All About BBA - What, Why, Where, When & How?

Bosse the board of open schooling take admission of candidates who are preferring flexibility in their learning journey.the national entrance exam like NEET,sat or other exams allows students to give the exam for taking admission in colleges.

Hence you are eligible for NEET go for it crack it for your

Hello,

Yes, you can take the DU JAT even if you are a humanities student without math as your main subject. The DU JAT primarily tests your proficiency in Quantitative Ability, Reasoning and Analytical Ability, General English, and Business and General Awareness. While a background in mathematics may be helpful

Correct Answer: Daughter's son

Solution : Given:
P – Q ⇒ P is the wife of Q
P ÷ Q ⇒ P is the husband of Q
P × Q ⇒ P is the son of Q
P + Q ⇒ P is the daughter of Q

As per the

Correct Answer: Statement 1 is false, and statement 2 is true.
 

Solution : The correct answer is (b) Statement 1 is false, and statement 2 is true.

Statement 1 is false. Global Depository Receipts (GDRs) allow foreign companies to raise funds in international markets, not in their home country's markets.

Correct Answer: INR 3,360

Solution : Selling price = INR 1,440
Loss = 40% of cost price
Cost price = selling price + loss
⇒ Cost price = 1440 + 40% of cost price
⇒ 60% of cost price = 1440
⇒ Cost price = $\frac{1440}{0.6}$ = INR 2400
Profit

Correct Answer: $\frac{k^{32}-\frac{1}{k^{32}}}{k+\frac{1}{k}}$

Solution : Consider, $\left(k-\frac{1}{k}\right)\left(k^2+\frac{1}{k^2}\right)\left(k^4+\frac{1}{k^4}\right)\left(k^8+\frac{1}{k^8}\right)\left(k^{16}+\frac{1}{k^{16}}\right)$
Multiplying and dividing by $(k+\frac{1}{k})$
⇒ $\left(k-\frac{1}{k}\right)\left(k^2+\frac{1}{k^2}\right)\left(k^4+\frac{1}{k^4}\right)\left(k^8+\frac{1}{k^8}\right)\left(k^{16}+\frac{1}{k^{16}}\right)=\frac{(k-\frac{1}{k})(k+\frac{1}{k})(k^2+\frac{1}{k^2})(k^4+\frac{1}{k^4})(k^8+\frac{1}{k^8})(k^{16}+\frac{1}{k^{16}})}{k+\frac{1}{k}}$
Now using, $(a+b)(a-b)=a^2 - b^2$
⇒ $\left(k-\frac{1}{k}\right)\left(k^2+\frac{1}{k^2}\right)\left(k^4+\frac{1}{k^4}\right)\left(k^8+\frac{1}{k^8}\right)\left(k^{16}+\frac{1}{k^{16}}\right)=\frac{(k^2-\frac{1}{k^2})(k^2+\frac{1}{k^2})(k^4+\frac{1}{k^4})(k^8+\frac{1}{k^8})(k^{16}+\frac{1}{k^{16}})}{k+\frac{1}{k}}$
$=\frac{(k^4-\frac{1}{k^4})(k^4+\frac{1}{k^4})(k^8+\frac{1}{k^8})(k^{16}+\frac{1}{k^{16}})}{k+\frac{1}{k}}$
$=\frac{(k^8-\frac{1}{k^8})(k^8+\frac{1}{k^8})(k^{16} + \frac{1}{k^{16}})}{k+\frac{1}{k}}$
$=\frac{(k^{16} - \frac{1}{k^{16}})(k^{16} + \frac{1}{k^{16}})}{k+\frac{1}{k}}$
$=\frac{k^{32} - \frac{1}{k^{32}}}{k+\frac{1}{k}}$
Hence, the correct answer is $\frac{k^{32} - \frac{1}{k^{32}}}{k+\frac{1}{k}}$.

Correct Answer: Kathakali

Solution : The correct option is Kathakali.

Mrinalini Vikram Sarabhai was a renowned Indian classical dancer, choreographer, and cultural icon. She made significant contributions to the field of dance and was a pioneer in promoting Indian classical dance forms. She received her training in the classical

hlwo aspirant

hope you are doing well

You need to score at least 65% in your BTech/ BE program.

Your age should be below 35 years of age.

You must take the test by the ISRO Centralized Recruitment Board.

The test includes a written test and an interview to join

Hello Aspirant,

I hope you are doing well.

• DTU Delhi - Delhi Technological University
• JMI New Delhi - Jamia Millia Islamia
• Jamia Hamdard, New Delhi
• NSUT Delhi - Netaji Subhas University of Technology
• GGSIPU Delhi - Guru Gobind Singh Indraprastha University
• MAIT Delhi - Maharaja Agrasen Institute of Technolog

For

Hello Aspirant,Hope you are doing well

Yes,Delhi University has scrapped the DU Joint Admission Test along with other entrance examinations which are conducted by the university for the admissions to the UG programmes. The scores of the CUET exams will be considered for the admissions to the BBA, BBE and