Amity University-Noida BBA Admissions 2026
ApplyAmong top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Hello aspirant,
As per your inquiry, the list of best colleges in Madhya Pradesh is given below,
Bosse the board of open schooling take admission of candidates who are preferring flexibility in their learning journey.the national entrance exam like NEET,sat or other exams allows students to give the exam for taking admission in colleges.
Hence you are eligible for NEET go for it crack it for your
Hello,
Yes, you can take the DU JAT even if you are a humanities student without math as your main subject. The DU JAT primarily tests your proficiency in Quantitative Ability, Reasoning and Analytical Ability, General English, and Business and General Awareness. While a background in mathematics may be helpful
Correct Answer: Daughter's son
Solution : Given:
P – Q ⇒ P is the wife of Q
P ÷ Q ⇒ P is the husband of Q
P × Q ⇒ P is the son of Q
P + Q ⇒ P is the daughter of Q
As per the
Correct Answer: Statement 1 is false, and statement 2 is true.
Solution : The correct answer is (b) Statement 1 is false, and statement 2 is true.
Statement 1 is false. Global Depository Receipts (GDRs) allow foreign companies to raise funds in international markets, not in their home country's markets.
Correct Answer: INR 3,360
Solution : Selling price = INR 1,440
Loss = 40% of cost price
Cost price = selling price + loss
⇒ Cost price = 1440 + 40% of cost price
⇒ 60% of cost price = 1440
⇒ Cost price = $\frac{1440}{0.6}$ = INR 2400
Profit
Correct Answer: $\frac{k^{32}-\frac{1}{k^{32}}}{k+\frac{1}{k}}$
Solution : Consider, $\left(k-\frac{1}{k}\right)\left(k^2+\frac{1}{k^2}\right)\left(k^4+\frac{1}{k^4}\right)\left(k^8+\frac{1}{k^8}\right)\left(k^{16}+\frac{1}{k^{16}}\right)$
Multiplying and dividing by $(k+\frac{1}{k})$
⇒ $\left(k-\frac{1}{k}\right)\left(k^2+\frac{1}{k^2}\right)\left(k^4+\frac{1}{k^4}\right)\left(k^8+\frac{1}{k^8}\right)\left(k^{16}+\frac{1}{k^{16}}\right)=\frac{(k-\frac{1}{k})(k+\frac{1}{k})(k^2+\frac{1}{k^2})(k^4+\frac{1}{k^4})(k^8+\frac{1}{k^8})(k^{16}+\frac{1}{k^{16}})}{k+\frac{1}{k}}$
Now using, $(a+b)(a-b)=a^2 - b^2$
⇒ $\left(k-\frac{1}{k}\right)\left(k^2+\frac{1}{k^2}\right)\left(k^4+\frac{1}{k^4}\right)\left(k^8+\frac{1}{k^8}\right)\left(k^{16}+\frac{1}{k^{16}}\right)=\frac{(k^2-\frac{1}{k^2})(k^2+\frac{1}{k^2})(k^4+\frac{1}{k^4})(k^8+\frac{1}{k^8})(k^{16}+\frac{1}{k^{16}})}{k+\frac{1}{k}}$
$=\frac{(k^4-\frac{1}{k^4})(k^4+\frac{1}{k^4})(k^8+\frac{1}{k^8})(k^{16}+\frac{1}{k^{16}})}{k+\frac{1}{k}}$
$=\frac{(k^8-\frac{1}{k^8})(k^8+\frac{1}{k^8})(k^{16} + \frac{1}{k^{16}})}{k+\frac{1}{k}}$
$=\frac{(k^{16} - \frac{1}{k^{16}})(k^{16} + \frac{1}{k^{16}})}{k+\frac{1}{k}}$
$=\frac{k^{32} - \frac{1}{k^{32}}}{k+\frac{1}{k}}$
Hence, the correct answer is $\frac{k^{32} - \frac{1}{k^{32}}}{k+\frac{1}{k}}$.
Correct Answer: Kathakali
Solution : The correct option is Kathakali.
Mrinalini Vikram Sarabhai was a renowned Indian classical dancer, choreographer, and cultural icon. She made significant contributions to the field of dance and was a pioneer in promoting Indian classical dance forms. She received her training in the classical
Hello Aspirant,
The cut offs depends upon certain factors such as number of candidates appearing in the examination, previous year cutoffs and difficulty level of the paper.
You can participate in the JAC counseling and fill the choices like DTU , NSUT and Guru Gobind University but the problem is
hlwo aspirant
hope you are doing well
You need to score at least 65% in your BTech/ BE program.
Your age should be below 35 years of age.
You must take the test by the ISRO Centralized Recruitment Board.
The test includes a written test and an interview to join
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