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5 Questions around this concept.
Equal chords of a circle subtend equal angles at the centre. (True/False)
AB and CD are the chord of the circle. Given that ∠ AOB = 60° and AB = CD, then ∠ COD = ?
Equal chords of congruent circles subtend equal angles at the centre. (True/False)
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In the adjoining figure, measure of angle AOB is
Theorem 1 : Equal chords of a circle subtend equal angles at the centre.
Let's see how this is possible.
Let suppose you are given two equal chords AB and CD of a circle with centre O. Consider the figure given below.
And we need to prove if ∠ AOB = ∠ COD.
In triangles AOB and COD, we have
OA = OC (Radii of a circle)
OB = OD (Radii of a circle)
AB = CD (Given)
Therefore, ∆ AOB ≅ ∆ COD (by SSS rule)
This gives ∠ AOB = ∠ COD (Corresponding parts of congruent triangles)
Now if two chords of a circle subtend equal angles at the centre, thrn the chords are equal. This is the converse of above theorem.
Theorem 2 : If the angles subtended by the chords of a circle at the centre are equal, then the chords are equal.
Let a circle with center O in which AB and CD are chords such that ∠ AOB = ∠ COD.
In triangles AOB and COD, we have
OA = OC (Radii of a circle)
OB = OD (Radii of a circle)
∠ AOB = ∠ COD (Given)
Therefore, ∆ AOB ≅ ∆ COD (by SAS rule)
This gives AB = CD (Corresponding parts of congruent triangles)
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