CAT 2025 Arithmetic Shortcuts: 1 Formula to Solve 5 Types of Questions

CAT 2025 Arithmetic Shortcuts: 1 Formula to Solve 5 Types of Questions

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Komal MiglaniUpdated on 11 Oct 2025, 10:45 AM IST

Hello CAT aspirants! As the CAT exam approaches, it’s the right time to focus on shortcuts and quick methods to tackle the Quantitative Aptitude section. You already know that out of 22 questions in CAT QA, around 8–10 questions come from arithmetic. That’s why learning effective arithmetic shortcuts is crucial to boost your speed and accuracy. In this article, you’ll learn how one simple formula can help you solve 5 different types of arithmetic questions, making your preparation smarter and more efficient for CAT 2025.

This Story also Contains

  1. Importance of Arithmetic in CAT
  2. The Magic Formula 1: Percentage Change
  3. The Magic Formula 2: Weighted Average
  4. Why These Shortcuts Work
  5. Previous Years Questions
  6. Best resources & practice material for CAT Number System
  7. CAT 2025 Preparation Resources by Careers360
CAT 2025 Arithmetic Shortcuts: 1 Formula to Solve 5 Types of Questions
CAT Arithmetic Shortcuts 2025

Importance of Arithmetic in CAT

As discussed above arithmetic has a significant topicwise weightage in CAT Quantitative Aptitude section. It makes almost 40% – 45% of the total questions asked in CAT QA. You need to focus on each topic of arithmetic to ace this section.

To know the syllabus of QA section CAT, click on: Quantitative aptitude syllabus for CAT – 2025.

Important arithmetic topics for CAT

As arithmetic is very important to ace the QA section of CAT, we should know which topic we need to focus more on. Therefore, we should know the important topics and their weightage in recent years.

Important arithmetic topics for CAT are


For complete syllabus of CAT, visit CAT syllabus 2025.

Have a look at the number of questions asked in CAT from arithmetic during last 5 years.

S. No.

Year

Slot

Percentage and its application

Average, Ratio, and Mixture

TSD

Time and Work

Total

1

2020

1

3

3

4


11

2

2020

2

3

2

4

1

10

3

2020

3

3

3

3

1

10

4

2021

1

3

3

1

3

10

5

2021

2

4

2

1

2

9

6

2021

3

3

3

1

3

10

7

2022

1

4

2

1

2

9

8

2022

2

2

5

1

1

9

9

2022

3

1

4

3

2

10

10

2023

1

3

2

3

1

9

11

2023

2

3

4

1

1

9

12

2023

3

3

2

1

2

8

13

2024

1

3

3

1

1

8

14

2024

2

4

2

1

1

8

15

2024

3

4

3

1

1

9

The Magic Formula 1: Percentage Change

CAT arithmetic shortcuts are important to increase accuracy and save time. Here, we will discuss 1 formula to solve 5 CAT question types with short approach.

The formula:

Final Value=Base or Initial Value×(1±Percentage Change100)

Other form of this formula:

Percentage Change=Final Value - Initial ValueInitial Value×100%

Applications of the Formula in 5 CAT question types

We are going to discuss application of percentage change formula in 5 different types of questions.

Type 1: To find the Percentage Increase or Decrease

This formula is used

  • To determine the percentage increase or decrease in population of a town

  • To solve the questions of depreciation or appreciation

  • To determine the percentage while comparing two values

  • To solve expenditure-based questions

Example:

A number is increased by 20% then by what percent it should be decreased to get the original value again?

Solution:

A number is increased by 20%: New Value = Initial Value × (1 + 20100) = Initial Value × 1.2

Required Percentage change: Percentage Change=ChangeBase×100%

= Initial Value × 1.2 - Initial ValueInitial Value × 1.2×100%

= 0.21.2×100%

= 16.66%

Type 2: Application in Profit and Loss

This formula is used

  • To determine the selling price (Final Value) if Cost Price (Initial Value) and Profit or Loss percentage (Percentage Change) is given.

  • To determine the Profit or Loss percentage (Percentage Change) if selling price (Final Value) and Cost Price (Initial Value) is given.

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Example:

A shopkeeper buys an article at ₹1000 and gains 20%. Find Selling Price.

Solution:

Selling Price = 1000 × (1 + 0.2) = ₹1200

Similarly, if he makes a 20% loss:

Then Selling Price = 1000 × 0.8 = ₹800


3. Application in Simple Interest (SI)

Simple interest is equivalent to percentage change of the principal over time.


Example: Principal = ₹2000, Rate = 10%, Time = 3 years. Calculate amount after 3 years.

Solution:

To determine the Amount after 3 years, take percentage change = 10 × 3 = 30%

Now apply the percentage change formula;

Amount =2000×(1+30100) = ₹2600


4. Application in Compound Interest (CI)

Repeated percentage change year after year gives the amount if interest is compounded annually.


Example:

Principal = ₹2000, Rate = 10% per annum compounded annually, Time = 3 years. Calculate the amount after 3 years.

Solution:

Amount after three years = 2000×(1+10100)×(1+10100)×(1+10100) = ₹2662

Compound interest = ₹ (2662 – 2000) = ₹ 662


Tip → You can think of compound interest as successive percentage changes.


5. Application in Successive Percentage Change

Questions bases two or more consecutive changes (increase/decrease) can also be solved with the same principle.


Shortcut:

Final Value=Initial Value(Base)×(1±a100)×(1±b100)


Example:

Price of an article increases by 20% and then decreases by 10%. Find net percentage change in the price of the article.

Solution:

Take Base Value or initial value = 100

Final Value=100×(1+20100)×(110100)
Final Value=100×1.2×0.9
Final Value=108

Net effect = 8% increase.

The Magic Formula 2: Weighted Average

CAT arithmetic shortcuts are important to increase accuracy and save time. Here, we will discuss 1 formula to solve 5 CAT question types with short approach where average needs to be calculated.

The formula:

Weighted average=Sum of Products of weights with average valueSum of Weights

Applications of the Formula in 5 CAT question types

We are going to discuss the application of weighted average in 5 different types of questions.

Type 1: To find the average value when two or more ingredients at different price are mixed in a given ratio

This formula is used

  • To determine the ratio of mixing two or more ingredients

  • To determine the average price when two or more quantities are added in a ratio

  • In milk and water problems

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Example:

If two varieties of wheats costing ₹40 and ₹60 are mixed in a ratio of 3 : 4 respectively, find the average price of wheat.

Solution:

Using the formula:

Weighted average=Sum of Products of weights with average valueSum of Weights

Required average price =40×3+60×43+4=51.42

Type 2: Application in Time, Speed, and Distance

This formula is used

  • To determine the average speed in TSD questions asked in CAT when different distances are covered at different speeds.

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Example:

Amit covers 80 km at 40 km/h and 120 km at 80 km/h. find his average speed for the journey.

Solution:

Time taken to cover 80 km at 40 km/h = 2 hrs

Time taken to cover 120 km at 80 km/h = 1.5 hrs

Using the formula:

Weighted average=Sum of Products of weights with average valueSum of Weights

Weighted average formula is reduced to average ie. Average speed = Total DistanceTotal time

Average speed=80+1202+1.5=57.14

Trick: If two equal distances are covered at different speeds, the average speed is the weighted harmonic mean.

Average speed = Twice of product of speedsSum of speeds

3. Application in Time and Work

When two or more workers having different efficiencies work together, their combined work rate is a weighted average of their individual rates.

Example: A can complete a job in 10 days, B in 20 days. In how many days they will finish the work together?

Solution:

To determine the 1-day work of A and B together, take weighted average

1 day work = 10+2010×20=320

So, time taken = 203 days

4. Application in Marks and Averages

The concept of weighted average is used when adding or removing, a student’s marks differ from average. Also, this concept is used to quick calculation of weighted average.

Example:

The average marks of 10 students is 40. A new student with 51 marks joins. Find the new average.

Solution:

Using the concept of weighted average, Ne average = 10×40+5111=45111=41

5. Application in Profit & Loss

When two or more items purchased at same rate and sold at different profit/loss percentages, the net effect can be quickly found with the help of this formula.

Shortcut:

Final Profit or loss percentage=Sum of all profit and loss percentagesNumber of items, Here loss percentage is taken a s negative

Example:

A trader makes a profit of 25% on one item and loss of 15% on another, both of equal cost price. Find the overall profit or loss percentages.

Solution:

Using the above formula

Final Profit percent=25152=5%

Why These Shortcuts Work

These arithmetic shortcuts for CAT are necessary to ace Arithmetic section of CAT. If we look at the topics like Profit and loss, mixtures, SI and CI, all are looked different but in reality they can be reduced to a similar logic.

As we have seen, Profit and loss, SI and CI are extension of percentages. Mixtures is an extension of average. Time and Work is extension of average and ratio.

Percentage formula unifies all the topics like profit and loss, SI and CI. Average unifies all the five topics discussed above.

Key Advantages

  • It reduces time

  • No need to learn specific formulas for different concepts

  • It reduces confusion

  • It increases accuracy

Previous Years Questions

Q 1) During the first year, the population of the town increased by 12%. The next year, due to some contagious disease, it decreased by 8%. At the end of the second year, the population was 64,400. Find the population of the town at the beginning of the first year.

1) 50,000

2) 54,750

3) 62,500

4) 50,500

Solution:

Let the initial population be x.

Then, according to the question,

The population increased by 12%

meaning the current population is 112%

of x. Again the population decreased

meaning it is now 92% of 112% of x.

So, 92% of 112% of x=64400

0.92×1.12x=64400

x=64400(0.92×1.12)

x=644001.0304

x=62500

Hence, the correct answer is 62,500.

Q 2) A notebook was sold for Rs. 28, at a profit of 12%. If it had been sold for Rs. 26.25, what would have been the profit percentage?

1) 5%

2) 7%

3) 4%

4) 6%

Solution:

Given: A notebook was sold for Rs. 28, at a profit of 12%.

The selling price (SP) is Rs. 28 and the profit is 12%.

Then, cost price (CP) is SP×100100+ Profit % .

So, CP=28×100100+12=2800112=25

If SP is Rs. 26.25, the profit

percentage will be SPCPCP×100

=26.252525×100=5%

Hence, the correct answer is 5%.

Q 3) The interest on a certain deposit at 4.5% p.a. is INR 135 in one year. How much will the additional interest in one year be on the same deposit at 5\% p.a.?

1) INR 16

2) INR 15

3) INR 14

4) INR 18

Solution:

Given: The interest on a certain deposit at 4.5% p.a. is INR 135 in one year.

Let the principle be P.

Simple interest = Principal × Rate × Time 100

135=P×4.5×1100

P=135004.5=3000

On the same principle at a 5% rate in 1 year,

Simple interest =3000×5×1100=150

So, the additional interest is 150135= INR 15

Hence, the correct answer is INR 15.

Q 4) A is 50% more efficient than B. B finished the same work in 20 days. If A and B worked together, then how much time would they take to finish the same work?

1) 10 days

2) 7 days

3) 8 days

4) 9 days

Solution:

Let the efficiency of B be 100 .

So, the efficiency of A=100+50=150

The efficiency ratio of A and B=150 :

100=3:2

Total efficiency =3+2=5 units

The time taken by B to finish the work is 20 days.

So, Total work = Efficiency of B× Time taken by B

Total work =2×20=40 units

Time taken by (A+B) to complete the work

= Total work Total efficiency

=405

=8 days

A and B together will finish the work in 8 days.

Hence, the correct answer is 8 days.

Q 5) Prasad goes 96 kilometres on a bike at a speed of 16 km/hr, 124 kilometres at 31 km/hr in a car, and 105 kilometres at 7 km/hr in a horse cart. Find his average speed for the entire distance travelled.

1) 16 km/hr

2) 13 km/hr

3) 7 km/hr

4) 11 km/hr

Solution:

Total distance travelled = 96+124+105=325 km

Total time taken =9616+12431+1057=6+4+15=25 hours

Average speed = Total distance Total time taken =32525=13 km/hr

Hence, the correct answer is 13 km/hr.

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Frequently Asked Questions (FAQs)

Q: How can we calculate average speed if a person travels with two different speeds for equal time?
A:

Average speed in this case is equal to sum of the speeds divided by 2.

Q: What is the difference between average and weighted average?
A:

Simple average is calculated when quantities are equal. Weighted average is calculated when quantities are not equal.

Q: Do I need to practice each application separately?
A:

Although, you can use the same formula but you need to practice each application separately so that you can get familiar with the question type.

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With a 70 percent in CAT Examination, you can go for various B-Schools or private collages. The S. K. Patel Institute of Management in Gandhinagar is an option for those who score 70-80 percent in their CAT examination or The Gujarat Institute of Management (GIM) in Goa with a cutoff of 60-80 percentage. These are the collages you can look for in Gujarat or nearby.

Collage in other regions: BA Colleges Accepting 70-80 Percentile in CAT 2025

Thank You.

Hello dear candidate,

NO. your application for CAT will not rejected for wrong gender small mistake in the OBC NCL certificate. You will be considered as an OBC candidate.

you just need to get your OBC certificate corrected and need to inform the CAT helpdesk about this error.


Hello,

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  • SIMSREE, Mumbai – Fee around Rs. 1.3–1.4 lakh for 2 years. Accepts CAT, CMAT, MAH-CET, MAT, ATMA. Cutoff is very high, usually 99+ percentile in CAT/CMAT.

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These are the main government institutes where the full MBA/PG programme fee is within Rs. 2 lakh. Cutoffs vary slightly each year and by category, but SIMSREE and PUMBA generally need high scores, while TISS has its own process along with CAT shortlisting.

Hope it helps !

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You can consider private dental colleges, state quota seats in other states, or reattempt NEET next year to improve your chances.

Hello dear candidate,

YES, with NEET score 344in the ST category you have high chances of getting admission in a BDS College in J&K through JKBOPEE counselling.

check the seat availability and next participate in JKBOPEE Counselling with all the necessary documents.

Thank you.