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5 Questions around this concept.
Two sides AB and BC, and the median AD of
In the given figure,
ABCD is a square, M is the midpoint of AB, and PQ
In the given figure,
ABC is a triangle, right angled at B. If BCDE is a square on side BC and ACFG is a square on AC. Then:
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Let P be a point equidistant from two intersecting lines L and M at point A. Then:
Theorem 1: The angles opposite to two equal sides of a triangle are equal.
Given: Let a
To prove:
Construction: Draw AD, the bisector of , to meet BC in D.
Proof:
Theorem 2 (Converse of Theorem 2): If two angles of a triangle are equal then the sides opposite to them are also equal..
Given: Let a
To prove:
Construction: Draw AD, the bisector of , to meet BC at D.
Proof:
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