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CAT Quantitative Aptitude Shortcut Methods

CAT Quantitative Aptitude Shortcut Methods

Edited By Team Careers360 | Updated on May 22, 2024 07:29 PM IST | #CAT

The Common Admission Test (CAT) is the gateway to the world of management for a student in India. The question paper is prepared by the top IIMs (Indian Institutes of Management) of the country every year. CAT exam easily creates a niche for itself among the top admission tests of the country’s academia. In this article, you’ll find some CAT Quantitative Aptitude shortcut methods that will be helpful for those preparing for the CAT 2024 exam.

CAT Quantitative Aptitude Shortcut Methods

Using quant shortcut methods can increase the chances of getting a good score in the Quantitative Aptitude section of the CAT 2024 exam. These CAT Quantitative Aptitude shortcut methods save time by making candidates rely less on the on-screen calculator and long-drawn calculations. In this article you'll find CAT number system shortcut tricks, arithmetic shortcut tricks, algebra shortcut tricks, and shortcut tricks from other CAT QA topics.

So make use of the CAT shortcut methods given in the article and don’t forget to practice questions daily.

CAT 2024 Exam Pattern

There are basically 3 sections in CAT Examination, which are:

Section

No. of Q’s

Time

A. Verbal Ability and Reading Comprehension

24

40 min.

B. Data Interpretation and Logical Reasoning

20

40 min.

C. Quantitative Ability

22

40 min.

Total

66

120 min. (2 hr.)

Each correct answer fetches 3 marks. Hence the total marks of the examination are 66 x 3 = 198. To achieve a good score in this section, it is important to solve questions quickly and accurately, and CAT Quantitative Aptitude Shortcut Methods or Shortcut Tricks for CAT Quant 2024 are quite helpful.

CAT Quantitative Aptitude section: An overview

CAT QA Syllabus

The syllabus of CAT exam is only what we have studied in our schools till the tenth standard. However, no specific syllabus exists. But for a better understanding of the CAT Quantitative Aptitude syllabus, we can refer to the following table:




Arithmetic

1. Percentage (Basics and related questions)

2. Ratios (Basics and related concepts i.e. Proportion and Variation)

3. Averages (Basics and related concepts i.e. Mixtures & Alligation)

4. Profit & Loss

5. Simple and Compound Interest

6. Time, Speed and Distance

(Questions related to Trains, Boats, Circular track etc.)

7. Time & Work


Number System

1. Numbers and their classification i.e. Prime numbers, rational numbers, fractions, integers etc.

2. Divisibility Rule

3. Factorization of Numbers

4. LCM & HCF related questions



Geometry

1. Lines and angles

2. Triangles (area, similarity, congruency etc.)

3. Circles

4. Quadrilaterals (Rectangle, square, trapezium)

5. Mensuration (Area and volume of 2D and 3D figures)

6. Trigonometry

7. Co-ordinate Geometry


Algebra

1. Advance Linear Equations

2. Quadratic Equations

3. Inequalities & Modulus

Miscellaneous

1. Permutation & Combination

2. Probability


Why are shortcut methods important for the CAT exam?

The Quantitative Aptitude section’s weightage is 66 marks out of a total of 198 marks. For good percentiles, score must be as follows (as per a review of previous exams):

1. Score > 33 = 99+ percentile {Attempts must be at least 14 with high accuracy}

2. Score > 24 = 95+ percentile {Attempts must be at least 10 with high accuracy}

3. Score > 18 = 80+ percentile {Attempts must be at least 7 with high accuracy}

The total time for this section is 40 min., so if the target score is more than 99 percentile, then for each question we get less than 3 min. and if the target score is more than 95 percentiles then we get around 4 min. for each question. In this time, we have to read, understand, and solve the question which is impossible to do without using the right approach and shortcut methods. Let’s understand how we can save time using Quantitative Aptitude Shortcut Techniques for CAT Exam:

CAT Number System Shortcut Tricks

Generally, 2-3 questions are asked from this section directly in the CAT Exam, but concepts of the number system are important to solve questions related to other sections i.e. algebra and arithmetic. Some CAT Quantitative Aptitude Shortcut Methods related to the number system are as under:

Divisibility rules

Understanding Divisibility rules is important to know whether any number is divisible by a divisor or we are wasting time in simplification, for ex: N= 37895; N/9; the rule of divisibility of 9 is that if the sum of digits of the dividend (N) is divisible by 9 then the number is also divisible by 9. In this example, sum of digits of N is 3+7+8+9+5 = 32, 32 is not divisible by 9 so there is no need to divide the number.

Let’s understand another shortcut method out of Shortcut Tricks for CAT Quant 2024:

? If ‘abcabc’ / 1001 then ans is ‘abc’. If a number is in the form of ‘abcabc’ then we can say that the number is definitely divisible by 1001 and its factors which are 3,7 & 11.

Ex: N = 325325 / 1001 = 325.

Prime factorization technique

Prime factorization is important while solving questions related to LCM & HCF and basic numbers questions related to the divisibility rule and classification of numbers. Let’s understand a shortcut method out of Shortcut Tricks for CAT Quant 2024:

? While factorization, always break the no. in big numbers.

Ex: N= 240 = 2 x 120 = 2 x 2 x 60 = 2 x 2 x 2 x 30 [ This is time taking]

Or N = 240 = 16 x 15 = 24 x 3 x 5

Simplification techniques

To simplify the calculation while solving questions related to the CAT Exam, simplification by short methods can save a great amount of time, let’s understand this with the help of the following example:

Simplification of fractions or how to cancel out -

ex: (50 x 35 + 28 x 25) / (75x30 + 60 x 15)

M-1

(1750+ 700) / (2250+900) = 2450/3150 = 245/315 = 49/63 = 7/9

M-2 [Take common if possible- it will save time or effort]

25 x 7 (2 x 5 + 4 x1) / 15 x 30 (5 x1 + 2 x 1) = 25 x 7 x 14 / 15 x 30 x 7 = 7/9

(Cancel out as much as possible rather than multiplication, this will make calculation easy)

Squaring and cubing numbers

Vedic Mathematics Tricks are most important to make the calculation part easy. One should learn squares from 1-25 (at least) and cubes from 1-12 (at least) which are helpful to find the squares and cubes of greater numbers. We can understand this from the following general approaches which are out of shortcut methods to find squares and cubes.

Square of 2-digit numbers:

To find the square of a two-digit number you can use the following method which is a general method for all such numbers:

N = ‘ab’ [ wherein b-unit digit and a-tens digit]

N2 = a (‘ab’ + b) / b2

Ex: (i) 312 = 3(31+1)/ 12 = 3(32)/1 = 96/1 = 961

(ii) 472 = 4(47+7)/ 72 = 4(54)/ 49 = 216/49 = 216+4/9 = 220/9 = 2209

[Note: If there are 2 digits in the second part then the ten’s digit will be added to the first part]

Square of 3-digit numbers:

To find the square of a 3-digit number you can use the following method which is a general method for all such numbers:

N = ‘abc’ [ wherein c-unit digit, b-tens digit and a-hundreds digit]

N2 = a (‘abc’ + ‘bc’) / ‘bc’2

Ex: (i) 3012 = 3(301+1)/ 012 = 3(302)/01 = 906/01

= 90601

Note: [There must be only two digits in the second part, if we get only one digit after squaring then we have to write zero before digit i.e.1 as 01 and if we get more than two digits then we have to add hundreds digit in the first part like following example]

(ii) 1172 = 1(117+17)/ 172 = 1(124)/ 289 = 124+2/89 = 126/89 = 12689

This approach will save time if the numbers are close to multiples of hundred like 301, 407, 119 etc. For different type of numbers, we use different approaches to save time.

CAT Arithmetic Shortcut Tricks

The arithmetic section is basically the combination of three basic concepts (Percentage, Ratio & proportion, Average) and their applications in different ways. In the CAT Exam, out of 22 questions, generally, 8-9 questions are asked from the arithmetic section. The basics of simple equations and calculations are the base for solving arithmetic questions. Following are some shortcut methods related to arithmetic section:

Addition and subtraction shortcuts:

Addition and subtraction are the base of the calculation part. To improve our calculation, we can work over some basic techniques related to addition and subtraction, let’s understand this with the help of some examples (practice these without pen and paper):

Addition Techniques:

  1. If we have to add 8 or 9 in any number, then we can use 8 as 10-2 and 9 as 10-1 because addition of 10 in number is very simple.

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Ex: (i). 28+8 = 28+10-2 = 38 -2 = 36

(ii). 36+9 = 36+10-1 = 46 -1 = 45

  1. If we have to add 2-digit number in any number then break the number and add in two parts.

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Ex: (i). 87 + 65 = 87+ 60 + 5 = 147 + 5 = 152

[now after breaking the number, adding 60 to 87 is easy as we have to add tens digit i.e. 6+8 = 14]

Subtraction Techniques:

  1. If we have to subtract 8 or 9 from any number, then we can use 8 as 10-2 and 9 as 10-1 because subtraction of 10 from any number is very simple.

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Ex: (i). 29 - 8 = 29-(10-2) = 29-10+2 = 19+2 = 2 [ for 8 firstly subtract 10 and then add 2 ]

(ii). 36-9 = 26 + 1 = 27 [ for 9 firstly subtract 10 and then add 1]

(iii). 57-8 = 47 + 2 = 49

Multiplication techniques (Vedic Mathematics, Grid Multiplication)

Multiplication is the most used part during calculation, if we can multiply greater numbers easily then we can save time and energy, for this let’s understand a shortcut method for multiplication by using Vedic Maths:

Column II I step1: Multiply column I step 2: cross multiplication

4 2 2 4 2

X 6 3 X3 6 3

----------- -----------

6 (4 x 3) + (6 x 2) + add carry from column 1 if

any = 24 {carry forward 2}

step3: Multiply column II – 4

x 6

------------

24 + add carry from step 2 if any = 24 + 2 = 26

Now start writing result of every step (after removing carry) from step-3 to step-1

= 26/4/6 = 2646 ans.

Division shortcuts

Division is the most hectic part of the calculation. By using some shortcut techniques, we can save effort. For eg: 1/5 = 2/10; 1/25 = 4/100; 1/125 = 8/1000, let’s understand how we can use these fractions:

(i) 523/5 = 523 x 2 / 10 = 1046 / 10 = 104.6

[As we can experience that multiplication of 2 is much easier than division by 5]

(ii) 728 / 25 = 728 x 4 / 100 = 2912 / 100 = 29.12

[As we can experience that multiplication of 4 is much easier than division by 25]

(iii) 523 / 125 = 523 x 8 / 1000 = 4184 / 1000 = 4.184

[As we can experience that multiplication of 8 is much easier than division by 125]

Percentage calculations

To solve the percentage questions efficiently by using shorter methods for saving time, focus on the following points:

  1. Learn and practice the ready reference of conversion which are asked frequently, for ex: 25% = ¼, 33.33% = 1/3 (simplest conversion) but for exam like CAT we have to learn some difficult ones for ex: 1/19 = 5.26%, 18.18% = 2/11 etc. [ Don’t worry about these, by proper techniques we can learn these in 1 day but for efficiency we have to keep revising these].

  1. We have to learn 3 concepts

a. Multiplication factor (M.F.)

Ex: A has 200 Rs. And B has 30% more than A, then B = 200 x 1.3 = 260 Rs.

b. Successive % change

c. Reverse percentage comparison.

Time, speed, and distance shortcuts

Time, speed and distance (T.S.D) is basically the application of percentage and ratio (using variation). In this section, most of the questions require shortcut methods and good knowledge of percentages and ratio. Let’s understand this with the help of a shortcut method:

Ex:

Que: If a person drives with the speed of 7 km/hr. from his house to office then he reaches 10 min late but if he starts at the same time from his house with the speed of 8 km./hr. then he reaches to the office 5 min. early. Find the distance between his house and office.

Ans: If we solve it by basic method then it will take around 5-6 min. but with the help of a formula we can solve this within 30 sec.-

Let S1 = 7 km/hr. and S2 = 8 km/hr.; Given: Time difference of both conditions = 15 min. = ¼ hr.

Then D = S1 x S2 x time difference / speed difference = 7 x 8 x 1/ 4 x 1 = 14 km.

Time and Work problem-solving methods

Time and Work is also an application of ratio. In this section, most of the questions are solved by using the LCM method which is a shortcut method for these types of questions which is less time taking than basic arithmetic approach. Let’s understand this with the help of a shortcut method:

Ex: A can do a piece of work in 8 days. B can do the same in 14 days. In how many days can the work be completed if A and B work together?

Solution: TA = 8 days; TB = 14 days

Let total work to be done= LCM (TA, TB) = LCM (8,14) = 56

W = 56 units

A can do = ⁵⁶⁄₈ = 7 units/day

B can do = ⁵⁶⁄₁₄ = 4 units/day then, (A + B) together can do = 11 units per day

So, no. of days taken by (A + B) to complete the same work is = ⁵⁶⁄₁₁ days

CAT Algebra Shortcut Tricks

In Algebra section basically, we deal with variables and their properties. In Quantitative Aptitude section out of 22 questions 7-8 questions are asked from this section. Some CAT Quantitative Aptitude Shortcut Methods related to algebra section are as under:

Simplification of algebraic expressions

To simplify the algebraic equations, you must learn algebraic identities. Let’s understand how to use identities as shortcut methods to solve the questions easily.

Ex: (x2 – 3) (x2 + 3) [ We can use identity to solve that i.e. (a-b) (a+b) = a2 – b2]

= (x4 - 32) = (x4 - 9)

Factorization techniques

A quadratic equation typically takes the form ?2+??+?=0; where a,b,c are constants, and ?≠0. The goal of factorization is to express the quadratic as a product of two linear factors. Let’s understand a shortcut method rather than basic factorization method:

? If, in a quadratic equation ?2+??+?=0, (b/2)2=c then factors are (x + b/2)2= 0.

Ex: ?2+6?+9= 0; we can notice that (b/2)2=c then factors are (?+3)2=0.

Algebraic identities

Algebraic identities are useful to solve not only quadratic questions but also for calculation. Let’s understand this with a simple identity which is (a-b) (a+b) = a2 – b2 .

Ex: 42 x 38 = (40 + 2) (40 – 2) [This method is very useful for solving such multiplication]

= 402 – 22 = 1600 – 4 = 1596

CAT Geometry Shortcut Tricks

Geometry section is basically all about the properties related to different shapes. In Quantitative Aptitude section 3-4 questions are asked out of 22 questions from this section. Some CAT Quantitative Aptitude Shortcut Methods related to geometry are as under:

Pythagorean triplets and their applications

Pythagoras theorem states that, in a right triangle, the square of the hypotenuse is equal to the sum of the square of the other two sides i.e. H2 = Base2 + Height2.

Pythagorean triplet is a shortcut method out of Quantitative Aptitude Shortcut Techniques for CAT Exam where we can find side without using Pythagoras theorem. There are some fix pairs which defines the sides of right-angle triangle i.e. (3,4,5- 5 is hypotenuse and 3,4 are other two sides), (6,8,10), (8,15,17) etc.

[Note: Greatest side in triplets is hypotenuse]

Ex: If base = 15, height = 8 (given), then we can say that hypotenuse = 17 without using Pythagoras theorem

Tricks for solving geometry problems quickly

Geometry questions are lengthy and time-consuming. To solve these questions, we require shortcut methods. Let’s understand a shortcut method out of CAT Quantitative Aptitude Shortcut Methods:

Ex: If side of an equilateral triangle ABC is 6 cm. then find the circumradius(R) of triangle ABC.

Solution:

M-1

Formula to find circumradius of a triangle is R= product of sides of triangle / 4x area of triangle

M-2

But we can directly find the circumradius of equilateral triangle with this shortcut:

R = side/ √3 = 6 / √3 = 2 √3 Ans.

CAT Mensuration Shortcut Tricks

Mensuration section is related to area and volumes of 2D and 3D shapes. At least 1 question is asked from this section in all competitive exams including CAT. Let’s understand some basics and Quantitative Aptitude Shortcut Techniques for CAT Exam related to this section as under:

Formulas for calculating area and volume of basic shapes

Knowledge of basic formulas is must to solve the questions and to apply shortcut methods properly. Some basic formulas which are used as shortcut methods are as under:

1. Area of parallelogram = Base x Height

Ex: In a parallelogram, base = 10 and height = 6 then area = 10 x 6 = 60

Shortcut methods for complex shapes

Polygons more than 4 sides are considered as complex shapes. Out of polygons, regular hexagon is mostly asked in the CAT Examination. Let’s understand some shortcut formulas to solve problems related to complex shapes:

Ex: If side of a regular hexagon is 8 cm. then find area and circumradius of the shape.

Solution: Area = 3√3 x square of side = 3√3 x 8 = 24√3 square cm.

Circumradius (R) = 2 x side = 2 x 8 = 16 cm.

Surface area and volume calculation tricks

To find the area and volume of 3D shapes is bit lengthy than that of 2D shapes. But the base formula for some 3D shapes are same. For Cube, Cuboid and Cylinder (these shapes come under prism shapes) we can use a general formula to find area and volume which is as under:

Area = Perimeter of Base x Height

Volume = Area of Base x Height

Let’s understand how we can make formulas by using this single formula. In Cylinder, base is circular, let the radius of circular base is r and height of cylinder is h, then:

Area = Perimeter of Base (Circle) x Height = 2πr x h = 2πrh

Volume = Area of Base (Circle) x Height = πr2 x h = πr2h

CAT Trigonometry Shortcut Tricks

Trigonometry is all about measurements related to triangles. Trigonometry is used to find sides using ratios and angles in any polygon by breaking the shape in triangles. Let’s understand some shortcut techniques out of Quantitative Aptitude Shortcut Techniques for CAT Exam:

Shortcut methods for trigonometric ratios

To remember the trigonometric ratios is difficult but we can learn that using a shortcut method which we used to learn in tenth class.

Sin θ=P/H; Cos θ=B/H; Tan θ= P/B [ where P=perpendicular, B=base, H=hypotenuse]

To learn this, we can use a quote, “Pandit(P) Badri(B) Prasad(P) /Har(H) Har(H) Bole(B)” = PBP/HHB

sin θ cos θ tan θ

P B P

-----------------------

H H B

These trigonometric ratios and Pythagoras theorem are used to make trigonometric identities i.e. sin2 θ + cos2 θ = 1; which are used to solve more questions quickly.

Trigonometric equations solving techniques

To simplify trigonometric equations, we can simply convert any trigonometric ratio in terms of sin θ & cos θ or we can use any other identity:

Ex: If tan θ + sec θ = 3 then find sin θ.

Solution:

M-1 tan θ = sin θ/ cos θ; sec θ = 1/ cos θ

From given equation? sin θ/ cos θ + 1/ cos θ = 3

sin θ. cos θ + 1 = 3 cos θ

Now we can further solve this question by using the basic identity sin2 θ + cos2 θ = 1.

M-2 sec θ - tan θ = 1/ (sec θ + tan θ) [A result derived from identity sec2θ = tan2θ + 1]

Given: sec θ + tan θ = 3 …. Eq-1

So we can say sec θ - tan θ = 1/3 …...Eq-2

Now sin θ can be easily find out by solving both equations

Applications of trigonometry in geometry problems

Trigonometry is used to find sides and angles while solving geometry problems.

Ex: In triangle ABC, side AB= 10cm., BC= 7 cm. if angle B = 30 degree then find area of the triangle.

Solution: Area of the triangle = ½ x AB X BC X Sin B = ½ x10 x7 x sin 30 = ½ x 70 x ½ = 17.5

CAT Shortcut Tricks For Other Topics

Probability shortcuts techniques

Probability is occurrence chances of any event. The most important thing to keep in mind that the value of probability of any event can’t be more than 1 and less than 0.

Probability = Favorable outcomes of any event / Total possible outcomes of the event

Let’s understand some shortcut methods to find total possible outcomes of any event:

1. If n coins are tossed simultaneously then total no. of outcomes = 2n

Ex: If 3 coins are tossed simultaneously then total no. of outcomes = 23 = 8

2. If n dices are rolled simultaneously then total no. of outcomes = 6n

Ex: If 2 dices are rolled simultaneously then total no. of outcomes = 62 = 36

Permutation and combination shortcut techniques

Permutation and combination are somehow base of probability. In this section, we learn about finding all possibilities of any event. Let’s understand some shortcut methods to solve questions related to P & C:

Ex: In how many ways 5 letters can be posted in 3 letter boxes.

Solution:

Here letters have choice to choose in which letter box they will be posted as per address. So, no. of letters is considered as N and no. of letter boxes are considered as R.

So total no. of ways = RN = 35 = 243 ans.

Practice and Application

CAT Quantitative Aptitude Important Topics


Topics

Time and Work

Interests (SI, CI)

Time, Speed, and Distance

Probability

Geometry & Mensuration

Number System, Basic Arithmetic

Algebra

Permutation & Combination

Profit, loss, and Discounts

Trigonometry, Logarithms, and Sets


CAT Shortcut Tricks: Importance of regular practice

The complexity and intensity of the exam demand a strategic and consistent preparation approach, where regular practice plays a critical role. The CAT exam not only tests your knowledge but also your ability to apply that knowledge quickly and accurately. Frequent practice enables you to increase your speed and improve your accuracy, reducing careless mistakes and enhancing your ability to solve problems under time constraints by using different shortcut methods that you have mastered with regular practice.

Solving previous years' CAT questions using shortcut methods

Solving CAT previous year question papers helps you to understand the type of questions and approach required to solve the questions. If you have the right approach and shortcut methods to solve the questions then a great score can be achieved in the exam. To achieve the desired score and dream IIM, you have to try to learn the shortcut methods as per the requirement of the exam and you have to practice them as much as you can in CAT mock tests and previous year questions.

CAT mock test practice with time management strategies

Through continuous practice, you can identify which types of questions you are strong or weak in, allowing you to develop personalized strategies. For example, deciding which questions to attempt first, and which ones to skip helps in time management. Time management is crucial in the CAT exam since all sections are timed, and you need to balance speed with the thoroughness of your answers. The length of the CAT exam requires mental stamina to maintain focus and concentration throughout the test. Regular practice sessions that mimic the length and intensity of the actual exam can help build this stamina.

Conclusion

To achieve a great score in an exam like the CAT you have to practice the Quantitative Aptitude Tricks & Shortcuts for the CAT exam, multiple times and have to understand the exam pattern so a specific strategy can be made. A smart approach is the key to clear the CAT Exam.

Download Free Practice Questions with Detailed Solutions for CAT Exam - MCQ PDFs

CAT QA Questions with Answers

TITLE

STUDY LINKS

NUMBER SYSTEMS SET 1

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NUMBER SYSTEMS SET 2

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RATIO, PROPORTION & VARIATION SET 1

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RATIO, PROPORTION & VARIATION SET 2

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PERCENTAGES SET 1

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PERCENTAGES SET 2

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PROFIT, LOSS & DISCOUNT SET 1

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PROFIT, LOSS & DISCOUNT SET 2

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INTEREST SET 1

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INTEREST SET 2

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AVERAGES AND MIXTURES SET 1

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AVERAGES AND MIXTURES SET 2

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TIME, SPEED & DISTANCE SET 1

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TIME, SPEED & DISTANCE SET 2

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TIME & WORK SET 1

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TIME & WORK SET 2

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POLYNOMIALS SET 1

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POLYNOMIALS SET 2

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EQUATIONS SET 1

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EQUATIONS SET 2

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FUNCTIONS SET 1

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FUNCTIONS SET 2

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SEQUENCE & SERIES SET 1

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SEQUENCE & SERIES SET 2

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GEOMETRY SET 1

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GEOMETRY SET 2

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MENSURATION SET 1

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MENSURATION SET 2

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PERMUTATIONS AND COMBINATIONS SET 1

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PERMUTATIONS AND COMBINATIONS SET 2

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PROBABILITY SET 1

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PROBABILITY SET 2

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SET THEORY SET 1

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SET THEORY SET 2

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COORDINATE GEOMETRY SET 1

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COORDINATE GEOMETRY SET 2

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TRIGONOMETRY SET 1

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TRIGONOMETRY SET 2

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LOGARITHM AND SURDS SET 1

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LOGARITHM AND SURDS SET 2

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STATISTICS SET 1

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STATISTICS SET 2

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CAT VARC Questions with Answers


TITLE

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READING COMPREHENSION SET 1

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READING COMPREHENSION SET 2

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PARA JUMBLES SET 1

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PARA JUMBLES SET 2

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PARACOMPLETION SET 1

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PARACOMPLETION SET 2

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PARASUMMARY SET 1

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PARASUMMARY SET 2

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ODD ONE OUT/MISFIT SENTENCE SET 1

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ODD ONE OUT/MISFIT SENTENCE SET 2

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CAT DILR Questions with Answers

TITLE

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ANALYTICAL PUZZLES SET 1

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ANALYTICAL PUZZLES SET 2

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BAR GRAPHS SET 1

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BAR GRAPHS SET 2

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BINARY LOGIC SET 1

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BINARY LOGIC SET 2

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BLOOD RELATIONS SET 1

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BLOOD RELATIONS SET 2

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CASELETS SET 1

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CASELETS SET 2

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CUBES AND DICING SET 1

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CUBES AND DICING SET 2

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DECISION MAKING SET 1

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DECISION MAKING SET 2

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GAMES AND TOURNAMENTS SET 1

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GAMES AND TOURNAMENTS SET 2

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INNOVATIVE GRAPHS SET 1

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INNOVATIVE GRAPHS SET 2

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LINE GRAPHS SET 1

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LINE GRAPHS SET 2

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LINEAR AND CIRCULAR ARRANGEMENT SET 1

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LINEAR AND CIRCULAR ARRANGEMENT SET 2

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LOGICAL DEDUCTIONS AND CONNECTIONS SET 1

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LOGICAL DEDUCTIONS AND CONNECTIONS SET 2

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ORDERING AND SEQUENCING SET 1

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ORDERING AND SEQUENCING SET 2

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PIE CHARTS SET 1

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PIE CHARTS SET 2

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RADAR GRAPHS SET 1

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RADAR GRAPHS SET 2

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REASONING BASED DI SET 1

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REASONING BASED DI SET 2

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ROUTES AND NETWORKS SET 1

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ROUTES AND NETWORKS SET 2

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SCATTER GRAPHS SET 1

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SCATTER GRAPHS SET 2

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SELECTIONS AND DISTRIBUTIONS SET 1

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SELECTIONS AND DISTRIBUTIONS SET 2

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SYLLOGISM SET 1

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SYLLOGISM SET 2

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TABLE BASED DI SET 1

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TABLE BASED DI SET 2

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VENN DIAGRAMS SET 1

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VENN DIAGRAMS SET 2

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Frequently Asked Question (FAQs)

1. What topics are covered in the Quantitative Ability section?

The CAT QA section covers the following topics:

  • Percentage

  • Ratios

  • Averages

  • Profit & Loss

  • Simple and Compound Interest

  • Time, Speed and Distance 

  • Time & Work

  • Numbers and their classification

  • LCM & HCF 

  • Lines and angles

  • Triangles

  • Circles

  • Quadrilaterals

  • Mensuration

  • Trigonometry

  • Co-ordinate Geometry

  • Advance Linear Equations

  • Quadratic Equations

  • Inequalities & Modulus

  • Permutation & Combination

  • Probability

2. How many questions are typically in the Quant section, and what is the time limit?

The Quant section has a total of 22 questions with a sectional time limit of 40 minutes.

3. How should I prepare for the Quant section?
  • Go through the CAT QA syllabus and understand the exam pattern. Start by revising basic concepts.

  • Take the help of online or offline tutors if you’re weak in maths. A thorough understanding of basic concepts is necessary.

  • Practice questions from CAT QA books, sample papers and PYQs regularly.

  • Don’t forget to revise the concepts that you have studied.

  • Take mock tests regularly to gauge your performance and analyze the mocks to identify your strengths and weaknesses. Work on weak areas accordingly.

4. Are CAT shortcut methods reliable?

Yes, if you use shortcut methods correctly then they are reliable. For this, you should practice a lot using shortcut methods to improve your accuracy and speed.

5. How to practice questions using shortcut methods?

You can start practicing with LOD 1 (Level of Difficulty 1) questions. Once you get comfortable with the methods, move to sample papers and CAT PYQs. Solve a lot of questions from each topic.

6. What can I do to solve quantitative aptitude questions quickly?

First and foremost, you should be completely well-versed in the basics of each topic. Important formulas and calculation shortcut methods should all be memorized by practicing questions consistently. Set a timer to check how much time you take to solve each question and focus on the ones that take the most time. 

7. Is the CAT quantitative aptitude section easy?

The CAT QA section is not considered easy by students. The difficulty level is moderate to high. But with solid preparation and adequate practice, this section can be tackled.

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Questions related to CAT

Have a question related to CAT ?

Hello aspirant,
The CAT exam syllabus is not officially prescribed, but it generally includes topics from the following sections:

1. Verbal Ability and Reading Comprehension (VARC)
2. Data interpretation and logical reasoning
3. Quantitative ability

  • Arithmetic

  • Algebra

  • Geometry and Mensuration

  • Number System

  • Modern Math

It seems unlikely that you would be able to get admission in the BTech CS branch at BIT Sindri or Mesra with a CML rank of 2058 and category rank of 433.

Key points:

1. The search results indicate that a CML (Common Merit List) rank of 2058 is quite low for admission to premier engineering colleges like BIT Sindri or NIT Mesra.

2. The cutoff ranks for BTech CS branch at these institutes are usually much higher, often in the range of 1000-2000 for the general category.

3. With a category rank of 433, you may have a better chance of getting admission in the reserved category quota, but the competition is still quite high.

4. The search results do not provide specific cutoff details for BIT Sindri or NIT Mesra, but the general trend suggests your current ranks may not be sufficient for the CS branch in these institutes.

My advice would be to:

1. Check the latest cutoff ranks and admission criteria on the official websites of BIT Sindri and NIT Mesra.

2. Explore other options like state-level engineering colleges or NITs where your current ranks may have a better chance of securing admission.

3. Consider improving your performance in the next attempt of the entrance exam to increase your chances of getting into your desired BTech program.



For VARC, read daily from diverse sources (newspapers, novels, journals) to improve comprehension and vocabulary. Practice RC passages and verbal ability questions regularly. For DILR (Data Interpretation and Logical Reasoning) and QA (Quantitative Aptitude), solve previous years' papers and take mock tests to identify weak areas. Join a coaching institute or online courses for guidance and stay consistent with your study schedule. Review and analyze your performance in mocks to understand mistakes and improve. Maintain a positive mindset and stay disciplined in your preparation.

Hello aspirant,

Every year, IIMs conduct the Common Admission Test (CAT), a national MBA entrance exam, in rotation. For admission to over 1,200 institutions and premier B-schools in India, as well as PGDM, Executive MBA, PhD, and FPM programmes, the IIM CAT exam is regarded as one of the most difficult MBA entrance exams to pass. One of the best MBA schools in India, IIMs offers PGDM and MBA programmes for students who pass the CAT exam with scores in the 82nd to 99th percentiles.

For complete information you can visit our website by clicking on the link given below.

https://bschool-careers360-com.cdn.ampproject.org/v/s/bschool.careers360.com/exams/cat/amp?amp_gsa=1&amp_js_v=a9&usqp=mq331AQIUAKwASCAAgM%3D#amp_tf=From%20%251%24s&aoh=17204523672625&csi=1&referrer=https%3A%2F%2Fwww.google.com&ampshare=https%3A%2F%2Fbschool.careers360.com%2Fexams%2Fcat

Thank you

Hope this information helps you.

Hello!

The educational qualification required for CAT exam is bachelor's degree or its equivalent from a recognized university with minimum of 50% for the open category and 45% for the SC/ST/PwD category. Since you have secured more than the required percentage in your bachelor's degree, you are eligible for CAT exam.

For more information, please visit the website by clicking on the link given below:

https://bschool.careers360.com/articles/cat-eligibility-criteria

I hope you will find this information helpful. Best wishes ahead!

View All

1-radian measures 600. (True/False)

Option: 1

True


Option: 2

False


$111111^2$ = 

Option: 1

123456654321


Option: 2

123454321


Option: 3

123454321


Option: 4

12345654321


1111112 =___________ 

Option: 1

 123456654321


Option: 2

1234554321


Option: 3

123454321


Option: 4

12345654321


159702 is divisible by

Option: 1

7


Option: 2

9


Option: 3

11


Option: 4

6


1600 satellites were sent up by a country for several purposes. The purposes are classified as broadcasting (B), communication (C), surveillance (S), and others (O). A satellite can serve multiple purposes; however a satellite serving either B, or C, or S does not serve O. 

The following facts are known about the satellites: 

1. The numbers of satellites serving B, C, and S (though may be not exclusively) are in the ratio 2: 1:1. 

2. The number of satellites serving all three of B, C, and S is 100. 

3. The number of satellites exclusively serving C is the same as the number of satellites exclusively serving S. This number is 30% of the number of satellites exclusively serving B. 

4. The number of satellites serving O is the same as the number of satellites serving both C and S but not B. 

Question:

What best can be said about the number of satellites serving C? 

Option: 1

Must be between 450 and 725 

 


Option: 2

Cannot be more than 800 
 


Option: 3

Must be between 400 and 800 

 


Option: 4

Must be at least 100 


1600 satellites were sent up by a country for several purposes. The purposes are classified as broadcasting (B), communication (C), surveillance (S), and others (O). A satellite can serve multiple purposes; however a satellite serving either B, or C, or S does not serve O. 

The following facts are known about the satellites: 

1. The numbers of satellites serving B, C, and S (though may be not exclusively) are in the ratio 2: 1:1. 

2. The number of satellites serving all three of B, C, and S is 100. 

3. The number of satellites exclusively serving C is the same as the number of satellites exclusively serving S. This number is 30% of the number of satellites exclusively serving B. 

4. The number of satellites serving O is the same as the number of satellites serving both C and S but not B. 

Question:

What is the minimum possible number of satellites serving B exclusively? 

Option: 1

100


Option: 2

200


Option: 3

500


Option: 4

250


1600 satellites were sent up by a country for several purposes. The purposes are classified as broadcasting (B), communication (C), surveillance (S), and others (O). A satellite can serve multiple purposes; however a satellite serving either B, or C, or S does not serve O. 

The following facts are known about the satellites: 

1. The numbers of satellites serving B, C, and S (though may be not exclusively) are in the ratio 2: 1:1. 

2. The number of satellites serving all three of B, C, and S is 100. 

3. The number of satellites exclusively serving C is the same as the number of satellites exclusively serving S. This number is 30% of the number of satellites exclusively serving B. 

4. The number of satellites serving O is the same as the number of satellites serving both C and S but not B. 

Question:

If at least 100 of the 1600 satellites were serving O, what can be said about the number of satellites serving S? 

Option: 1

At most 475 

 


Option: 2

Exactly 475 
 


Option: 3

At least 475 

 


Option: 4

No conclusion is possible based on the given information 


1600 satellites were sent up by a country for several purposes. The purposes are classified as broadcasting (B), communication (C), surveillance (S), and others (O). A satellite can serve multiple purposes; however a satellite serving either B, or C, or S does not serve O. 

The following facts are known about the satellites: 

1. The numbers of satellites serving B, C, and S (though may be not exclusively) are in the ratio 2: 1:1. 

2. The number of satellites serving all three of B, C, and S is 100. 

3. The number of satellites exclusively serving C is the same as the number of satellites exclusively serving S. This number is 30% of the number of satellites exclusively serving B. 

4. The number of satellites serving O is the same as the number of satellites serving both C and S but not B. 

Question:

 If the number of satellites serving at least two among B, C, and S is 1200, which of the following MUST be FALSE? 

Option: 1

The number of satellites serving C cannot be uniquely determined 

 


Option: 2

The number of satellites serving B is more than 1000 
 


Option: 3

All 1600 satellites serve B or C or S 

 


Option: 4

The number of satellites serving B exclusively is exactly 250 


2839155 is divisible by

Option: 1

2


Option: 2

7


Option: 3

55


Option: 4

None of the above


'a' for which x^{2}-ax+9= 0 can be written as square of a linear factor is

Option: 1

6


Option: 2

-6,6


Option: 3

\left ( 6,\infty \right )


Option: 4

\left ( -\infty,-6 \right )


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