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Practice sets are very crucial from an exam point of view. On day 20 Career’s 360 has prepared this practice test to give the candidates exposure to the actual exam pattern. Students may refer to it and practice more papers in the following days using our articles. You may prepare for the CAT test in an organized way by following our 60-day CAT exam preparation strategy. Make sure to improve your test-taking skills by practising with these CAT practice questions every day.
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This CAT Sample paper consists of three Sections:
Part- A consists of 9 questions.
Part- B consists of 7 questions.
Part- C consists of 9 questions.
Q1. For the given pair (x, y) of positive integers, such that (-x + 3y/2) = 7 and x < 210. How many integer values of y satisfy the given conditions? (CAT previous year questions)
340
341
342
1024
Q2. A quadratic function f(x) attains a maximum of 12 at x = 1. The value of the function at x = 0 is 7. What is the value of f (x) at x = -11? (CAT previous year questions)
-805
-719
-859
-883
Q3. If the roots of the equation in y i.e. y3 – ay2 + by – c = 0 are three consecutive integers, then the smallest possible value of b (nearest to its integer value) is ______________ [TITA]
Q4. The sum of the integers in the solution set of |x2 - 7x| > 5 is: (CAT exam model paper)
10
15
20
0
Q5. The equation x2 + ax + (3-b) = 0 has real roots. What is the minimum value of a2 + b2? (CAT previous year questions)
0
2
4
8
Q6. X is p% less than Y and Z is p% more than Y. If X is 2.5p% more than Z, then find p.
(Note: p ≠ 0) - (CAT previous year questions)
20
40
60
50
Q7. The value of the base of a triangle for which area is minimum if the relation between the perpendicular distance from the vertex and the base is p = 7b2 - 84 is _______________ (where b represents base and p represents perpendicular distance) [TITA]
Q8. Let f (x) = max (2x + 1, 3 − 4x), where x is any real number. Value of f(x) at x = 7.5 is: (CAT exam model paper)
-11
- 27
16
43
Q9. Let g (x) be a function such that g (x + 1) g (x) = 12 for every real x. Then what is the value of g (11) g (0)? (CAT exam model paper)
1
12
1/12
6
Direction (Q1-Q3):
Four friends Arun, Bittu, Cirag and Dheeraj went for an excursion with their wives Priya, Renu, Sharita and Varti, not necessarily in the same order. Each couple hails from a different city, including Madurai, Cutnee, Kurnool, and Hapur, but they are not necessarily in that order. They went to Delhi to visit the Pinkfort, where they sat in a row. Each wife always sat to the immediate right of her husband.
(CAT practice questions)
(i) Bittu sat to the immediate right of Priya.
(ii) Dheeraj is from Hapur and Priya is not from Madurai.
(iii) Renu and her husband were sitting to the immediate right of the couple that hailed from Cutnee.
(iv) Chirag and his wife were sitting to the immediate left of the couple from Kurnool and Chirag was sitting to the immediate right of Sharita.
(v) Arun sat to the immediate right of Renu, who is not from Madurai.
Q1. Who is Dheeraj’s wife?
Sharita
Priya
Varti
Renu
Q2. Which couple is from Cutnee?
Varti and Bittu
Dheeraj and Renu
Chirag and Priya
Arun and Sharita
Q3. Who is the husband in the couple, who is seated second in the row from left to right?
Arun
Bittu
Chirag
Dheeraj
Direction (Q4- Q7) (CAT practice questions)
A cube is formed by joining 216 smaller and identical cubes. The bigger cube is painted black colour on all its faces. From the bigger cube, 64 smaller cubes from a corner were taken out and the cube formed by joining these 64 smaller cubes is painted pink in all its faces. Again, this cube is fitted back into its usual position in the large cube.
Q4. How many smaller cubes have no faces painted?
Q5. How many smaller cubes have three faces painted?
Q6. How many smaller cubes have only two faces painted?
Q7. How many smaller cubes have only one face painted?
In the questions below, find the phrase with an error.
Q1: If I had known, I would lend you my car.
I will lend you my car
I would lent you my car
I would have lent you my car
No improvement needed
Q2. You have no trouble at school, if you had done your homework.
You would have had no trouble at school.
You will have no trouble at school.
You would had no trouble at school
No improvement needed
Q3. If you had done better at your interview, you get that job.
You will get that job.
You would get that job.
You would have got that job.
No improvement needed
Choose appropriate sentence
Q4. While the guests danced, the thieves broke into the house.
While the guests have danced
While the guests were dancing
While the guests had danced
No improvement needed
Q5. Take a shower (a)/ you will (b)/ feel better. (c) / No error (d)
(a)
(b)
(c)
(d)
Q6. Whenever I look (a)/ at the moon, my heart (b)/ fills with the pleasure. (c)/ No error(d)
(a)
(b)
(c)
(d)
Q7. The whole block of flats (a)/ including two shops were (b)/ destroyed in fire. (c)/ No error (d)
(a)
(b)
(c)
(d)
Q8. The man who cannot (a)/ believe his senses and the man who cannot (b)/ believe anything else are insane. (c)/ No error(d)
(a)
(b)
(c)
(d)
Q9. If you go by __ train you can have quite__ comfortable journey, but make sure you get ___ express, not __ train that stops at all the stations.
a, an, a, the
an, a, the, a
No article, an, a, the
No article, a, an, a
Answer 1: (B)
3y/2 = 7 + x
⇒ y = (14 + 2x)/3; for y to be integer (14 + 2x) should be divisible by 3
So, x = 2; y = 6
When x= 5, y = 8
When x = 8, y = 10
When x = 11, y = 12 and so on…
So, there is an AP in x with the first term being 2 and the common difference is 3.
nth term in x must be less than or equal to 210 i.e., 1024.
Therefore, 2 + (n-1)3 ≤ 1024
⇒ n ≤ (1022/3) +1
Therefore, n must be 341.
Hence, there can be 341 solutions.
Answer 2: (D)
If the function gets the maximum of 12 at x = 1
f(x) = a(x – 1)2 + 12
So, f (0) = a + 12 = 7 [Given]
⇒ a = –5
f(x) = –5(x – 1)2 + 12
So, f(-11) = –5(-12 – 1)2 + 12 = –845 + 12 = –833
Hence, the correct answer is –833.
Answer 3:
Let roots be (n - 1), n and (n + 1).
In a cubic equation, the coefficient of y divided by the coefficient of y3 represents the sum of the product of roots taken two at a time.
So, b = the sum of the product of roots taken two at a time
n(n - 1) + (n + 1)n + (n - 1) (n + 1) = b
⇒ n2 - n + n2 + n + n2 - 1 = b
⇒ 3n2 - 1 = b
The value of b will be minimal when the value of n2 is minimum.
i.e., n2 = 0
So, 3 × 0 - 1 = b
∴ b = -1
Hence, the correct answer is -1.
Answer 4: (D)
|x2 - 7x| > 5
⇒ x2 - 7x > 5 or x2 - 7x < -5
Case 1:
⇒ x2-7x > 5
⇒ x2 - 7x – 5 > 0
⇒ x > [(7±√69)/2], which gives two solutions x > 7 or x < 0 (for x to be integer).
Case 2:
⇒ x2 - 7x < -5
⇒ x2 - 7x + 5 < 0
⇒ x < [(7±√29)/2], which gives two solutions x < 7 or x > 0 (for x to be integer).
So, x = [1, 2, 3, 4, 5, 6]
There is no common solution in both cases.
Hence, the correct answer is 0.
Answer 5: (D)
For real roots; a2 – 4(3 – b) ≥ 0
⇒ a2 + 4b – 12 ≥ 0
⇒ a2 + 4b + b2 – b2 – 12 ≥ 0
⇒ a2 + b2 ≥ b2 – 4b + 12
⇒ a2 + b2 ≥ b2 – 4b + 4 + 8
⇒ a2 + b2 ≥ (b – 2)2 + 8
At b = 2, a2 + b2 has the minimum value. i.e., 8.
Hence, the correct answer is 8.
Answer 6: (A)
X = (100 – p) Y/100
Z = (100 + p) Y/100
X = (100 + 2.5p) Z/100
From 1st and 2nd relation, we get X = Z (100 – p) / (100 + p)
So, Z (100 – p) / (100 + p) = (100 + 2.5p) Z/100
⇒ 100(100 – p) = (100 + p) (100 + 2.5p)
⇒ – 100p = 100p – 250p + 2.5p2
⇒ 50p = 2.5p2
⇒ p = 20
Hence, the correct answer is 20.
Answer 7:
Area = ½ (base) (height) = ½ b (7b2 - 84) = 7b3/2 - 84b1/2
For Area to be minimum, find dA/db = 21/2 b2 – 42 = 0
⇒ b2 = 4
⇒ b = 2 or b = -2
Now find d2A/db2 = 21b
At b = 2; d2A/db2 = 42, which is greater than 0.
So, at b = 2, we get the minimum value of Area.
Hence, the correct answer is 2.
Answer 8: (C)
f(x) = max (2 × 7.5 + 1, 3 – 4 × 7.5) at x = 7.5
⇒ f(x) = max (16, -27) at x = 7.5
Hence, the correct answer is 16.
Answer 9: (B)
For x = 0; g(1) = 12/g(0)
Similarly g(2) = 12/g(1), which gives g(2) = g(0)
g(3) = g(1) and so on.
Therefore, g(11) = g(9) = g(7) = ……= g(1) = 12/g(0)
⇒ g (11) g (0) = 12
Hence, the correct answer is 12.
Solution 1-3:
Males: Arun, Bittu, Cirag and Dheeraj
Females: Priya, Renu, Sharita and Varti
Cities: Madurai, Cutnee, Kurnool and Hapur
Regarding the couples, the wife always sits to the immediate right of her husband.
From (i), Bittu is not the husband of Priya.
From (ii), Dheeraj is from Hapur.
From (iii), Renu is not from Cutnee.
From (iv), Cirag is not from Kurnool and is not the husband of Sharita.
From (v), Arun is not married to Renu and Renu is not from Madurai.
Possibility Table
HUSBAND | WIFE | CITY |
Bittu | Priya | Hapur |
Dheeraj | Sharita, Reno, Priya, Varita | Hapur |
Chirag | Sharita, Renu, Priya or Varita | Hapur, Kurnool, Mudrai or Cutnee |
Arun | Renu | Hapur, Cutnee, Madurai or Kurnool |
So, according to the table, there were two possibilities for Chirag's wife either Priya or Varita so we will consider these cases one by one.
Case I: If we consider Priya as Chirag’s wife and Priya can’t be from Madurai so they must be from Cutnee.
So, the arrangement could look like this:
------ Sharita Chirag --- Priya Bittu---Renu Arun-------
Now after this arrangement only one man and one woman is left so we can consider the woman as Arun’s wife and the man as Sharita’s Husband
Dheeraj ------ Sharita Chirag --- Priya Bittu---Renu Arun-------Varti
This arrangement fulfils all the conditions, so it is not required to consider any other case.
Answer 1: Dheeraj is married to Sharita. [Which is option (A)]
Answer 2: Chirag and Priya are from Cutnee. [Which is option (C)]
Answer 3: Chirag and his wife are seated second in the row. [Which is option (C)]
Solution 4 to 7:
Answer 4: By assuming a 4 × 4 × 4 cube is also not painted with pink colour, the number of cubes with no faces painted is = (6 – 2)3 = 64. Of these 64 smaller cubes now, in the second, third and fourth layers leftmost 9 cubes are painted pink, on the bottom surface four smaller cubes are painted pink and on the fourth layer back six smaller cubes are painted.
Hence, the total number of cubes with no face painted = 64 – 19 = 45
Answer 5: The number of cubes which are three faces painted before removing 64 smaller cubes = 8 and after painting with pink colour to those 64 smaller cubes seven new cubes will have three faces painted.
Hence, the total number of cubes with three faces painted = 8 + 7 = 15
Answer 6: The number of smaller cubes painted on two faces in the larger cube after removing 4 × 4 × 4 is illustrated as shown below.
9 edges with four smaller cubes with two faces painted = 9 × 4 = 36; 3 edges with one cube with two faces painted = 3 × 1 = 3
In the pink cube, there are 24 cubes on 12 edges which are painted on two faces.
Hence, the number of cubes with two faces painted = 36 + 3 + 24 = 63
Answer 7: The number of cubes with one face painted in the larger cube = 3 × 16 + 3 × 7 = 69. Number of cubes with one face painted in the 4 × 4 cube = 6 × 4 = 24
Hence, the total number of smaller cubes with one face painted = 69 + 24 = 93
Answer 1: (C)
if clause: had known (past perfect), Main clause: would/ could have lent.
Answer 2: (A)
if clause: had done (past perfect), the main clause: would/ could/ might have had.
Answer 3: (C)
if clause: had done (past perfect), the main clause: would/ could/ might have had.
Answer 4: (B)
The previous event is simple past, then the next event must be past continuous for continuous action.
Answer 5: D
“take a shower” is an idiomatic phrase. Hence, No error.
Answer 6: (C)
“with pleasure” is an idiomatic phrase. With pleasure replaced with “pleasure”.
Answer 7: (B)
“was” is used instead of “were”. The whole block is considered a singular subject and the singular subject takes a singular verb.
Answer 8: (D)
when two nouns get added with the use of ‘and’ and a possessive adjective article is used before both nouns then we use a plural verb but when the possessive adjective article is used with only one noun then it is considered to be one and hence singular verb is used.
Answer 9: (D)
No article is used between By and Means of transport.
Before comfortable “a” should be used.
Before “express”, “an” will be used as there is a vowel at the start.
Before “train”, “a” will be used.
300+ Phrasal Verbs List for CAT Exam, Types With Examples & Practice Questions | CAT Quantitative Aptitude Questions with Answers PDF |
A quadratic function is a degree two polynomial function in which the variable's maximum exponent is 2.
The roots are the values of 'x' for which the quadratic equation is true, indicating where the graph intersects the x-axis.
There can be 1, 0, or 2 roots in a quadratic equation.
Real roots are real-valued equation solutions. This implies that they may be positive, negative, or zero, but not imaginary or complex. The real roots of the equation x^2-4=0 are x=2 and x=-2, which are both real values that satisfy the equation. Simply said, real roots are the values of a variable that satisfy the equation and may be found on the number line.
Yes absolutely, practices will make you better, helping in increase of speed and accuracy.
Hello,
A blurry signature on your CAT admit card may raise concerns, as it could be difficult for authorities to verify your identity. However, if the rest of the admit card details, such as your photograph and personal information, are clear and accurate, it might not cause an immediate issue. It's advisable to ensure that your signature is clear during future document submissions.
But if your signature is still recognizable, even if it's slightly blurry, it should generally not cause a major issue. As long as the exam authorities can identify your signature, they may accept it. However, it's always best to ensure that all details on your admit card are clear to avoid any potential problems during the exam.
To know more about CAT admit card, visit: https://bschool.careers360.com/articles/cat-admit-card
Hope it helps !
If you have a leg fracture and are scheduled to appear for the CAT entrance exam, it’s best to contact the CAT exam conducting authorities directly rather than the local exam center alone. CAT is managed centrally by the Indian Institutes of Management (IIMs), and they have established protocols for handling candidates with medical needs. Informing the CAT exam cell (via their official contact channels) will ensure that your request is processed appropriately and documented centrally.
You should explain your medical situation and, if needed, request specific arrangements, such as additional assistance to navigate the exam center or seating adjustments. While reaching out to the CAT exam cell, you may also inquire if additional documentation, such as a medical certificate, is required to facilitate the arrangements. Additionally, contacting the allotted test center as a secondary step could be beneficial, as the local administrators may also help with on-ground assistance.
For official contact information, refer to the CAT website’s helpdesk or contact page, which will have the latest guidelines for handling such requests. Taking these steps should ensure a smoother exam experience despite your injury.
https://bschool.careers360.com/articles/cat-eligibility-criteria
Hello aspirant,
If you signature is blur and readable or visible then it will not cause any problem but if it is too much blur or not visible then it can cause the problem. I suggest you to correct you signature at the time when correction window opens.
Thank you
Hope it helps you
Yes, you can certainly attempt the CAT exam with a fractured leg, but there are a few practical considerations to help make the experience smoother. Since CAT is a computer-based test (CBT) and requires candidates to be seated for a few hours, it's essential to ensure you’re comfortable during this time. To manage discomfort, consider arranging seating adjustments or leg support if needed. You may also need assistance getting to the exam center and moving around, as most exam centers may not allow additional mobility devices unless pre-arranged.
The CAT exam authorities generally don’t have special accommodations specifically for fractured limbs, but they do provide support for candidates with disabilities. You could reach out to the exam organizers or your designated exam center to discuss any specific needs, such as seating arrangements. Also, be mindful of pain management strategies; consult your doctor for guidance on managing pain during the exam and consider adjusting your study posture to prevent strain.
Ultimately, with careful planning and by reaching out for any necessary accommodations, it is entirely possible to successfully attempt CAT with a fractured leg.
To access your free CAT mock tests on the Career 360 app first of all enroll yourself for free mock test then , log in to your account and navigate to the "CAT Preparation" section within the app. You should see a dedicated area for mock tests where you can access and take the ones you've enrolled for.
Here are a few steps to follow:
1.Open the Career 360 app: Launch the app on your phone or device.
2.Login with your credentials: Use your registered email and password to log in to your account.
3.Access the CAT section: Once logged in, look for a section labeled "CAT Preparation" or similar.
4.Find your mock tests: Within the CAT section, you should see an option for "Mock Tests" or "Test Series." Click on it to view your available mock tests.
If you are still having problem in accessing free cat mock test contact support from career 360 app your problem or issue will be resolved in 24 hours and you will be able to give free mock test.apart from this you can check preparation study material on our app.
Thank you
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