Great Lakes PGPM & PGDM 2025
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2 Questions around this concept.
ABCD is a trapezium with AB || DC. E and F are points on non-parallel sides AD and BC respectively such that EF is parallel to AB then
Theorem : If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points then the other two sides are divided in the same ratio.
Given: in which and DE intersects AB and AC at D and E respectively.
To prove:
Construction: Join BE and CD. Draw and .
Proof: We have
Now, and being on the same base DE and between the same parallels DE and BC, we have
From (i), (ii) and (iii) we have
Theorem (Converse of Thales Theorem): If a line divides any two sides of a triangle in the same ratio then the line must be parallel to the third side.
Given: and a line intersecting AB at D and AC at E, such that .
To Prove:
Proof:
If possible, let DE not be parallel to BC. Then, there must be another line through D which is parallel to BC.
Then, by Thales' theorem, we have
From (i) and (ii), we get
This is possible only when E and F coincide.
Hence,
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