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5 Questions around this concept.
Two sides AB and BC, and the median AD of ABC are correspondingly equal to the two sides PQ and QR, and the median PM of PQR. Then,
In the given figure,
ABCD is a square, M is the midpoint of AB and meets AD at P and BC produced at Q. Then,
In the given figure,
ABC is a triangle, right angled at B. If BCDE is a square on side BC and ACFG is a square on AC. Then
Let P be a point equidistant from two intersecting lines L and M at a point A. then,
Theorem 1: The angles opposite to two equal sides of a triangle are equal.
Given: Let a
To prove:
Construction: Draw AD, the bisector of , to meet BC in D.
Proof:
Theorem 2 (Converse of Theorem 2): If two angles of a triangle are equal then the sides opposite to them are also equal..
Given: Let a
To prove:
Construction: Draw AD, the bisector of , to meet BC at D.
Proof:
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