management Executives (ME). The rest are given the opportunity of undergoing the training for four months one more time along with the next batch of Management Trainees (MT) and then passing through the subsequent test consisting of the written assessment and case-analysis. The Management Trainee (MT) who fails to get confirmed as a Management Executive (ME) the second time is fired.
The scatter-graph below depicts the number of Management Trainees (MT) at Deloitte taking the tests from January 2020 till May 2022, and the vis-à-vis hired Management Trainees (MT) at Deloitte who were fired :
It is also known that for the month of September 2019 at Deloitte, 96 hired Management Trainees (MT) failed to be confirmed as a Management Executive (ME) the first time, and that 36 hired Management Trainees (MT) were fired.
Question :
In which test did the minimum number of Management Trainees (MT) get confirmed as a Management Executive (ME) in the second attempt ?
Two friends Moloy and Niloy passed out from the Purulia Institute of Science and Technology with B.Tech degrees in Mechanical Engineering, but even after a year placement was hard to find. So they decided to take the challenge head-on, came down to Kolkata, rented a garage space on Park Street, and having an affinity towards making people enjoy good food, started their firm named 'B.Tech Bread-Omlette Wala'.
They started with three items on the menu. One was the French Toast which could be prepared in 3 minutes. The second was the Egg Tortillas which took 15 minutes to prepare. Any one of Moloy and Niloy could prepare any one of them at a time. The third was the Egg Bhurji with French Fries. This however was prepared on an automated fryer which could prepare 3 servings at a time and took 5 minutes irrespective of the number of servings equal to or below 3. The fryer did not need anyone to attend to it, and the time to put in the raw ingredients could be neglected. So one could tend to the preparation of other items while the Egg Bhurji with French Fries were being prepared.
They wanted to serve the orders as early as possible after the order was given. The individual items in any order were served as and when all the items were ready, and the order was then considered closed. None of the items on the menu were prepared in advance in anticipation of future orders.
On the first day, 3 groups of customers came in and ordered at 6.00 pm, 6.10 pm, and 6.13 pm. The first order was for a plate of Egg Tortillas, two plates of French Toast, and three plates of Egg Bhurji with French Fries. The second order was for a plate of French Toast and two plates of Egg Bhurji with French Fries. The third order was for a plate of Egg Tortilla and a plate of Egg Bhurji with French Fries.
On the backdrop of the above information answer the questions given :
Question:
Assuming that the next customer's order could only be attended to when the previous customer's order was closed, at what time would the first customer's order be considered closed ?
Six sticks of equal lengths were kept in the vertical position in an empty flower-vase, to be arranged at the six corners of a regular hexagon. The two ends of each of the sticks were of different colours.
The top ends of the sticks were one of each of the following colours – Red, Cyan, Pink, Brown, Black and Green. The bottom ends were one of each of the following colours – Blue, Yellow, White, Orange, Purple and Grey. Both the sets of colours mentioned were in no particular order.
It was also known that :
a) The stick with the red colour was opposite to the stick with the blue colour
b) There were exactly two sticks whose both ends had colours whose names started with the same letter
c) The stick with the grey colour was adjacent to the stick with the white colour
d) The stick with the cyan colour was adjacent to both the sticks with the brown colour and the one with the blue colour
e) The stick with the purple colour was adjacent to both the sticks with the grey colour and the one with the green colour
f) The stick with the white colour was opposite to the stick with the green colour
Question :
What was the colour of the bottom end of the stick having brown colour at the top end ?
Two friends Moloy and Niloy passed out from the Purulia Institute of Science and Technology with B.Tech degrees in Mechanical Engineering, but even after a year placement was hard to find. So they decided to take the challenge head-on, came down to Kolkata, rented a garage space on Park Street, and having an affinity towards making people enjoy good food, started their firm named 'B.Tech Bread-Omlette Wala'.
They started with three items on the menu. One was the French Toast which could be prepared in 3 minutes. The second was the Egg Tortillas which took 15 minutes to prepare. Any one of Moloy and Niloy could prepare any one of them at a time. The third was the Egg Bhurji with French Fries. This however was prepared on an automated fryer which could prepare 3 servings at a time and took 5 minutes irrespective of the number of servings equal to or below 3. The fryer did not need anyone to attend to it, and the time to put in the raw ingredients could be neglected. So one could tend to the preparation of other items while the Egg Bhurji with French Fries were being prepared.
They wanted to serve the orders as early as possible after the order was given. The individual items in any order were served as and when all the items were ready, and the order was then considered closed. None of the items on the menu were prepared in advance in anticipation of future orders.
On the first day, 3 groups of customers came in and ordered at 6.00 pm, 6.10 pm, and 6.13 pm. The first order was for a plate of Egg Tortillas, two plates of French Toast, and three plates of Egg Bhurji with French Fries. The second order was for a plate of French Toast and two plates of Egg Bhurji with French Fries. The third order was for a plate of Egg Tortilla and a plate of Egg Bhurji with French Fries.
On the backdrop of the above information answer the questions given :
Question:
Assuming that the next customer's order could only be attended to when the previous customer's order was closed, at what time would the third customer's order be considered closed ?
Two friends Moloy and Niloy passed out from the Purulia Institute of Science and Technology with B.Tech degrees in Mechanical Engineering, but even after a year placement was hard to find. So they decided to take the challenge head-on, came down to Kolkata, rented a garage space on Park Street, and having an affinity towards making people enjoy good food, started their firm named 'B.Tech Bread-Omlette Wala'.
They started with three items on the menu. One was the French Toast which could be prepared in 3 minutes. The second was the Egg Tortillas which took 15 minutes to prepare. Any one of Moloy and Niloy could prepare any one of them at a time. The third was the Egg Bhurji with French Fries. This however was prepared on an automated fryer which could prepare 3 servings at a time and took 5 minutes irrespective of the number of servings equal to or below 3. The fryer did not need anyone to attend to it, and the time to put in the raw ingredients could be neglected. So one could tend to the preparation of other items while the Egg Bhurji with French Fries were being prepared.
They wanted to serve the orders as early as possible after the order was given. The individual items in any order were served as and when all the items were ready, and the order was then considered closed. None of the items on the menu were prepared in advance in anticipation of future orders.
On the first day, 3 groups of customers came in and ordered at 6.00 pm, 6.10 pm, and 6.13 pm. The first order was for a plate of Egg Tortillas, two plates of French Toast, and three plates of Egg Bhurji with French Fries. The second order was for a plate of French Toast and two plates of Egg Bhurji with French Fries. The third order was for a plate of Egg Tortilla and a plate of Egg Bhurji with French Fries.
On the backdrop of the above information answer the questions given :
Question:
Suppose Moloy and Niloy had decided to process multiple orders at the same time, however strictly prioritising a first come first serve basis, when would the second customer's order be considered closed ?
Two friends Moloy and Niloy passed out from the Purulia Institute of Science and Technology with B.Tech degrees in Mechanical Engineering, but even after a year placement was hard to find. So they decided to take the challenge head-on, came down to Kolkata, rented a garage space on Park Street, and having an affinity towards making people enjoy good food, started their firm named 'B.Tech Bread-Omlette Wala'.
They started with three items on the menu. One was the French Toast which could be prepared in 3 minutes. The second was the Egg Tortillas which took 15 minutes to prepare. Any one of Moloy and Niloy could prepare any one of them at a time. The third was the Egg Bhurji with French Fries. This however was prepared on an automated fryer which could prepare 3 servings at a time and took 5 minutes irrespective of the number of servings equal to or below 3. The fryer did not need anyone to attend to it, and the time to put in the raw ingredients could be neglected. So one could tend to the preparation of other items while the Egg Bhurji with French Fries were being prepared.
They wanted to serve the orders as early as possible after the order was given. The individual items in any order were served as and when all the items were ready, and the order was then considered closed. None of the items on the menu were prepared in advance in anticipation of future orders.
On the first day, 3 groups of customers came in and ordered at 6.00 pm, 6.10 pm, and 6.13 pm. The first order was for a plate of Egg Tortillas, two plates of French Toast, and three plates of Egg Bhurji with French Fries. The second order was for a plate of French Toast and two plates of Egg Bhurji with French Fries. The third order was for a plate of Egg Tortilla and a plate of Egg Bhurji with French Fries.
On the backdrop of the above information answer the questions given :
Question:
Suppose Moloy and Niloy had decided to process multiple orders at the same time, however strictly prioritising a first come first serve basis, when would the third customer's order be considered closed ?
Two friends Moloy and Niloy passed out from the Purulia Institute of Science and Technology with B.Tech degrees in Mechanical Engineering, but even after a year placement was hard to find. So they decided to take the challenge head-on, came down to Kolkata, rented a garage space on Park Street, and having an affinity towards making people enjoy good food, started their firm named 'B.Tech Bread-Omlette Wala'.
They started with three items on the menu. One was the French Toast which could be prepared in 3 minutes. The second was the Egg Tortillas which took 15 minutes to prepare. Any one of Moloy and Niloy could prepare any one of them at a time. The third was the Egg Bhurji with French Fries. This however was prepared on an automated fryer which could prepare 3 servings at a time and took 5 minutes irrespective of the number of servings equal to or below 3. The fryer did not need anyone to attend to it, and the time to put in the raw ingredients could be neglected. So one could tend to the preparation of other items while the Egg Bhurji with French Fries were being prepared.
They wanted to serve the orders as early as possible after the order was given. The individual items in any order were served as and when all the items were ready, and the order was then considered closed. None of the items on the menu were prepared in advance in anticipation of future orders.
On the first day, 3 groups of customers came in and ordered at 6.00 pm, 6.10 pm, and 6.13 pm. The first order was for a plate of Egg Tortillas, two plates of French Toast, and three plates of Egg Bhurji with French Fries. The second order was for a plate of French Toast and two plates of Egg Bhurji with French Fries. The third order was for a plate of Egg Tortilla and a plate of Egg Bhurji with French Fries.
On the backdrop of the above information answer the questions given :
Question:
A fourth customer comes in and orders two plates of French Toast at 6.24 pm. Suppose Moloy and Niloy had decided to process multiple orders at the same time, however strictly prioritising a first come first serve basis. For exactly how many minutes would one of the friends be idle from 6.00 pm till serving the last customer, assuming that the four customers were the only ones to have come in within the period being discussed ?
Two friends Moloy and Niloy passed out from the Purulia Institute of Science and Technology with B.Tech degrees in Mechanical Engineering, but even after a year placement was hard to find. So they decided to take the challenge head-on, came down to Kolkata, rented a garage space on Park Street, and having an affinity towards making people enjoy good food, started their firm named 'B.Tech Bread-Omlette Wala'.
They started with three items on the menu. One was the French Toast which could be prepared in 3 minutes. The second was the Egg Tortillas which took 15 minutes to prepare. Any one of Moloy and Niloy could prepare any one of them at a time. The third was the Egg Bhurji with French Fries. This however was prepared on an automated fryer which could prepare 3 servings at a time and took 5 minutes irrespective of the number of servings equal to or below 3. The fryer did not need anyone to attend to it, and the time to put in the raw ingredients could be neglected. So one could tend to the preparation of other items while the Egg Bhurji with French Fries were being prepared.
They wanted to serve the orders as early as possible after the order was given. The individual items in any order were served as and when all the items were ready, and the order was then considered closed. None of the items on the menu were prepared in advance in anticipation of future orders.
On the first day, 3 groups of customers came in and ordered at 6.00 pm, 6.10 pm, and 6.13 pm. The first order was for a plate of Egg Tortillas, two plates of French Toast, and three plates of Egg Bhurji with French Fries. The second order was for a plate of French Toast and two plates of Egg Bhurji with French Fries. The third order was for a plate of Egg Tortilla and a plate of Egg Bhurji with French Fries.
On the backdrop of the above information answer the questions given :
Question:
Had Niloy been absent on that day, and assuming that the next customer's order could only be attended to when the previous customer's order was closed, at what time would the fourth customer's order (refer to the previous question) be considered closed ?
The bar-graph given below shows the foreign exchange reserves of Nepal (in million Rupees) from 2014 to 2021. Answer the following questions based on the graph :
Question:
What was the percentage increase (rounded to the nearest integer, if deemed necessary) in the foreign exchange reserves in 2020 over 2016 ?
The Jadavpur University’s Prince Anwar Shah Road hostel consists of two large separate buildings, one for the ladies and the other for the gents, while having a common kitchen and dining hall. It is the hostel of the CS and the EEC department of engineering students of the university.
In recognition of the growing dissatisfaction and hence complaints among the inmates of the hostel regarding the menu served for dinner, the Dean of the engineering department, Dr Aparesh Sanyal, personally decided to investigate the matter. He set about collecting information about the preference of dinner among the inmates, separately from the gents and the ladies wing of the hostel.
Dr Sanyal was able to gather the following partial information :
Hostel inmates
Menu preference for dinner
Total
Egg Meal
Fish Meal
Chicken Meal
Gents
20
Ladies
64
Total
60
The Warden of the hostel was consulted, who after investigation declared that the following facts were clear :
1. Forty percent of the hostel inmates were ladies
2. One-third of the gentlemen inmates preferred an egg meal for dinner
3. Half the hostel inmates preferred either fish meal or chicken meal
Question:
What proportion of the lady hostel inmates preferred a fish meal for dinner ?
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