Great Lakes - PGPM & PGDM 2025
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Hello CAT 2024 aspirants,
The CAT 2024 exam for MBA admissions from 2025-2027 is set for November 24. In this 60-day preparation guide series from Careers360, we’ll explore strategies for day 25 to help you prepare effectively and succeed in the CAT entrance test.
This article will cover CAT questions related to allegations and mixtures, CAT puzzle questions, and CAT reading comprehension questions.
When we combine two or more substances to form a single homogeneous entity, it is called a mixture. Whereas alligation is a rule that helps in finding the mean value of a mixture when the quantities and prices of the ingredients are known.
Mixture and Alligation involves combining two or more quantities with different prices, concentrations, or values to achieve a desired mixture.
The rule of alligation is used to find the ratio in which two or more ingredients at different prices (or concentrations) must be mixed to produce a mixture at a given price (or concentration).
If a Container contains ‘x’ units of pure liquid, and we replace the liquid with ‘y’ units of water, then after ‘n’ successive replacements, the units of pure liquid left are x(1- y/x)n
The weighted average method can be useful as well.
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Getting an idea from CAT's previous year's questions helps in our preparation.
Q1. If a certain weight of an alloy of silver and copper is mixed with 3 kg of pure silver, the resulting alloy will have 90% silver by weight. If the same weight of the initial alloy is mixed with 2 kg of another alloy which has 90% silver by weight, the resulting alloy will have 84% silver by weight. Then, the weight of the initial alloy, in kg, is [CAT exam 2021]
3
2.5
4
3.5
Solution: (A)
Case 1:
Let the weight of Silver = x; the weight of copper = y in the initial alloy.
According to the first condition:
(x+3+y) x 90/100 = (3+ x)
On solving, 9y = 3 + x
According to the second condition:
Quantity of silver = x + 90% of 2 Kg = 84 % of (x+ y+ 2)
On solving, 4x + 3 = 21y
Solve the two equations in two cases, we get x = 2.4 Kg and y = 0.6 Kg
Therefore, the total weight of the initial alloy = 3 Kg.
Q2. Two alcohol solutions, A and B, are mixed in the proportion 1:3 by volume. The volume of the mixture is then doubled by adding solution A such that the resulting mixture has 72% alcohol. If solution A has 60% alcohol, then the percentage of alcohol in solution B is [CAT exam 2020]
94%
92%
90%
89
Solution: (B)
Let Volume of A =100; Volume of B = 300; Volume of A +B = 400
On adding 400 litre volume of the mixture becomes 800 litres (According to question)
Alcohol in new mixture = 72% of 800 = 576
Alcohol in A = 60% of 500 = 300
Alcohol in B = 576 – 300 = 276
Percent of alcohol in B = 276x 100/ 300 = 92%
CAT exam: Prerequisite:
How to Prepare for Quantitative Aptitude for CAT by Arun Sharma (7th Edition: Page No 177- 180)
Mission CAT (YouTube Channel)
How to Prepare for Quantitative Aptitude for CAT by Arun Sharma (7th Edition: Page No 181- 189)
CAT Previous year Papers.
CAT Sample Papers.
CAT 2024 Syllabus Topic: Strategy to prepare Problem-Solving/Puzzle (Selection) for CAT
Such questions are solved by considering pre-conditions and a few essential conditions for the selection of a group.
Comprehension (CAT Puzzle Questions):
A new game show on TV has 100 boxes numbered 1, 2, . . . , 100 in a row, each containing a mystery prize. The prizes are items of different types, a, b, c, . . . , in decreasing order of value. The most expensive item is of type a, a diamond ring, and there is exactly one of these. You are told that the number of items at least doubles as you move to the next type. For example, there would be at least twice as many items of type b as of type a, at least twice as many items of type c as of type b and so on. There is no particular order in which the prizes are placed in the boxes. [CAT exam 2019]
Q1. What is the minimum possible number of different types of prizes?
Case Sensitivity: No
Answer Type: Equal
Possible Answer: 2
Explanation: If type a is 1 in number and Type b is 99 in number. Therefore, a minimum of 2 different types are possible.
Q2. What is the maximum possible number of different types of prizes?
Case Sensitivity: No
Answer Type: Equal
Possible Answer: 6
Explanation: If type a is 1 in number and type b is 2, type c is 4, type d is 8, type e is 16, and type f is 32 in number. If we proceed further type g should be at least 64 and the total count will be more than 100.
Therefore, a maximum of 6 different types are possible.
Q3. Which of the following is not possible?
There are exactly 75 items of type e.
There are exactly 45 items of type c.
There are exactly 60 items of type d.
There are exactly 30 items of type b.
Ans: (2)
Go through options:
Option 1:
If e is 75, we cannot have f (min 150 > 100)
So, the sum of a, b, c and d should be 25 where a is 1.
a = 1; b =2; c= 4; d = 18; e = 75, is a valid solution.
Option 2: If c is 45, we cannot have d (min 90 and sum will be > 100)
So, the sum of a and b should be 55 where a is 1. This is not possible at all.
In a similar way, we can check for option 3 and option 4 but it is not required now since we got our answer.
Find the criteria for selection
Formation of groups on the basis of criteria
A group is arranged in a table
Go through the options and eliminate the wrong option
Go through CAT previous year papers to analyze the types of questions asked on selection
Practice different types of problems
LRDI for CAT by Nishit K. Sinha
https://online.2iim.com › blogs › cat-preparation-strategy
Cat preparation-iQuanta (YouTube Channel)
Verbal and Non-Verbal Reasoning by R S Agrawal
CAT Previous year Papers.
CAT Sample Papers.
CAT Exam Important Topic: Reading Comprehension Part-2 (CAT reading comprehension questions) for CAT Exam
In this section, we will make strategies for Reading Comprehension with the help of CAT previous years' questions based on CAT RC questions
Comprehension:
Scientists recently discovered that Emperor Penguins—one of Antarctica’s most celebrated species—employ a particularly unusual technique for surviving the daily chill. As detailed in an article published today in the journal Biology Letters, the birds minimize heat loss by keeping the outer surface of their plumage below the temperature of the surrounding air. At the same time, the penguins’ thick plumage insulates their body and keeps it toasty. . . .
The researchers analyzed thermographic images . . . taken over roughly a month during June 2008. During that period, the average air temperature was 0.32 degrees Fahrenheit. At the same time, the majority of the plumage covering the penguins’ bodies was even colder: the surface of their warmest body part, their feet, was an average of 1.76 degrees Fahrenheit, but the plumage on their heads, chests and backs was -1.84, -7.24- and -9.76-degrees Fahrenheit respectively. Overall, nearly the entire outer surface of the penguins’ bodies was below freezing at all times, except for their eyes and beaks. The scientists also used a computer simulation to determine how much heat was lost or gained from each part of the body—and discovered that by keeping their outer surface below the air temperature, the birds might paradoxically be able to draw very slight amounts of heat from the air around them. The key to their trick is the difference between two different types of heat transfer: radiation and convection.
The penguins do lose internal body heat to the surrounding air through thermal radiation, just as our bodies do on a cold day. Because their bodies (but not surface plumage) are warmer than the surrounding air, heat gradually radiates outward over time, moving from a warmer material to a colder one. To maintain body temperature while losing heat, penguins, like all warm-blooded animals, rely on the metabolism of food. The penguins, though, have an additional strategy. Since their outer plumage is even colder than the air, the simulation showed that they might gain back a little of this heat through thermal convection—the transfer of heat via the movement of a fluid (in this case, the air). As the cold Antarctic air cycles around their bodies, slightly warmer air comes into contact with the plumage and donates minute amounts of heat back to the penguins, then cycles away at a slightly colder temperature.
Most of this heat, the researchers note, probably doesn’t make it all the way through the plumage and back to the penguins’ bodies, but it could make a slight difference. At the very least, the method by which a penguin’s plumage wicks heat from the bitterly cold air that surrounds it helps to cancel out some of the heat that’s radiating from its interior. And given the Emperors’ unusually demanding breeding cycle, every bit of warmth counts. . . . Since [penguins trek as far as 75 miles to the coast to breed and male penguins] don’t eat anything during [the incubation period of 64 days], conserving calories by giving up as little heat as possible is absolutely crucial.
Explanation:
Paragraph 1: About the discovery of Emperor penguins in Antarctica.
Paragraph 2: About the behaviour of the body parts of penguins at very low temperatures.
Paragraph 3: About the heat transfer by penguins for their survival through radiation.
Since their outer plumage is even colder than the air, the simulation showed that they might gain back a little of this heat through thermal convection—the transfer of heat via the movement of a fluid (in this case, the air).
Paragraph 4: Given the Emperors’ unusually demanding breeding cycle, every bit of warmth counts, conserving calories by giving up as little heat as possible is absolutely critical.
On the basis of this analysis, we will solve the questions related to this passage. Strategies to solve an RC will be discussed in the next article.
Tenses and Parts of Speech
Each paragraph indicates a different point.
Summarize each paragraph in a word or phrase
Skimming Text
No facts or figures need to be memorized (Just know where they are)
Look for transition words to connect the ideas.
How to Prepare for Verbal Ability & Reading Comprehension for CAT by Meenakshi Upadhyay and Arun Sharma (9th Edition)
TCY Online
CAT Previous year Papers.
Bodhee Prep CAT Preparation (YouTube)
We will be back with Day 26 of the CAT exam preparation guide 2024 for 60 days tomorrow. Do practice and be focused.
With a 65 percentile in CAT, getting admission to USMS (Guru Gobind Singh Indraprastha University) may be difficult, as its cutoff is usually 75-85 percentile or higher for the general category.
However, you can consider other good MBA colleges that accept 60-70 percentile in CAT, such as:
Christ University, Bangalore
Institute of Public Enterprise, Hyderabad
Amrita School of Business, Kochi
PES University, Bangalore
KIIT School of Management, Bhubaneswar
Rajagiri Centre for Business Studies, Kochi
Army Institute of Management, Kolkata
Research their admission criteria, placements, and faculty to choose the best fit.
Hello
With a 65 percentile in CAT , USMS (GGSIPU) admission is difficult as its cutoffs are usually higher. However, you can explore private and tier-2/tier-3 MBA colleges that accept lower CAT scores.
Options to Consider:
1. Private MBA Colleges :
Amity University, Noida
LPU (Lovely Professional University)
Alliance University, Bangalore
Christ University, Bangalore
Apeejay School of Management, Delhi
2. B-Schools Accepting Lower CAT Percentile :
BIMTECH (PGDM-Retail/IB/Insurance)
XIME Bangalore
ITM Navi Mumbai
IPE Hyderabad
Jaipuria Institute of Management
3. Other Entrance Exams :
Appear for MAT, CMAT, XAT (low percentile accepted by some colleges)
Consider state-level exams like MAH CET, KMAT or TANCET .
Hope this gives you the clarity you need.
Hello there,
With your
academic profile (General, Male, Non-Engineer)
, you should
target MBA colleges that focus more on CAT percentile than past academics.
Target Colleges & Minimum CAT Percentile:
You
can
get a good MBA college with
strategic applications
and
high CAT/XAT percentile.
I hope this answer helps you. If you have more queries then feel free to share your questions with us we will be happy to assist you.
Thank you and wishing you all the best for your bright future.
Hi,
As per your given JEE Main percentile which is 88.34 in the SC Category, Your Predicted JEE MAINS 2025 rank may range between 147086 - 170102.
Based on the previous year analysis, According to your JEE MAINS percentile and category you have less possibility of getting a seat for admission in NIT Surathkal.
Some of the other colleges in which you have chances to get admission includes:
You can predict more colleges using the JEE MAINS 2025 college predictor tool.
Hope this information will help you
With your academic background, you have a good chance of getting into some of the top IIMs. Here's a breakdown of your profile:
- Class 10:91.6% - Excellent!
- Class 12:66% - Average, but not a deal-breaker
- B.Tech Computer Science: 8.4 CGPA - Very good!
Assuming you score well in CAT , here are some IIMs you might have a good chance of getting into:
- IIM Ahmedabad: Although the qualifying CAT cut off is 85 percentile, the final cut off typically goes up to 99-100 percentile.With a good CAT score, you might be considered.
- IIM Kozhikode: The CAT cut off for IIM Kozhikode is typically around 95-98 percentile. Your academic profile and a good CAT score might make you a competitive candidate.
- IIM Indore:The CAT cut off for IIM Indore is typically around 90-95 percentile. With a good CAT score and your academic background, you might have a chance.
Keep in mind that CAT cut offs can vary from year to year, and other factors like work experience, extracurricular activities, and personal interviews also play a significant role in the admission process.
To increase your chances, focus on scoring well in CAT, and make sure you have a strong overall profile.
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