Hello aspirant,

Colleges that accept the CMAT will each declare the CMAT cut off date of 2024. As more than 1000 B-schools throughout the country accept CMAT scores for admission to their MBA and PGDM programs, applicants should aim for a 100 percentile on the exam, which is between 345 and 360 points.

To know the cutoff of top colleges in Gujrat, you can visit the website by following link:

https://bschool.careers360.com/articles/cmat-cutoff

Thank you

Hope it helps you.

Correct Answer: TGQJ

Solution : Let's check each option –
First option: MRVY; M + 5 = R; R + 4 = V; V + 3 = Y
Second option: GLPS; G + 5 = L; L + 4 = P; P + 3 = S
Third option: NSWZ; N + 5 = S; S + 4 = W; W + 3 = Z
Fourth option: TGQJ; T + 13 = G; G + 10 = Q; Q – 7 = J

The fourth option is different from the other three options because the difference in the position value of the letters is different. Hence, the fourth option is correct.

Correct Answer: Both assertion and reason are true, and the reason is the correct explanation of the assertion.
  

Solution : The correct answer is (a) Both assertion and reason are true, and the reason is the correct explanation of the assertion.

The assertion is true. Dematerialization indeed refers to the process of converting physical securities, such as share certificates and bonds, into an electronic or digital form, which is held in a demat account.

The reason is true and provides the correct explanation of the assertion. Dematerialization helps in reducing the risk of theft and forgery of securities because electronic or digital securities are held in a demat account and do not involve the physical handling and transfer of paper certificates, thereby reducing the risk of theft or forgery associated with physical certificates.

Correct Answer: 279

Solution : Given:
a = 12(390)8; b = 7(134)5; c = 5(?)12

Square the sum of the first and third numbers and then subtract 10 from the resultant, to obtain the middle number –
Here, a = 12(390)8→(12 + 8)² – 10 = (20)² – 10 = 400 – 10 = 390
b = 7(134)5→(7 + 5)² – 10 = (12)² – 10 = 144 – 10 = 134
c = 5(?)12→(5 + 12)² – 10 = (17)² – 10 = 289 – 10 = 279

So, 279 is the required missing term. Hence, the third option is correct.

Correct Answer: 4620

Solution : According to the question,
Area of the frustum =  Volume of the cylinder
⇒ $\frac{1}{3}\pi$ ((7)² + (28)² + 7×28) 45 = $\pi r^{2} h$ where $r$, $h$ are the radius and heights of the cylinder
⇒ $\frac{1}{3}\pi(49 + 754 + 196)$ 45 =  $\pi × 9x^{2} × 5x$
⇒ (49 + 754 + 196) 15 = $9x^{2} × 5x$
⇒ 1029 = $3x^{3}$
⇒ $x^{3}$ = $\frac{1029}{3}$ = 343
⇒ $x$ = $\sqrt{343}$ = 7
Curved surface area = $2\pi r h$
= 2 $\frac{22}{7}$ × 35 × 21
= 2 × 22 × 5 × 21
= 4620
Hence, the correct answer is 4620.

Correct Answer: SITUATION

Solution : Given:
ADMINISTRATION

Now, let's compare all the option words with the word ADMINISTRATION –
First option: STRAIN; All the letters of STRAIN are present in the word ADMINISTRATION.
Second option: TRADITION; All the letters of TRADITION are present in the word ADMINISTRATION.
Third option: SITUATION; All the letters of SITUATION are not present in the word ADMINISTRATION. U is not present in the word ADMINISTRATION.
Fourth option: RATION; All the letters of RATION are present in the word ADMINISTRATION.

So, from the above, only SITUATION cannot be formed using the letters of the word ADMINISTRATION. Hence, the third option is correct.

Correct Answer: Lectures and presentations

Solution : The correct answer is (d) Lectures and presentations.

Lectures and presentations are the training methods best suited for teaching theoretical concepts and principles. In a lecture or presentation format, an instructor can deliver information, explanations, and demonstrations of theoretical concepts and principles. This method allows for a structured and systematic approach to conveying knowledge, providing explanations, and presenting theoretical frameworks. Lectures and presentations are effective for introducing new concepts, providing in-depth explanations, and highlighting key theoretical principles in a concise and organized manner.

Correct Answer: INR 8,000

Solution : Let the amount invested in scheme A be $x$​ and in scheme B be $y$
Rate of A scheme = $\frac{8}{100}$ = 0.08
Rate of B scheme = $\frac{10}{100}$ = 0.10
Total invested amount INR 10,000
⇒ $x + y$ = 10,000
Total  interest = ($x$ × 0.08 × 2) + ($y$ × 0.10 × 2) = 1680
⇒ 0.16$x$ + 0.20 $y$ = 1680 
⇒ 0.16 $x$  + 0.20(10,000 –  $x$​) = 1680
⇒ 0.16 $x$ + 2000 − 0.20 $x$ = 1680
⇒ – 0.04 $x$ = 1680 – 2000 = – 320
⇒ $x$ = $\frac{– 320}{ – 0.04}$ = 8000
Hence, the correct answer is INR 8,000​.