4 Questions around this concept.
In the given figure, AB is parallel to CD, Then the value of measure of x is
Theorem 4 : If a transversal intersects two parallel lines, then each pair of interior angles on the same side of the transversal is supplementary.
A transversal t cuts parallel lines AB and CD at point E and F respectively and forming two pairs of consecutive interior angles, namely (∠3, ∠6) and (∠4, ∠5).
We have to prove ∠3 + ∠6 = 180° and ∠4 + ∠5 = 180°
Since ray EF stands on line AB,
we have, ∠3 + ∠4 = 180° [linear pair angles]
but, ∠4 = ∠6 [Alternate interior angles]
Therefore, ∠3 + ∠6 = 180°
In simmilar way we can show that ∠4 + ∠5 = 180°
Theorem 5 : If a transversal intersects two lines such that a pair of interior angles on the same side of the transversal is supplementary, then the two lines are parallel.
A transversal t, cuts two lines AB and CD at E and F respectively such that ∠4 + ∠5 = 180°.
We need to prove, AB is parallel to CD.
Since ray EB stands on line t,
we have: ∠1 + ∠4 = 180° [linear pair angle]
and, ∠4 + ∠5 = 180° [given]
therefore, ∠1 + ∠4 = ∠4 + ∠5
this gives, ∠1 = ∠5
But, these are corresponding angles. So AB is parallel to CD.
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