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    CAT Definition of logarithm - Practice Questions & MCQ

    Edited By admin | Updated on Oct 04, 2023 04:20 PM | #CAT

    Quick Facts

    • 4 Questions around this concept.

    Solve by difficulty

    loga p < loga q , this expression is true when 1 < a and 0 < p < q. (True/False)

    Which of the following option is correct

    When 0 < a < 1 and m < n, then, loga m __________ logn?

    Concepts Covered - 1

    Definition of logarithm

    A logarithm is a mathematical operation that determines how many times one number should be multiplied by itself to obtain another number. It's the inverse operation to exponentiation.

    Definition:

    The logarithm of a number x with base b is denoted as log_{b}x and is defined as:

    \mathrm{b^y=x \Longrightarrow y=\log _b x}

    Where:

    - b is the base of the logarithm.

    - x is the number.

    - y is the logarithm of x to the base b .

    Note:\mathrm{ b > 0 , (b\neq 1), and x > 0 .}

    Common Bases:

    1. Natural Logarithm: Base e (where e \approx2.71828) . Denoted as \mathrm{In \: x}.

    2. Common Logarithm: Base 10. Denoted as log x.

    Solved Examples:

    1. If \mathrm{3^{5}=243} , what is \mathrm{log_3}  243 ?

    Solution:  

       Using the definition of logarithm, we have:

       \mathrm{3^{y}=243}

       Given, \mathrm{3^{5}=243}

       So, y = 5  

       Thus, \mathrm{log_3 \: 243 = 5 .}

    2. Given log 25 = 1.3979 , find  log 5.

    Solution:  

       Using properties of logarithms:

        \mathrm{\begin{aligned} & \log 25=\log 5^2 \\ & 2 \log 5=1.3979 \\ & \log 5=\frac{1.3979}{2}=0.699 . \end{aligned}}

    Tips and Tricks:

    1. Understand the Basics: Ensure you're clear on the foundational concept that logarithm is the inverse operation of exponentiation.

    2. Use Properties of Logarithms: Familiarise yourself with various properties like:

    \mathrm{\begin{aligned} -\log _b(m n) & =\log _b m+\log _b n \\ -\log _b\left(\frac{m}{n}\right) & =\log _b m-\log _b n \\ -\log _b\left(m^n\right) & =n \log _b m \end{aligned}}

     

    3. Change of Base Formula: If you're unfamiliar with the base used in a question, remember you can change the base using the formula:

     

           \mathrm{\log _b a=\frac{\log _c a}{\log _c b}}

       Where c can be any positive number different from 1.

    4. Stay Cautious: Remember that the logarithm of a number to a base less than 1 is negative. Also, the base and the number whose logarithm we are taking should always be positive.

    5. Practice with Calculator: While understanding the concepts is crucial, proficiency with a calculator can speed up solving problems, especially when dealing with non-integral logarithm values.

    In summary, understanding the definition and properties of logarithms is fundamental for solving a variety of quantitative problems in management entrance exams. With consistent practice and a clear grasp of the basics, students can confidently tackle logarithmic questions.

     

     

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