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5 Questions around this concept.
In the adjoining figure, the value of y is (AOB is straight line)
Two lines AB and CD intersect at O. If then measure of is
Vertically Opposite Angles: When two lines intersect, then the angles having their arms in the opposite direction are called vertically opposite angles. The pair of vertically opposite angles is equal.
One pair is ∠AOD and ∠BOC. and another pair is ∠AOC and ∠BOD.
Theorem 1 : If two lines intersect each other, then the vertically opposite angles are equal.
Let two lines AB and CD intersect at a point O. Then, two pairs of vertically opposite angles are formed:
(i) ∠AOC and ∠BOD (ii) ∠AOD and ∠BOC.
We need to prove that ∠AOC = ∠BOD and ∠AOD = ∠BOC..
Since ray OA stands on line CD, we have
Therefore, ∠AOC + ∠AOD = 180° [linear pair].
Again, ray OD stands on line AB
So, ∠AOD + ∠BOD = 180° [linear pair].
From above 2 equation, we can write
∠AOC + ∠AOD = ∠AOD + ∠BOD
his implies that ∠AOC = ∠BOD
Similarly, it can be proved that ∠AOD = ∠BOC.
Remark:
The sum of all the angles formed on the same side of a line at a given point on the line is 180°.
The sum of all angles around a point is 360°.
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