CAT Admit Card Date:05 Nov' 25 - 30 Nov' 25
Hello CAT aspirants! As the CAT exam approaches, it’s the right time to focus on shortcuts and quick methods to tackle the Quantitative Aptitude section. You already know that out of 22 questions in CAT QA, around 8–10 questions come from arithmetic. That’s why learning effective arithmetic shortcuts is crucial to boost your speed and accuracy. In this article, you’ll learn how one simple formula can help you solve 5 different types of arithmetic questions, making your preparation smarter and more efficient for CAT 2025.
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As discussed above arithmetic has a significant topicwise weightage in CAT Quantitative Aptitude section. It makes almost 40% – 45% of the total questions asked in CAT QA. You need to focus on each topic of arithmetic to ace this section.
To know the syllabus of QA section CAT, click on: Quantitative aptitude syllabus for CAT – 2025.
As arithmetic is very important to ace the QA section of CAT, we should know which topic we need to focus more on. Therefore, we should know the important topics and their weightage in recent years.
Important arithmetic topics for CAT are
For complete syllabus of CAT, visit CAT syllabus 2025.
Have a look at the number of questions asked in CAT from arithmetic during last 5 years.
S. No. | Year | Slot | Percentage and its application | Average, Ratio, and Mixture | TSD | Time and Work | Total |
1 | 2020 | 1 | 3 | 3 | 4 | 11 | |
2 | 2020 | 2 | 3 | 2 | 4 | 1 | 10 |
3 | 2020 | 3 | 3 | 3 | 3 | 1 | 10 |
4 | 2021 | 1 | 3 | 3 | 1 | 3 | 10 |
5 | 2021 | 2 | 4 | 2 | 1 | 2 | 9 |
6 | 2021 | 3 | 3 | 3 | 1 | 3 | 10 |
7 | 2022 | 1 | 4 | 2 | 1 | 2 | 9 |
8 | 2022 | 2 | 2 | 5 | 1 | 1 | 9 |
9 | 2022 | 3 | 1 | 4 | 3 | 2 | 10 |
10 | 2023 | 1 | 3 | 2 | 3 | 1 | 9 |
11 | 2023 | 2 | 3 | 4 | 1 | 1 | 9 |
12 | 2023 | 3 | 3 | 2 | 1 | 2 | 8 |
13 | 2024 | 1 | 3 | 3 | 1 | 1 | 8 |
14 | 2024 | 2 | 4 | 2 | 1 | 1 | 8 |
15 | 2024 | 3 | 4 | 3 | 1 | 1 | 9 |
CAT arithmetic shortcuts are important to increase accuracy and save time. Here, we will discuss 1 formula to solve 5 CAT question types with short approach.
Final Value formula:
$Final\ Value = Base\ or\ Initial\ Value \times \left(1 \pm \frac{Percentage\ Change}{100}\right)$
Other form (Percentage Change formula):
$Percentage\ Change = \frac{Final\ Value - Initial\ Value}{Initial\ Value} \times 100%$
We are going to discuss application of percentage change formula in 5 different types of questions.
Type 1: To find the Percentage Increase or Decrease
This formula is used
To determine the percentage increase or decrease in population of a town
To solve the questions of depreciation or appreciation
To determine the percentage while comparing two values
To solve expenditure-based questions
Example:
A number is increased by 20%. By what percent should it be decreased to get the original value again?
Solution:
A number is increased by 20%:
$ \text{New Value} = \text{Initial Value} \times \left(1 + \frac{20}{100}\right) = \text{Initial Value} \times 1.2 $
$ \text{Required percentage decrease: } \text{Percentage Change} = \frac{\text{Change}}{\text{Base}} \times 100\% $
$ = \frac{\text{Initial Value} \times 1.2 - \text{Initial Value}}{\text{Initial Value} \times 1.2} \times 100\% $
$ = \frac{0.2 \times \text{Initial Value}}{1.2 \times \text{Initial Value}} \times 100\% $
$ = 16.66\% $
Type 2: Application in Profit and Loss
This formula is used
To determine the selling price (Final Value) if Cost Price (Initial Value) and Profit or Loss percentage (Percentage Change) is given.
To determine the Profit or Loss percentage (Percentage Change) if selling price (Final Value) and Cost Price (Initial Value) is given.
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Example:
A shopkeeper buys an article at ₹1000 and gains 20%. Find the Selling Price.
Solution:
$ \text{Selling Price} = 1000 \times (1 + 0.2) = \text{₹1200} $
Similarly, if he makes a 20% loss:
$ \text{Selling Price} = 1000 \times 0.8 = \text{₹800} $
Type 3. Application in Simple Interest (SI)
Simple interest is equivalent to percentage change of the principal over time.
Example:
Principal = ₹2000, Rate = 10%, Time = 3 years. Calculate the amount after 3 years.
Solution:
Total percentage change = $10 \times 3 = 30%$
Apply the percentage change formula:
$\text{Amount} = 2000 \times \left(1 + \frac{30}{100}\right) = 2600$ Rs
Type 4. Application in Compound Interest (CI)
Repeated percentage change year after year gives the amount if interest is compounded annually.
Example:
Principal = ₹2000, Rate = 10% per annum compounded annually, Time = 3 years. Calculate the amount after 3 years.
Solution:
$ \text{Amount after 3 years} = 2000 \times \left(1 + \frac{10}{100}\right) \times \left(1 + \frac{10}{100}\right) \times \left(1 + \frac{10}{100}\right) = 2662 $ Rs
$ \text{Compound Interest} = (2662 - 2000) = 662 $ Rs
Tip → You can think of compound interest as successive percentage changes.
Type 5. Application in Successive Percentage Change
Questions bases two or more consecutive changes (increase/decrease) can also be solved with the same principle.
Shortcut:
$ \text{Final Value} = \text{Initial Value (Base)} \times \left(1 \pm \frac{a}{100}\right) \times \left(1 \pm \frac{b}{100}\right) $
Example:
Price of an article increases by 20% and then decreases by 10%. Find the net percentage change in the price of the article.
Solution:
Take Base Value or Initial Value = 100
$ \text{Final Value} = 100 \times \left(1 + \frac{20}{100}\right) \times \left(1 - \frac{10}{100}\right) $
$ \Rightarrow \text{Final Value} = 100 \times 1.2 \times 0.9 $
$ \Rightarrow \text{Final Value} = 108 $
$ \text{Net Effect} = 8% \ \text{increase} $
CAT arithmetic shortcuts are important to increase accuracy and save time. Here, we will discuss 1 formula to solve 5 CAT question types with short approach where average needs to be calculated.
$ \text{Weighted Average} = \frac{\text{Sum of (Weights × Values)}}{\text{Sum of Weights}} $
We are going to discuss the application of weighted average in 5 different types of questions.
Type 1: To find the average value when two or more ingredients at different price are mixed in a given ratio
This formula is used
To determine the ratio of mixing two or more ingredients
To determine the average price when two or more quantities are added in a ratio
In milk and water problems
Example:
If two varieties of wheat costing ₹40 and ₹60 are mixed in a ratio of 3:4 respectively, find the average price of wheat.
Solution:
Using the formula:
$ \text{Weighted Average} = \frac{\text{Sum of (Weights × Values)}}{\text{Sum of Weights}} $
$ \text{Required Average Price} = \frac{40 \times 3 + 60 \times 4}{3 + 4} = 51.42 $
Type 2: Application in Time, Speed, and Distance
This formula is used
To determine the average speed in TSD questions asked in CAT when different distances are covered at different speeds.
Example:
Amit covers 80 km at 40 km/h and 120 km at 80 km/h. Find his average speed for the journey.
Solution:
Time taken to cover 80 km at 40 km/h:
$ \text{Time}_1 = \frac{80}{40} = 2\ \text{hours} $
Time taken to cover 120 km at 80 km/h:
$ \text{Time}_2 = \frac{120}{80} = 1.5\ \text{hours} $
Average speed formula:
$ \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} $
$ \text{Average Speed} = \frac{80 + 120}{2 + 1.5} = \frac{200}{3.5} = 57.14\ \text{km/h} $
Trick: If two equal distances are covered at different speeds, the average speed is the weighted harmonic mean.
$ \text{Average Speed} = \frac{2 \times (\text{Speed}_1 \times \text{Speed}_2)}{\text{Speed}_1 + \text{Speed}_2} $
Type 3. Application in Time and Work
When two or more workers having different efficiencies work together, their combined work rate is a weighted average of their individual rates.
Example:
A can complete a job in 10 days, B in 20 days. In how many days will they finish the work together?
Solution:
Work done by A in 1 day:
$ \text{Work}_A = \frac{1}{10} $
Work done by B in 1 day:
$ \text{Work}_B = \frac{1}{20} $
Work done by A and B together in 1 day:
$ \text{Work}_{\text{Together}} = \frac{1}{10} + \frac{1}{20} = \frac{3}{20} $
Time taken to finish the work together:
$ \text{Time} = \frac{1}{\text{Work}_{\text{Together}}} = \frac{1}{3/20} = \frac{20}{3} \approx 6.67\ \text{days} $
Type 4. Application in Marks and Averages
The concept of weighted average is used when adding or removing, a student’s marks differ from average. Also, this concept is used to quick calculation of weighted average.
Example:
The average marks of 10 students is 40. A new student with 51 marks joins. Find the new average.
Solution:
Using the concept of weighted average:
$ \text{New Average} = \frac{10 \times 40 + 51}{10 + 1} = \frac{451}{11} = 41 $
Type 5. Application in Profit & Loss
When two or more items purchased at same rate and sold at different profit/loss percentages, the net effect can be quickly found with the help of this formula.
Shortcut:
$ \text{Final Profit or Loss %} = \frac{\text{Sum of all Profit and Loss %}}{\text{Number of Items}} $
(Here, loss percentage is taken as negative.)
Example:
A trader makes a profit of 25% on one item and a loss of 15% on another, both of equal cost price. Find the overall profit or loss percentage.
Solution:
Using the formula:
$ \text{Final Profit %} = \frac{25 + (-15)}{2} = \frac{10}{2} = 5% $
These arithmetic shortcuts for CAT are necessary to ace Arithmetic section of CAT. If we look at the topics like Profit and loss, mixtures, SI and CI, all are looked different but in reality they can be reduced to a similar logic.
As we have seen, Profit and loss, SI and CI are extension of percentages. Mixtures is an extension of average. Time and Work is extension of average and ratio.
Percentage formula unifies all the topics like profit and loss, SI and CI. Average unifies all the five topics discussed above.
It reduces time
No need to learn specific formulas for different concepts
It reduces confusion
It increases accuracy
Q1. During the first year, the population of the town increased by 12%. The next year, due to some contagious disease, it decreased by 8%. At the end of the second year, the population was 64,400. Find the population of the town at the beginning of the first year.
50,000
54,750
62,500
50,500
Solution:
Let the initial population be $x$.
Population after 12% increase: $1.12x$
Population after 8% decrease: $0.92 \times 1.12x = 64400$
$x = \frac{64400}{0.92 \times 1.12} = \frac{64400}{1.0304} = 62500$
Answer: 62,500
Q2. A notebook was sold for Rs. 28, at a profit of 12%. If it had been sold for Rs. 26.25, what would have been the profit percentage?
5%
7%
4%
6%
Solution:
Given $SP = 28$, Profit % = 12%
$CP = \frac{SP \times 100}{100 + \text{Profit %}} = \frac{28 \times 100}{112} = 25$
If $SP = 26.25$, Profit % = $\frac{26.25 - 25}{25} \times 100 = 5%$
Answer: 5%
Q3. The interest on a certain deposit at 4.5% p.a. is INR 135 in one year. How much will the additional interest in one year be on the same deposit at 5% p.a.?
INR 16
INR 15
INR 14
INR 18
Solution:
Simple Interest formula: $SI = \frac{P \times R \times T}{100}$
Given $SI = 135$, $R = 4.5%$, $T = 1$ year
$135 = \frac{P \times 4.5 \times 1}{100} \Rightarrow P = \frac{135 \times 100}{4.5} = 3000$
SI at 5%: $SI = \frac{3000 \times 5 \times 1}{100} = 150$
Additional interest = $150 - 135 = 15$
Answer: INR 15
Q4. A is 50% more efficient than B. B finished the same work in 20 days. If A and B worked together, how much time would they take to finish the same work?
10 days
7 days
8 days
9 days
Solution:
Let efficiency of B = 100 units
Efficiency of A = $100 + 50 = 150$ units
Efficiency ratio: $A:B = 150:100 = 3:2$
Total efficiency = $3 + 2 = 5$ units
Total work = Efficiency of B × Time taken by B = $2 \times 20 = 40$ units
Time taken by A + B = $\frac{\text{Total Work}}{\text{Total Efficiency}} = \frac{40}{5} = 8$ days
Answer: 8 days
Q5. Prasad goes 96 km on a bike at 16 km/hr, 124 km at 31 km/hr in a car, and 105 km at 7 km/hr in a horse cart. Find his average speed for the entire distance travelled.
16 km/hr
13 km/hr
7 km/hr
11 km/hr
Solution:
Total distance: $96 + 124 + 105 = 325$ km
Time taken: $t = \frac{96}{16} + \frac{124}{31} + \frac{105}{7} = 6 + 4 + 15 = 25$ hours
Average speed = $\frac{\text{Total Distance}}{\text{Total Time}} = \frac{325}{25} = 13\ \text{km/hr}$
Answer: 13 km/hr
1. Arun Sharma: A Quantitative Approach for CAT (7th Edition)
2. Quantitative Aptitude for CAT by Nishit K Sinha
The candidates can download the various CAT preparation resources designed by Careers360 using the links given below.
eBook Title | Download Links |
CAT 2025 Arithmetic Important Concepts and Practice Questions | |
CAT 2025 Algebra Important Concepts and Practice Questions | |
CAT 2025 Number System - Important Concepts & Practice Questions | |
CAT 2025 Exam's High Scoring Chapters and Topics | |
CAT Mock Test Series - 20 Sets, Questions with Solutions By Experts | |
Mastering CAT Exam: VARC, DILR, and Quant MCQs & Weightages | |
CAT 2025 Mastery: Chapter-wise MCQs for Success for VARC, DILR, Quant | |
CAT 2025 Quantitative Aptitude Questions with Answers | |
CAT 2025 Important Formulas | |
Past 10 years CAT Question Papers with Answers | |
CAT 2025 Quantitative Aptitude Study Material PDF - Geometry and Mensuration |
Frequently Asked Questions (FAQs)
Average speed in this case is equal to sum of the speeds divided by 2.
Simple average is calculated when quantities are equal. Weighted average is calculated when quantities are not equal.
Although, you can use the same formula but you need to practice each application separately so that you can get familiar with the question type.
On Question asked by student community
Hello dear candidate,
Yes, you have a very good chance of getting a BPT seat with 488 out of 600 and TS EAMCET rank of 14,000 under the ST category.
As the cut off of BPT for ST category students are generally between 25,000 to 45,000 ranks, depending upon the college and you have TS EAMCET rank of 14,000.
Thank you.
If you got 802 marks in Telangana Intermediate and belong to the ST category, you have a fair chance to get admission in a BPT course in 2025, but it depends on the college and cut-off. Most BPT colleges in Telangana ask for 12th marks in Physics, Chemistry, and Biology, and some also use the TS EAMCET rank for admission. The cut-off for ST students is usually lower than for general students, but it changes every year. It is better to check the previous year’s cut-offs of the colleges you want to apply to.
Hello, Getting shortlisted for IIM Lucknow or IIT Bombay (SJMSOM) with your profile is challenging, primarily due to your 58% in Class 10th, which significantly impacts the composite score calculation for both institutes. While your 98 percentile CAT score is excellent, and your 24 months of work experience, B.Com (Hons) background (providing academic diversity, especially for IIM-L), and KVS National player status are valuable additions, top IIMs and IITs heavily weigh consistent academic performance. Your 74% in 12th is also on the lower side. IIM Lucknow places substantial weight on 10th and 12th marks, making a call quite difficult despite your strengths. You likely have a relatively better, though still uncertain, chance at IIT Bombay, as their weighting might be slightly less penalizing for past academics compared to IIM-L, and your high CAT score is a major factor. However, the low 10th score remains a significant hurdle for both prestigious institutions.
I hope you found this information helpful and for study related queries you can ask in careers360 app, Have a great day and!
Hey,
You already have a strong profile with the score of 58% in Class 10, 74% in Class 12, and 80% in graduation, but admission in IIT Bombay, Shailesh J Mehta School of Management is quite competitive, especially if you are in general category because the cutoff for general goes to 98.5-99%. Your CAT percentage is impressive but your 10th marks might reduce your score during the shortlisting process. If you perform well in Written Ability Test and Personal Interview, and present your commerce background you still stand a fair chance. But it would also be wise if you have some backups like MDI Gurugram, IMT Ghaziabad, IMI Delhi, where your marks and profile will fit well in their selection range.
HELLO,
I am providing you the link below through which you will be able to download the previous 10 years CAT question papers
Here is the link :- CAT Previous year Question papers
Hope this Helps!
Directions for question :
M/s Deloitte Touche Tohmatsu Limited, one of the top four audit and accounting firms in the world with headquarters at London, UK, and with an operational presence in 153 countries, hires Management Trainees (MT) from all the premier management institutes of India thrice every year, in the months of January, May and September.
Each new group of Management Trainees (MT) have to go through a four month rigorous training schedule, after which they have to pass through a test consisting of a written assessment and a case-analysis. The top hundred ranked Management Trainees (MT) based on the performance in the test are confirmed as Management Executives (ME). The rest are given the opportunity of undergoing the training for four months one more time along with the next batch of Management Trainees (MT) and then passing through the subsequent test consisting of the written assessment and case-analysis. The Management Trainee (MT) who fails to get confirmed as a Management Executive (ME) the second time is fired.
The scatter-graph below depicts the number of Management Trainees (MT) at Deloitte taking the tests from January 2020 till May 2022, and the vis-à-vis hired Management Trainees (MT) at Deloitte who were fired :
It is also known that for the month of September 2019 at Deloitte, 96 hired Management Trainees (MT) failed to be confirmed as a Management Executive (ME) the first time, and that 36 hired Management Trainees (MT) were fired.
Question :
In which test did the minimum number of Management Trainees (MT) get confirmed as a Management Executive (ME) in the second attempt ?
September 2020
May 2021
January 2021
January 2022
Directions for question:
The bar-graph given below shows the foreign exchange reserves of Nepal (in million Rupees) from 2014 to 2021. Answer the following questions based on the graph :
Question:
What was the percentage increase (rounded to the nearest integer, if deemed necessary) in the foreign exchange reserves in 2020 over 2016 ?
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