Parul University MBA Admissions 2025
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Practice sets are very crucial from an exam point of view. On day 20 Career’s 360 has prepared this practice test to give the candidates exposure to the actual exam pattern. Students may refer to it and practice more papers in the following days using our articles. You may prepare for the CAT test in an organized way by following our 60-day CAT exam preparation strategy. Make sure to improve your test-taking skills by practising with these CAT practice questions every day.
This CAT Sample paper consists of three Sections:
Part- A consists of 9 questions.
Part- B consists of 7 questions.
Part- C consists of 9 questions.
Q1. For the given pair (x, y) of positive integers, such that (-x + 3y/2) = 7 and x < 210. How many integer values of y satisfy the given conditions? (CAT previous year questions)
340
341
342
1024
Registrations Deadline- 05th July | India's youngest NAAC A++ accredited University | NIRF rank band 151-200 | 2200 Recruiters | 45.98 Lakhs Highest Package
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Q2. A quadratic function f(x) attains a maximum of 12 at x = 1. The value of the function at x = 0 is 7. What is the value of f (x) at x = -11? (CAT previous year questions)
-805
-719
-859
-883
Q3. If the roots of the equation in y i.e. y3 – ay2 + by – c = 0 are three consecutive integers, then the smallest possible value of b (nearest to its integer value) is ______________ [TITA]
Q4. The sum of the integers in the solution set of |x2 - 7x| > 5 is: (CAT exam model paper)
10
15
20
0
Q5. The equation x2 + ax + (3-b) = 0 has real roots. What is the minimum value of a2 + b2? (CAT previous year questions)
0
2
4
8
Q6. X is p% less than Y and Z is p% more than Y. If X is 2.5p% more than Z, then find p.
(Note: p ≠ 0) - (CAT previous year questions)
20
40
60
50
Q7. The value of the base of a triangle for which area is minimum if the relation between the perpendicular distance from the vertex and the base is p = 7b2 - 84 is _______________ (where b represents base and p represents perpendicular distance) [TITA]
Q8. Let f (x) = max (2x + 1, 3 − 4x), where x is any real number. Value of f(x) at x = 7.5 is: (CAT exam model paper)
-11
- 27
16
43
Q9. Let g (x) be a function such that g (x + 1) g (x) = 12 for every real x. Then what is the value of g (11) g (0)? (CAT exam model paper)
1
12
1/12
6
Direction (Q1-Q3):
Four friends Arun, Bittu, Cirag and Dheeraj went for an excursion with their wives Priya, Renu, Sharita and Varti, not necessarily in the same order. Each couple hails from a different city, including Madurai, Cutnee, Kurnool, and Hapur, but they are not necessarily in that order. They went to Delhi to visit the Pinkfort, where they sat in a row. Each wife always sat to the immediate right of her husband.
(CAT practice questions)
(i) Bittu sat to the immediate right of Priya.
(ii) Dheeraj is from Hapur and Priya is not from Madurai.
(iii) Renu and her husband were sitting to the immediate right of the couple that hailed from Cutnee.
(iv) Chirag and his wife were sitting to the immediate left of the couple from Kurnool and Chirag was sitting to the immediate right of Sharita.
(v) Arun sat to the immediate right of Renu, who is not from Madurai.
Q1. Who is Dheeraj’s wife?
Sharita
Priya
Varti
Renu
Q2. Which couple is from Cutnee?
Varti and Bittu
Dheeraj and Renu
Chirag and Priya
Arun and Sharita
Q3. Who is the husband in the couple, who is seated second in the row from left to right?
Arun
Bittu
Chirag
Dheeraj
Direction (Q4- Q7) (CAT practice questions)
A cube is formed by joining 216 smaller and identical cubes. The bigger cube is painted black colour on all its faces. From the bigger cube, 64 smaller cubes from a corner were taken out and the cube formed by joining these 64 smaller cubes is painted pink in all its faces. Again, this cube is fitted back into its usual position in the large cube.
Q4. How many smaller cubes have no faces painted?
Q5. How many smaller cubes have three faces painted?
Q6. How many smaller cubes have only two faces painted?
Q7. How many smaller cubes have only one face painted?
In the questions below, find the phrase with an error.
Q1: If I had known, I would lend you my car.
I will lend you my car
I would lent you my car
I would have lent you my car
No improvement needed
Q2. You have no trouble at school, if you had done your homework.
You would have had no trouble at school.
You will have no trouble at school.
You would had no trouble at school
No improvement needed
Q3. If you had done better at your interview, you get that job.
You will get that job.
You would get that job.
You would have got that job.
No improvement needed
Choose appropriate sentence
Q4. While the guests danced, the thieves broke into the house.
While the guests have danced
While the guests were dancing
While the guests had danced
No improvement needed
Q5. Take a shower (a)/ you will (b)/ feel better. (c) / No error (d)
(a)
(b)
(c)
(d)
Q6. Whenever I look (a)/ at the moon, my heart (b)/ fills with the pleasure. (c)/ No error(d)
(a)
(b)
(c)
(d)
Q7. The whole block of flats (a)/ including two shops were (b)/ destroyed in fire. (c)/ No error (d)
(a)
(b)
(c)
(d)
Q8. The man who cannot (a)/ believe his senses and the man who cannot (b)/ believe anything else are insane. (c)/ No error(d)
(a)
(b)
(c)
(d)
Q9. If you go by __ train you can have quite__ comfortable journey, but make sure you get ___ express, not __ train that stops at all the stations.
a, an, a, the
an, a, the, a
No article, an, a, the
No article, a, an, a
Answer 1: (B)
3y/2 = 7 + x
⇒ y = (14 + 2x)/3; for y to be integer (14 + 2x) should be divisible by 3
So, x = 2; y = 6
When x= 5, y = 8
When x = 8, y = 10
When x = 11, y = 12 and so on…
So, there is an AP in x with the first term being 2 and the common difference is 3.
nth term in x must be less than or equal to 210 i.e., 1024.
Therefore, 2 + (n-1)3 ≤ 1024
⇒ n ≤ (1022/3) +1
Therefore, n must be 341.
Hence, there can be 341 solutions.
Answer 2: (D)
If the function gets the maximum of 12 at x = 1
f(x) = a(x – 1)2 + 12
So, f (0) = a + 12 = 7 [Given]
⇒ a = –5
f(x) = –5(x – 1)2 + 12
So, f(-11) = –5(-12 – 1)2 + 12 = –845 + 12 = –833
Hence, the correct answer is –833.
Answer 3:
Let roots be (n - 1), n and (n + 1).
In a cubic equation, the coefficient of y divided by the coefficient of y3 represents the sum of the product of roots taken two at a time.
So, b = the sum of the product of roots taken two at a time
n(n - 1) + (n + 1)n + (n - 1) (n + 1) = b
⇒ n2 - n + n2 + n + n2 - 1 = b
⇒ 3n2 - 1 = b
The value of b will be minimal when the value of n2 is minimum.
i.e., n2 = 0
So, 3 × 0 - 1 = b
∴ b = -1
Hence, the correct answer is -1.
Answer 4: (D)
|x2 - 7x| > 5
⇒ x2 - 7x > 5 or x2 - 7x < -5
Case 1:
⇒ x2-7x > 5
⇒ x2 - 7x – 5 > 0
⇒ x > [(7±√69)/2], which gives two solutions x > 7 or x < 0 (for x to be integer).
Case 2:
⇒ x2 - 7x < -5
⇒ x2 - 7x + 5 < 0
⇒ x < [(7±√29)/2], which gives two solutions x < 7 or x > 0 (for x to be integer).
So, x = [1, 2, 3, 4, 5, 6]
There is no common solution in both cases.
Hence, the correct answer is 0.
Answer 5: (D)
For real roots; a2 – 4(3 – b) ≥ 0
⇒ a2 + 4b – 12 ≥ 0
⇒ a2 + 4b + b2 – b2 – 12 ≥ 0
⇒ a2 + b2 ≥ b2 – 4b + 12
⇒ a2 + b2 ≥ b2 – 4b + 4 + 8
⇒ a2 + b2 ≥ (b – 2)2 + 8
At b = 2, a2 + b2 has the minimum value. i.e., 8.
Hence, the correct answer is 8.
Answer 6: (A)
X = (100 – p) Y/100
Z = (100 + p) Y/100
X = (100 + 2.5p) Z/100
From 1st and 2nd relation, we get X = Z (100 – p) / (100 + p)
So, Z (100 – p) / (100 + p) = (100 + 2.5p) Z/100
⇒ 100(100 – p) = (100 + p) (100 + 2.5p)
⇒ – 100p = 100p – 250p + 2.5p2
⇒ 50p = 2.5p2
⇒ p = 20
Hence, the correct answer is 20.
Answer 7:
Area = ½ (base) (height) = ½ b (7b2 - 84) = 7b3/2 - 84b1/2
For Area to be minimum, find dA/db = 21/2 b2 – 42 = 0
⇒ b2 = 4
⇒ b = 2 or b = -2
Now find d2A/db2 = 21b
At b = 2; d2A/db2 = 42, which is greater than 0.
So, at b = 2, we get the minimum value of Area.
Hence, the correct answer is 2.
Answer 8: (C)
f(x) = max (2 × 7.5 + 1, 3 – 4 × 7.5) at x = 7.5
⇒ f(x) = max (16, -27) at x = 7.5
Hence, the correct answer is 16.
Answer 9: (B)
For x = 0; g(1) = 12/g(0)
Similarly g(2) = 12/g(1), which gives g(2) = g(0)
g(3) = g(1) and so on.
Therefore, g(11) = g(9) = g(7) = ……= g(1) = 12/g(0)
⇒ g (11) g (0) = 12
Hence, the correct answer is 12.
Solution 1-3:
Males: Arun, Bittu, Cirag and Dheeraj
Females: Priya, Renu, Sharita and Varti
Cities: Madurai, Cutnee, Kurnool and Hapur
Regarding the couples, the wife always sits to the immediate right of her husband.
From (i), Bittu is not the husband of Priya.
From (ii), Dheeraj is from Hapur.
From (iii), Renu is not from Cutnee.
From (iv), Cirag is not from Kurnool and is not the husband of Sharita.
From (v), Arun is not married to Renu and Renu is not from Madurai.
Possibility Table
HUSBAND | WIFE | CITY |
Bittu | Priya | Hapur |
Dheeraj | Sharita, Reno, Priya, Varita | Hapur |
Chirag | Sharita, Renu, Priya or Varita | Hapur, Kurnool, Mudrai or Cutnee |
Arun | Renu | Hapur, Cutnee, Madurai or Kurnool |
So, according to the table, there were two possibilities for Chirag's wife either Priya or Varita so we will consider these cases one by one.
Case I: If we consider Priya as Chirag’s wife and Priya can’t be from Madurai so they must be from Cutnee.
So, the arrangement could look like this:
------ Sharita Chirag --- Priya Bittu---Renu Arun-------
Now after this arrangement only one man and one woman is left so we can consider the woman as Arun’s wife and the man as Sharita’s Husband
Dheeraj ------ Sharita Chirag --- Priya Bittu---Renu Arun-------Varti
This arrangement fulfils all the conditions, so it is not required to consider any other case.
Answer 1: Dheeraj is married to Sharita. [Which is option (A)]
Answer 2: Chirag and Priya are from Cutnee. [Which is option (C)]
Answer 3: Chirag and his wife are seated second in the row. [Which is option (C)]
Solution 4 to 7:
Answer 4: By assuming a 4 × 4 × 4 cube is also not painted with pink colour, the number of cubes with no faces painted is = (6 – 2)3 = 64. Of these 64 smaller cubes now, in the second, third and fourth layers leftmost 9 cubes are painted pink, on the bottom surface four smaller cubes are painted pink and on the fourth layer back six smaller cubes are painted.
Hence, the total number of cubes with no face painted = 64 – 19 = 45
Answer 5: The number of cubes which are three faces painted before removing 64 smaller cubes = 8 and after painting with pink colour to those 64 smaller cubes seven new cubes will have three faces painted.
Hence, the total number of cubes with three faces painted = 8 + 7 = 15
Answer 6: The number of smaller cubes painted on two faces in the larger cube after removing 4 × 4 × 4 is illustrated as shown below.
9 edges with four smaller cubes with two faces painted = 9 × 4 = 36; 3 edges with one cube with two faces painted = 3 × 1 = 3
In the pink cube, there are 24 cubes on 12 edges which are painted on two faces.
Hence, the number of cubes with two faces painted = 36 + 3 + 24 = 63
Answer 7: The number of cubes with one face painted in the larger cube = 3 × 16 + 3 × 7 = 69. Number of cubes with one face painted in the 4 × 4 cube = 6 × 4 = 24
Hence, the total number of smaller cubes with one face painted = 69 + 24 = 93
Answer 1: (C)
if clause: had known (past perfect), Main clause: would/ could have lent.
Answer 2: (A)
if clause: had done (past perfect), the main clause: would/ could/ might have had.
Answer 3: (C)
if clause: had done (past perfect), the main clause: would/ could/ might have had.
Answer 4: (B)
The previous event is simple past, then the next event must be past continuous for continuous action.
Answer 5: D
“take a shower” is an idiomatic phrase. Hence, No error.
Answer 6: (C)
“with pleasure” is an idiomatic phrase. With pleasure replaced with “pleasure”.
Answer 7: (B)
“was” is used instead of “were”. The whole block is considered a singular subject and the singular subject takes a singular verb.
Answer 8: (D)
when two nouns get added with the use of ‘and’ and a possessive adjective article is used before both nouns then we use a plural verb but when the possessive adjective article is used with only one noun then it is considered to be one and hence singular verb is used.
Answer 9: (D)
No article is used between By and Means of transport.
Before comfortable “a” should be used.
Before “express”, “an” will be used as there is a vowel at the start.
Before “train”, “a” will be used.
300+ Phrasal Verbs List for CAT Exam, Types With Examples & Practice Questions | CAT Quantitative Aptitude Questions with Answers PDF |
A quadratic function is a degree two polynomial function in which the variable's maximum exponent is 2.
The roots are the values of 'x' for which the quadratic equation is true, indicating where the graph intersects the x-axis.
There can be 1, 0, or 2 roots in a quadratic equation.
Real roots are real-valued equation solutions. This implies that they may be positive, negative, or zero, but not imaginary or complex. The real roots of the equation x^2-4=0 are x=2 and x=-2, which are both real values that satisfy the equation. Simply said, real roots are the values of a variable that satisfy the equation and may be found on the number line.
Yes absolutely, practices will make you better, helping in increase of speed and accuracy.
Hey Paridhi ,
I hope you are absolutely fine. As per your mentioned query , you have to understand the exam pattern first. Its syllabus, the type of questions and so on. Here i am mentioning some tips i hope this will be helpful for you.
To know more you can refer this :
https://bschool.careers360.com/articles/cat-preparation-strategy
Revert for further query!
Good luck !
Hello Abhishek,
No, you cannot take admission into B. Tech Marine Engineering at CUSAT if you do not take the CAT 2025 exam. CUSAT CAT is a mandatory exam for admission into all undergraduate programs including B Tech Marine Engineering. Admission to the program will only be possible for candidates with valid CAT scores.
Hi aspirant,
The Common Admission Test (CAT) is a highly competitive exam, and practicing sample questions is essential for efficient preparation.
Kindly refer to the link attached above for the sample papers.
All the best!
Hello,
States you can apply in (B-category/management quota):
Telangana, Andhra Pradesh, Karnataka, Tamil Nadu, Kerala, and Puducherry. All allow non-domicile students for private colleges.
Approx MBBS fees (per year):
Telangana: Rs. 12–15 lakh
Andhra Pradesh: Rs. 12–18 lakh
Karnataka: Rs. 15–20 lakh
Tamil Nadu: Rs. 15–22 lakh
Kerala: Rs. 7–8.5 lakh
Karnataka registration:
Closed in Feb 2025. Likely to reopen for mop-up/stray rounds in June–July 2025.
Kerala registration:
Closed in March 2025. Stray round expected in June–July 2025. Dates not announced yet.
Hope it helps !
Dear Aspirant
Your rank at eleven thousand eight hundred eighty seven under the OBC reservation has a strong chance for admission to the Computer Science Engineering (CSE) program at one of the three CUSAT campuses The exact seat depends on opening and closing ranks for CSE in each campus and the round of counselling
CUSAT campuses offering BTech CSE
• School of Engineering Thrikkakkara – flagship campus in Kochi
• CUCEK Kuttanad – second campus in Alappuzha district
• Lakeside campus does not offer CSE so only two campuses are relevant
Previous closing ranks under OBC quota for CSE
• Thrikkakkara campus closed near rank one thousand
• CUCEK Kuttanad closed around six thousand two hundred in 2024
Your likelihood with rank 11887
• Thrikkakkara campus is unlikely as CSE closes much lower than your rank
• CUCEK has potential since closing ranks in recent years have extended into the high six thousands
• Seats may remain open in later rounds so you may gain admission at CUCEK
Other CSE seat possibilities under OBC
• School of Engineering might open seats in spot or mop up rounds if higher ranked students do not confirm
• CUCEK will likely accept OBC candidates up to rank one two thousand to thirteen thousand
• Keep an eye on real time counselling as closing ranks may shift downward with seat cancellations
Alternative branches and campuses
If CSE is not available at CUCEK you may consider similar branches like Electronics and Communication Engineering Information Technology Mechanical Engineering and Civil Engineering closing beyond twelve thousand under OBC
You may also add interdisciplinary programs or lateral entry courses available in Lakeside or Thrikkakkara depending on available seats
Counselling strategy recommendations
• Register and fill choices on the CUSAT admissions portal in all counselling rounds
• Place CUCEK CSE as a high preference followed by ECE or IT at Thrikkakkara or CUCEK
• Monitor round wise closing ranks through the portal or official communications
• Participate in mop up and spot rounds where seats are more likely available near your rank
Key considerations
• Cutoffs decrease between rounds allowing more opportunities in later phases
• OBC candidates compete within their category reducing competition compared to open rankings
• CUCEK is your best target campus for CSE at your rank under OBC
• You must have all documents ready like previous marksheet category certificate and CUSAT admit card for verification
Let me know if you would like a suggested list of choices tailored to your academic interest or want help tracking counselling round data
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