2 Questions around this concept.
In ABC, if $\angle$B = 90° and D is the midpoint of BC, then AC2 = AD2 + 3CD2. (True/False)
Some Important Results
1. If ∆ABC is a right angle triangle with right-angled at B such that BD ⊥AC, DM ⊥ BC, and DN ⊥ AB.
Then,
2. If ABC is a triangle in which ∠ ABC < 90° and AD ⊥ BC. Then, AC2 = AB2 + BC2 – 2 BC · BD.

3. If AD is a median of a triangle ABC and AM ⊥ BC.

Then,
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